left join only fetches one row - php

This SQL only fetches one row from the table category when I'm using fetchAll(), I know there is atleast two rows with the same info. Any ideas?
Click here to see a more detailed explanation of what I thought the problem was
$query = " SELECT
category.*,
GROUP_CONCAT('category_hierarchy.category_id' SEPARATOR ',') AS subcategories
FROM category
LEFT JOIN category_hierarchy ON category.category_id = category_hierarchy.category_parent_id
WHERE category.type = '1'
ORDER BY category.sort_order ASC";
// Prepare.
$stmt = $dbh->prepare($query);
// Execute.
$stmt->execute();
// Fetch results.
$categories = $stmt->fetchAll();
$countedRows = count($categories);
foreach($categories as $category) {
$parent_arr = '';
if(!empty($category['subcategories'])) {
$parent_arr = array(display_children($category['subcategories']));
}
$arr[] = array(
'category_id' => $category['category_id'],
'title' => $category['title'],
'slug' => $category['slug'],
'url' => $category['url'],
'type' => $category['type'],
'sort_order' => $category['sort_order'],
'categories' => $parent_arr
);
}

You have a aggregate function group_concat and without group by clause it will always return one row, you may need to add a group by at the end.
SELECT
category.*,
GROUP_CONCAT('category_hierarchy.category_id' SEPARATOR ',') AS subcategories
FROM category
LEFT JOIN category_hierarchy ON category.category_id = category_hierarchy.category_parent_id
WHERE category.type = '1'
group by category.category_id
ORDER BY category.sort_order ASC

Related

how to select multiple rows using mysql and php?

I had two tables
ads
adImages
here table ads id and table adImages adsId are same. here i have to select all the rows from the table ads and adImages, and display it in json format.
My codes looks:
$query="SELECT a.*, b.images FROM `ads` AS a INNER JOIN `adImages` AS b ON a.id = b.adsId";
$result=mysql_query($query);
$value = mysql_num_rows($result);
if($value>=1)
{
while($row = mysql_fetch_array($result))
{
$details[] = array(
'id' => $row['id'],
'location' => $row['location'],
'title'=>$row['title'],
'mobile' => $row['mobile'],
'description' => $row['description'],
'category' => $row['category'],
'images' =>'http://greenwma.com/dev/uploads/'.$row['images'],
);
}
echo json_encode($details);
}
And its output json looks like :
[{"id":"10","location":"9.982852,76.300637","title":"Ggg","mobile":"5555555","description":"Google","category":"BusMedia","images":"http:\/\/greenwma.com\/dev\/uploads\/MapCapture2016062319:07:39.jpg{"id":"10","location":"9.982852,76.300637","title":"Ggg","mobile":"5555555","description":"Google","category"BusMedia","images":"http:\/\/greenwma.com\/dev\/uploads\/MapCapture2016-06-23 17:27:05.jpg"},{"id":"11","location":"9.962439,76.305337","title":"Test","mobile":"898566899","description":"Test","category":"Bus Shelters","images":"http:\/\/greenwma.com\/dev\/uploads\/MapCapture2016-06-23 19:15:16.jpg"},{"id":"11","location":"9.962439,76.305337","title":"Test","mobile":"898566899","description":"Test","category":"Bus Shelters","images":"http:\/\/greenwma.com\/dev\/uploads\/MapCapture2016-06-23 19:08:50.jpg"},{"id":"11","location":"9.962439,76.305337","title":"Test","mobile":"898566899","description":"Test","category":"Bus Shelters","images":"http:\/\/greenwma.com\/dev\/uploads\/MapCapture2016-06-23 19:07:39.jpg"}]
here the problem is id,location,title,mobile,description,category are repeating for each image on same adsId.
And my need is that, I have to get json in the format
[{"id":"10","location":"9.982852,76.300637","title":"Ggg","mobile":"5555555","description":"Google ","category":"Bus Media","images":"http:\/\/greenwma.com\/dev\/uploads\/MapCapture2016-06-23 19:07:39.jpg","http:\/\/greenwma.com\/dev\/uploads\/MapCapture2016-06-23 17:27:05.jpg"},{"id":"11","location":"9.962439,76.305337","title":"Test","mobile":"898566899","description":"Test","category":"Bus Shelters","images":"http:\/\/greenwma.com\/dev\/uploads\/MapCapture2016-06-23 19:15:16.jpg","http:\/\/greenwma.com\/dev\/uploads\/MapCapture2016-06-23 19:08:50.jpg","http:\/\/greenwma.com\/dev\/uploads\/MapCapture2016-06-23 19:07:39.jpg"}]
that is, I have to get all images separated by comma in single json object. for that what all changes should I make in the above code.
You can use CONCAT() & GROUP_CONCAT() with sub queries to do it in one query and lesser loops.
SELECT a.*, GROUP_CONCAT(images) images FROM (
SELECT a.*, CONCAT('http://greenwma.com/dev/uploads/', b.images) images
FROM `ads` AS a
INNER JOIN `adImages` AS b ON a.id = b.adsId
) tbl
GROUP BY id

mysql query to an array

I am new to php. I can't figure out how to query my db to list this mockup. For each array, I want to query the db to list only what is related to the left in ''.
My db consist of 2 tables.
table1 = album
id, name
table2 = picture
id, album, picPath
$q_albums = array(
'People' => array(
ALBUM_PATH.'4.jpg',
ALBUM_PATH.'11.jpg',
ALBUM_PATH.'10.jpg'),
'Nature' => array(
ALBUM_PATH.'2.jpg',
ALBUM_PATH.'3.jpg',
ALBUM_PATH.'5.jpg',
ALBUM_PATH.'6.jpg',
ALBUM_PATH.'7.jpg'),
'Art' => array(
ALBUM_PATH.'1.jpg',
ALBUM_PATH.'8.jpg',
ALBUM_PATH.'9.jpg',
ALBUM_PATH.'2.jpg'),
'Wilderness' => array(
ALBUM_PATH.'3.jpg',
ALBUM_PATH.'2.jpg',
ALBUM_PATH.'5.jpg',
ALBUM_PATH.'7.jpg',
ALBUM_PATH.'6.jpg'),
'Photography' => array(
ALBUM_PATH.'8.jpg',
ALBUM_PATH.'1.jpg',
ALBUM_PATH.'9.jpg',
ALBUM_PATH.'12.jpg'),
'Fashion' => array(
ALBUM_PATH.'11.jpg',
ALBUM_PATH.'4.jpg',
ALBUM_PATH.'10.jpg'),
);
As dev-null-dweller notes, you need to build the array from the query results in a loop. Fortunately, it's pretty easy:
$sql = <<<END
SELECT album.name AS albumName, picture.picPath AS picPath
FROM album JOIN picture ON album.id = picture.album
END;
$res = $mysqli->query( $sql );
$q_albums = array();
while ( $row = $res->fetch_object() ) {
// this line actually build the array, entry by entry:
$q_albums[ $row->albumName ][] = $row->picPath;
}
$res->close();
Edit: As Mr. Radical notes, if you want your results to include empty albums, you should change the JOIN to a LEFT JOIN. If you do that, the query will return a row with a null picPath for any empty albums, so you'll have to deal with those null paths somehow. One way would be to include something like the following code after building the array:
foreach ( $q_albums as $album => &$pics ) {
// remove dummy null entries from empty albums
if ( !isset( $pics[0] ) ) array_shift( $pics );
}
#Ilmari Karonen I would use LEFT JOIN instead of JOIN.
SELECT album.name AS albumName, picture.picPath AS picPath
FROM album LEFT JOIN picture ON album.id = picture.album

How to retrieve all posts with all comments using 2 SQL queries

I am trying to make a page with a list of posts, and underneath each post all the comments belonging to that post. Initially I wanted to use just one query to retrieve all the posts + comments using the SQL's JOIN, but I find it impossible to for example retrieve a post with multiple comments. It only displays the posts with a maximum of 1 comment per post, or it just show a post multiple times depending on the amount of comments.
In this related question, somebody talked about using 2 queries:
How to print posts and comments with only one sql query
But how do I do this?
I've got the query and a while loop for posts, but I obviously don't want to run a query for comments for each post inside that loop.
$getPost = mysql_query('SELECT p.post_id,
p.user_id,
p.username,
p.content
FROM post p
ORDER BY p.post_id DESC');
while($row = mysql_fetch_array($getPost))
{
...
}
Table structure (reply is the table for storing comments):
POST (post_id (primary key), user_id, username, content, timestamp)
REPLY (reply_id (primary key), post_id, username, reply_content, timestamp)
You can do it in a single query, which is OK if the amount of data in your original posts is small:
$getPost = mysql_query('SELECT
p.*,
r.reply_id, r.username r_username, r.reply_content, r.timestamp r_timestamp
FROM post p
left join reply r
ORDER BY p.post_id DESC'
);
$posts = array();
$last_id = 0;
while($row = mysql_fetch_array($getPost))
{
if ($last_id != $row['post_id']) {
$posts[] = array(
'post_id' => $row['post_id'],
'user_id' => $row['user_id'],
'username' => $row['username'],
'content' => $row['content'],
'timestamp' => $row['timestamp'],
'comments' => array()
);
}
$posts[sizeof($posts) - 1]['comments'][] = array(
'reply_id' => $row['reply_id'],
'username' => $row['r_username'],
'reply_content' => $row['reply_content'],
'timestamp' = $row['r_timestamp']
);
}
Otherwise, break it into two queries like so:
$getPost = mysql_query('SELECT
p.*,
FROM post p
ORDER BY p.post_id DESC'
);
$rows = array();
$ids = array();
$index = array();
while($row = mysql_fetch_assoc($getPost)) {
$row['comments'] = array();
$rows[] = $row;
$ids[] = $row['post_id'];
$index[$row['post_id']] = sizeof($rows) - 1;
}
$getComments = mysql_query('select r.* from replies r where r.post_id in ("'
. join('","', $ids)
. '")');
while ($row = mysq_fetch_assoc($getComments)) {
$rows[$index[$row['post_id']]]['comments'][] = $row;
}
... Or something like that. Either option allows you to litter your first query with WHERE clauses and so forth to your heart's content. The advantage of the 2nd approach is that you don't re-transmit your original post data for each comment!
In order to also get those posts without comments, you need to use a LEFT OUTER JOIN. In that case, any row in the first table without any corresponding rows in the second table will be paired with a row consisting of null values.
SELECT * FROM posts
LEFT OUTER JOIN comments ON posts~post_id = comments~post_id;
By the way: there is also a RIGHT OUTER JOIN. When you would use that, you would get all comments, including those where the parent post got lost somehow, but no posts without comments.

Combine mysql query with sub query results into one PHP array

I have a table that contains events, to list these events I loop through the event table, check the event type and look up it's value in it's specific table with it's eventId.
At the moment this uses one query to get the 20 events and then up to 3 queries to get the data on those events. I currently have it coded procedurally but need to change it so that at the end it just returns the data in array form.
Here's a Pseduo code example of what I need to achieve:
while(eventQuery):
if commentQueryResult;
$array .= commentQueryResult;
if forumPostQueryResult;
$array .= forumPostQueryResult;
if uploadItemQueryResult;
$array .= uploadItemQueryResult;
endwhile;
return $array; // Combined returned results as one array
I will then be able to access the data and just foreach loop through it.
I'm just not sure the best way to combine multiple result sets into an array?
OR you could try and combine them into one query ...
$eventResult = mysql_query(
'SELECT userevent.event, userevent.eventId, userevent.friendId
FROM userevent
WHERE userevent.userId = 1 OR userevent.friendId = 1
ORDER BY userevent.id DESC
LIMIT 20'
);
while ($eventRow = mysql_fetch_row($eventResult)){
if($eventRow[0] == 1){
$result = mysql_fetch_array(mysql_query("
SELECT forumRooms.id, forumRooms.title
FROM forumPosts
INNER JOIN forumRooms ON forumPosts.`forumTopic` = forumRooms.`id`
WHERE forumPosts.id = '$eventRow[1]'"));
}
elseif($eventRow[0] == 2){
$result = mysql_fetch_array(mysql_query("
SELECT game.id, game.uriTitle, game.title
FROM usergamecomment
INNER JOIN game ON usergamecomment.`gameId` = game.id
WHERE usergamecomment.id = $eventRow[1]"));
}
elseif($eventRow[0] == 4){
$result = mysql_fetch_array(mysql_query("
SELECT usercomment.comment, UNIX_TIMESTAMP(usercomment.TIME), `user`.id, `user`.username, `user`.activate
FROM usercomment
INNER JOIN `user` ON usercomment.`userId` = `user`.id
WHERE usercomment.id = $eventRow[1]
AND `user`.activate = 1"));
}
elseif($eventRow[0] == 5){
$result = mysql_fetch_array(mysql_query("
SELECT game.id, game.title, game.uriTitle
FROM game
WHERE game.id = $eventRow[1]"));
}
// Combined Results as array
}
I'm in the process of converting all of these to PDO, that's the next step after working out the best way to minimise this.
Challenge accepted. ;)
Since you are actually only interested in the results inside the while loop, you could try this single query. Due to the LEFT JOINS it might not be faster, pretty much depends on your database. The final $result contains all elements with their respective fields.
$result = array();
$q = 'SELECT userevent.event AS userevent_event,
userevent.eventId AS userevent_eventId,
userevent.friendId AS userevent_friendId,
forumRooms.id AS forumRooms_id,
forumRooms.title AS forumRooms_title,
game.id AS game_id,
game.uriTitle AS game_uriTitle,
game.title AS game_title,
usercomment.comment AS usercomment_comment,
UNIX_TIMESTAMP(usercomment.TIME) AS usercomment_time,
user.id AS user_id,
user.username AS user_username,
user.activate AS user_activate,
g2.id AS game2_id,
g2.uriTitle AS game2_uriTitle,
g2.title AS game2_title
FROM userevent
LEFT JOIN forumPosts ON forumPosts.id = userevent.eventId
LEFT JOIN forumRooms ON forumPosts.forumTopic = forumRooms.id
LEFT JOIN usergamecomment ON usergamecomment.id = userevent.eventId
LEFT JOIN game ON usergamecomment.gameId = game.id
LEFT JOIN usercomment ON usercomment.id = userevent.eventId
LEFT JOIN user ON usercomment.userId = user.id
LEFT JOIN game g2 ON userevent.eventId = g2.id
WHERE (userevent.userId = 1 OR userevent.friendId = 1)
AND userevent.eventId >= (SELECT userevent.eventId
WHERE userevent.userId = 1 OR userevent.friendId = 1
ORDER BY userevent.id DESC LIMIT 1,20);';
$r = mysql_query($q);
while ( $o = mysql_fetch_row($r) ) {
switch($o['userevent_event']) {
case 1:
$result[] = array(
'id' => $o['forumsRooms_id'],
'title' => $o['forumsRooms_title'],
);
break;
case 2:
$result[] = array(
'id' => $o['game_id'],
'uriTitle' => $o['game_uriTitle'],
'title' => $o['game_title'],
);
break;
case 4:
$result[] = array(
'comment' => $o['usercomment_comment'],
'time' => $o['usercomment_time'],
'id' => $o['user_id'],
'username' => $o['user_username'],
'activate' => $o['user_activate'],
);
break;
case 5:
$result[] = array(
'id' => $o['game2_id'],
'uriTitle' => $o['game2_uriTitle'],
'title' => $o['game2_title'],
);
break;
}
}
Note: Eventually, the query has to be edited slightly, I just wrote that out of my head w/o testing. Optimization can surely be done if I'd knew more about the db structure.
Also, this is merely a proof of concept that it can indeed be done with a single query. ;)

Lots and lots of joins in a Zend Query, hopefully just a slight tweak

Apologies for all this code, anyhow Im re-working a query into the Zend query way of working, this is what I have so far:
$db = Zend_Registry::get ( "db" );
$stmt = $db->query('
SELECT recipe_pictures.picture_id, recipe_pictures.picture_filename, course.course_name, cuisines.name, recipes.id, recipes.Title, recipes.Method, recipes.author, recipes.SmallDesc, recipes.user_id, recipes.cuisine, recipes.course, recipes.Created_at, recipes.vegetarian, recipes.Acknowledgements, recipes.Time, recipes.Amount, recipes.view_count, recipes.recent_ips, guardian_writers.G_item, guardian_writers.G_type
FROM recipes
LEFT JOIN course ON recipes.course = course.course_id
LEFT JOIN recipe_pictures ON recipes.id = recipe_pictures.recipe_id
LEFT JOIN cuisines ON recipes.cuisine = cuisines.id
LEFT JOIN guardian_writers ON recipes.author = guardian_writers.G_author
WHERE recipes.id = ?', $id);
$stmt->setFetchMode(Zend_Db::FETCH_ASSOC);
$recipes = $stmt->fetchAll();
return $recipes;
That one above works, trying to get the Zend version properly, my effort is below.
$db = Zend_Registry::get ( "db" );
$select = $db->select()
->from(array('r' => 'recipes'))
->join(array('c' => 'course'),
'r.course = c.course_id')
->join(array('rp' => 'recipe_pictures'),
'r.id = rp.recipe_id')
->join(array('cui' => 'cuisines'),
'r.cuisine = cui.id')
->join(array('gw' => 'guardian_writers'),
'r.author = gw.G_author')
->where(' id = ? ', $id);
$recipes = $db->fetchRow($select);
return $recipes;
If anyone can spot an error Id be very grateful, thanks
Use joinLeft instead of join to produce left joins.
To fetch specific columns from a table, rather than all (*) use this:
->from(array('r' => 'recipes'), array('id', 'title', 'method'))
or
->joinLeft(array('rp' => 'recipe_pictures'),
'r.id = rp.recipe_id',
array('picture_id', 'picture_filename')
)
To fetch no columns from a table, pass an empty array as the third parameter.
The join method provides an sql INNER JOIN. If you want to get a LEFT JOIN you should use joinLeft.

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