Access a node value according to the attribute [duplicate] - php

Question

This question already has answers here:
SimpleXML: Selecting Elements Which Have A Certain Attribute Value
(2 answers)
Closed 7 years ago.
I'm having trouble accessing a value from an XML file. Especially I can't extract the FrenchText. All I always get is the value from the GermanText. Does anyone have an idea, how to get to the value of the node containing the french string directly.
Consulting the web, I found this, but it only results in an error
echo $STRUCTURE_ITEM->NAME[#lang="fr"]
Any help would be greatly appreciated.
Here's my code
<?php
$myXMLData = '<?xml version="1.0" encoding="utf-8"?>
<CATALOG>
<CLASSIFICATION>
<STRUCTURE_ITEM>
<KEY>3605</KEY>
<NAME lang="de">GermanText1</NAME>
<NAME lang="fr">FrenchText1</NAME>
<PARENT_ID>worlds</PARENT_ID>
<SORT>0</SORT>
</STRUCTURE_ITEM>
<STRUCTURE_ITEM>
<KEY>3606</KEY>
<NAME lang="de">GermanText2</NAME>
<NAME lang="fr">FrenchText2</NAME>
<PARENT_ID>3605</PARENT_ID>
<SORT>0</SORT>
</STRUCTURE_ITEM>
</CLASSIFICATION>
</CATALOG>';
$xml=simplexml_load_string($myXMLData);
foreach($xml->CLASSIFICATION->children() as $STRUCTURE_ITEM) {
echo $STRUCTURE_ITEM->KEY . ", ";
echo $STRUCTURE_ITEM->NAME . ", ";
echo $STRUCTURE_ITEM->NAME . ", "; // <---- The problem lies here
echo $STRUCTURE_ITEM->PARENT_ID . "<br>";
} ;
?>
EDIT
Thanks for the valuable input. I've tried
$category_name_fr = $xml->xpath('//STRUCTURE_ITEM/NAME[#lang="fr"]');
Now I get the french values, but I get back an array containing all available french text. (FrenchText1, FrenchText2). But I just want the value of the current node.

Answer 1

Let me suggest an approach different from xpath: an inner foreach loop will iterate over all <NAME> and check for the lang attribute:
$lang = "fr";
foreach ($xml->CLASSIFICATION->STRUCTURE_ITEM as $item) {
echo $item->KEY . ", ";
foreach ($item->NAME as $name)
if ($name['lang'] == $lang) echo $name . ", ";
echo $item->PARENT_ID . "<br />";
}
See it in action: https://eval.in/303058
EDIT: If your XML is consistent meaning that de is always first and fr is always second, simply do:
$lang = 1; // 1 = fr, 0 = de
foreach ($xml->CLASSIFICATION->STRUCTURE_ITEM as $item) {
echo $item->KEY . ", ";
echo $item->NAME[$lang] . ", ";
echo $item->PARENT_ID . "<br />";
}
See this in action: https://eval.in/303062

Answer 2

Your xpath formula does something like this:
1. Starts from document root and proceeds in direction called 'descendant-or-self' (shortcut is //)
2. From this context searches in 'children' direction which is default (notice, that direction is not given after /) and looks for element called STRUCTURE_ITEM
3. From updated context (STRUCTURE_ITEM elements), xpath once more seeks for children elements, called NAME
4. Finally all nodes that fits ale checked with additional test (placed in []). Test says - check if there are nodes in 'attributes' direction (shortcut #). Nodes must be named 'fr'.
Because multiple nodes fits, results are concatenated. If you wish to extract NAME elements separately, try to shrink your initial context (don't start from document root [//]).
#edit:
this seems helpful: XPath query return multiple nodes on different levels