Here I have a string, "Hello World! I am trying out regex in PHP!". What I want to do is retrieve string values between a set of characters. In this example, the characters are ** **
$str = "**Hello World!** I am trying out regex in PHP!";
preg_match('#\*\*(.*)\*\*#Us', $str, $match);
echo $match[1];
This will echo out "Hello World!", but I want to echo out several matches:
$str = "**Hello World!** I am trying out **regex in PHP!**";
How would I be able to do so? I tried using preg_match_all() but I don't think I was using it properly, or that it would work at all in this case.
You can use:
$str = "**Hello World!** I am trying out **regex in PHP!**";
preg_match_all('/\*{2}([^*]*)\*{2}/', $str, $m);
print_r($m[1]);
Array
(
[0] => Hello World!
[1] => regex in PHP!
)
Even your regex #\*\*(.*)\*\*#Us should work with this but my suggested regex is little more efficient due to negation based pattern [^*]*
You got 1 match owing to using preg_match.You should use preg_match_all Here is another pattern.It uses word non word match between the delimiters
<?php
$str = "**Hello World!** I am trying out **regex in PHP!**";
$regex='/\*\*([\w\W]*)\*\*/iU';
preg_match_all($regex, $str, $m);
print_r($m[1]);
I suggest you to use a non-greedy form of regex. Because i think you want to match also the contents (text inside **) where the single * resides.
$str = "**Hello World!** I am trying out **regex in PHP!**";
preg_match_all('~\*\*(.*?)\*\*~', $str, $matches);
print_r($matches[1]);
DEMO
Related
i need to explode youtube url from this line:
[embed]https://www.youtube.com/watch?v=L3HQMbQAWRc[/embed]
It is possible? I need to delete [embed] & [/embed].
preg_match is what you need.
<?php
$str = "[embed]https://www.youtube.com/watch?v=L3HQMbQAWRc[/embed]";
preg_match("/\[embed\](.*)\[\/embed\]/", $str, $matches);
echo $matches[1]; //https://www.youtube.com/watch?v=L3HQMbQAWRc
$string = '[embed]https://www.youtube.com/watch?v=L3HQMbQAWRc[/embed]';
$string = str_replace(['[embed]', '[/embed]'], '', $string);
See str_replace
why not use str_replace? :) Quick & Easy
http://php.net/manual/de/function.str-replace.php
Just for good measure, you can also use positive lookbehind's and lookahead's in your regular expressions:
(?<=\[embed\])(.*)(?=\[\/embed\])
You'd use it like this:
$string = "[embed]https://www.youtube.com/watch?v=L3HQMbQAWRc[/embed]";
$pattern = '/(?<=\[embed\])(.*)(?=\[\/embed\])/';
preg_match($pattern, $string, $matches);
echo $match[1];
Here is an explanation of the regex:
(?<=\[embed\]) is a Positive Lookbehind - matches something that follows something else.
(.*) is a Capturing Group - . matches any character (except a newline) with the Quantifier: * which provides matches between zero and unlimited times, as many times as possible. This is what is matched between the groups prior to and after. This are the droids you're looking for.
(?=\[\/embed\]) is a Positive Lookahead - matches things that come before it.
I need a regex that can actually get any number that is inserted after "ab" and "cr". For example, I have a string like this:
rw200-208-ab66
fg200-cr30-201
I need to print ab66 and cr30.
I have tried using strpos:
if (strpos($part,'ab') !== false) {
$a = explode("ab", $part);
echo 'ab'.$a[1];
}
That does not work for the second item.
You could use \K to discard the previously matched chars from printing at the final. The below regex would give you the number which exists next to ab
or cr.
(?:ab|cr)\K\d+
To get the number with alphabets also, use
preg_match_all('~(?:ab|cr)\d+~', $str, $match);
Use this regex:
(?>ab|cr)\d+
See IDEONE demo:
$re = "#(?>ab|cr)\d+#";
$str = "rw200-208-ab66\nfg200-cr30-201";
preg_match_all($re, $str, $matches);
print_r($matches[0]);
Output:
Array
(
[0] => ab66
[1] => cr30
)
so i want to find usernames in a string and put them in an array, i've made the regex and it returns the match, but when there are 2 matches it only puts the first one in the array. Can anyone see what is wrong with my regex?
$reactie = 'hey #sjerd and #jeska';
$pattern = '/#\w*/';
preg_match($pattern, $reactie, $matches);
print_r($matches);
You need to use preg_match_all with correct regex with word boundary:
$reactie = 'hey #sjerd and #jeska';
$pattern = '/#\w+\b/';
preg_match_all($pattern, $reactie, $matches);
print_r($matches[0]);
I have a word Hello How are you :chinu i am :good i want to get the word which contains : like :chinu and :good
My code:
<?php
//$string='Hello How are you :chinu i am :good';
//echo strtok($string, ':');
$string='Hello How are you :chinu i am :good';
preg_match('/:([:^]*)/', $string, $matches);
print_r($matches);
?>
Above code i am getting Array ( [0] => : [1] => ) But not getting the exact text. Please help me.
Thanks
Chinu
To get all matches you need to use preg_match_all(). As far as your regular expression goes your negated class is backwards; matching any character of: :, ^ "zero or more" times and will not match what you expect.
You stated in the comments about the "records" being printed twice, this is because you print the $matches array itself instead of printing the group index which only displays the match results.
preg_match_all('/:\S+/', $string, $matches);
print_r($matches[0]);
:\S+
Try this.See demo.
http://regex101.com/r/tF5fT5/43
$re = "/:\\S+/im";
$str = "Hello How are you :chinu i am :good";
preg_match_all($re, $str, $matches);
So you would need to do something like the following to match the characters up to the space:
preg_match_all('/:[^ ]+/', $string, $matches);
or if you're looking for alpha-only characters you might use the following:
preg_match_all('/:[A-Za-z]+/', $string, $matches);
The array you would look for would be $matches[0] at this point.
print_r($matches)
print_r($matches[0])
You can always reassign the matches sub array with something like this:
$matchesArray = $matches[0]
I am trying to filter out all characters before the first / sign. I have strings like
ABC/123/...
and I am trying to filter out ABC, 123 and ... into separate strings. I have alsmost succeeded with the parsing of the first letters before the / sign except that the / sign is part of the match, which I don´t want to.
<?php
$string = "ABC/123/...";
$pattern = '/.*?\//';
preg_match($pattern, $string, $matches, PREG_OFFSET_CAPTURE);
print_r($matches);
?>
The letters before the first/ can differ both in length and characters, so a string could also look like EEEE/1111/aaaa.
If you are trying to split the string using / as the delimiter, you can use explode.
$array = explode("/", $string);
And if you are looking only for the first element, you can use array_shift.
$array = array_shift(explode("/", $string));