PHP Skip something a certain amout of times in loop - php

Question

I have a ton of for loops for generating a table, with results from my MySQL DB. Some of the more important information are the start and end date. I calculate how many days this absence has besides the start date(For example 02.03.2015 - 04.03.2015, 2 days). I save this result in $difference, however I get this result during a for loop, so I cant simply go to the for loop and say $xyz - difference.
So I thought about skiping the <td>'s in the loop, as many times as the difference.
Here in the picture you see that the <td>'s are off the amount of days the absence lasts.
How can I skip them as many times as the difference, so the tables looks right again?
My code is still a mess so no comments about that:
echo '<table class="table table table-bordered table-striped table-hover">';
echo '<thead>';
for ($l = 0; $l < $days; $l++) {
if ($l == 0) {
echo '<th>', '<b>Day</b>', '</th>';
} else {
$date = "$current-$month-$l";
$date = date('D', strtotime($date));
$date = substr($date, 0, -1);
echo '<th class="center">', $date,'</th>';
}
echo "\n";
}
echo '</thead>';
echo '<tbody>';
for ($l = 0; $l < $days; $l++) {
if ($l == 0) {
echo '<td>', '<b>Onshore</b>', '</td>';
} else {
echo '<th class="center">', $l, '</th>';
}
echo "\n";
}
for ($i = 0; $i < $count_user; $i++) {
echo '<tr>';
$result = mysql_query("select start, end, type_FK, employee_FK FROM absences where employee_FK = {$array_user[$i]['employee_ID']} and MONTH(start) = $month and YEAR(start) = $current");
while ($row = mysql_fetch_assoc($result)) {
$array_absences[] = $row;
}
$count = 0;
if (!empty($array_absences)) {
$count = count($array_absences);
}
for ($j = 0; $j < $days; $j++) {
$true = 0;
if ($j == 0 && $i == $count_on) {
echo '<td>';
echo '<b>Offshore</b>';
echo '</td>';
for($k = 0; $k < $days -1; $k++){
echo '<td>';
echo '</td>';
}
echo '</tr>';
}
if ($j == 0) {
echo '<td>';
echo $array_user[$i]['name'], ' ', $array_user[$i]['surname'];
echo '</td>';
}
for ($k = 0; $k < $count; $k++) {
$array_absences[$k]['start'] = substr($array_absences[$k]['start'], -2);
$array_absences[$k]['end'] = substr($array_absences[$k]['end'], -2);
$array_absences[$k]['start'] = ereg_replace("^0", "", $array_absences[$k]['start']);
$array_absences[$k]['end'] = ereg_replace("^0", "", $array_absences[$k]['end']);
$difference = $array_absences[$k]['end'] - $array_absences[$k]['start'];
if ($j == $array_absences[$k]['start'] && $array_absences[$k]['employee_FK'] == $array_user[$i]['employee_ID']) {
$true = 1;
$result = mysql_query("select approved from absences where DAY(start) = $j and MONTH(start) = $month");
while ($row = mysql_fetch_assoc($result)) {
$approved[] = $row;
$n++;
}
$now = date('Y-m-d');
$absence = strtotime("$current/$month/$j");
$absence = date('Y-m-d',$absence);
for ($q = 0; $q < $difference+1; $q++) {
if ($approved[$n]['approved'] == 1) {
echo '<td class="center green">';
} elseif ($approved[$n]['approved'] == 0 && $now <= $absence) {
echo '<td class="center orange">';
} elseif ($approved[$n]['approved'] == 0 && $now > $absence) {
echo '<td class="center red">';
}
for ($l = 0; $l < $count_types; $l++) {
if ($array_absences[$k]['type_FK'] == $types[$l]['type_ID']) {
echo $types[$l]['short'];
}
}
echo '</td>';
}
}
}
//Days that are not absences
//Skip this the amounts of $difference
echo '<td ';
//If weekend special coloring
$date = "$current-$month-$j+1";
$date = new DateTime($date);
$day = $date->format("w");
if ($day == 6 || $day == 0) {
echo 'class = "weekend"';
}
echo '>';
echo '</td>';
echo "\n";
}
echo '</tr>';
}

Answer 1

I'm afraid I did not really get the sense of your explanations, however, to skip something in a loop, you can use the continue keyword for this.
For example :
for($i = 0; $i++; i<1000){
if($i < 200 && $i > 100)
continue;
// Computations are here....
}