Find and identify which elements from an array exist in a string - php

Question

I have an array let's say it looks like this:
$arr=array('aa','bb','cc');
Now let's say I have a string that looks like any of these:
$str='bb';
$str='A_STRING_bb_WITH_SOME_TEXT';
$str='ASTRINGbbWITHSOMETEXT';
$str='A+STRING+bb+WITH+SOME+TEXT';
$str='A STRING bb WITH SOME TEXT';
I would like a function that gives me:
$r=find_which_one($arr,$str);
$r should be "bb" for all of those. What's the best way to do this?

Answer 1

Something like this:
function find_which_one($arr,$str){
foreach($arr AS $needle){
if (strpos($str, $needle)){
return true; //returns true on the first match
}
}
return false
}

Answer 2

$arr=array('aa','bb','cc');
$str='A_STRING_bb_WITH_SOME_TEXT aa';
function find_which_one(array $arr,$str) {
$r = preg_match(
'/((' . implode(')|(', $arr) .'))/',
$str,
$matches
);
return ($r !== false) ? $matches[0] : $r;
}
$r=find_which_one($arr,$str);
var_dump($r);
Returns false if not found, else the value from $arr that occurred first

Answer 3

This will return the correct key. If not found, it will return false.
function find_which_one($keys,$value) {
foreach($keys as $key) if (strpos($value, $key)) return $key;
return false;
}

Answer 4

Using array_filter it is straight forward:
$arr = array('aa','bb','cc');
$str = 'A+STRING+bb+WITH+SOME+TEXT';
print_r ( array_filter($arr, function($k) use($str) {
return strpos($str, $k) !== FALSE; }) );
Array
(
[1] => bb
)
Or else:
$str = 'ASTRINGbbWITHSOMETEXT';
print_r ( array_filter($arr, function($k) use($str) {
return strpos($str, $k) !== FALSE; }) );
Array
(
[1] => bb
)