Save to array an array content that it's inside array - php

Question

I have this array. I want to extract to a new one array the content of only one of this array ([choices]). How can i do it in php?
Array
(
[0] => Array
(
[key] => field_54df3275b708a
[label] => Idioma
[name] => idioma
[type] => select
[instructions] =>
[required] => 0
[choices] => Array
(
[Catalan] => Catalan
[Castellano] => Castellano
[Ingles] => Ingles
)
[default_value] =>
[allow_null] => 0
[multiple] => 0
[conditional_logic] => Array
(
[status] => 0
[rules] => Array
(
[0] => Array
(
[field] => null
[operator] => ==
[value] =>
)
)
[allorany] => all
)
[order_no] => 0
)
)
I try this code (i think that's its a bad code):
foreach($array as $k=>$v){
if (is_array($v)){
foreach($v as $l=>$w){
if ($w){
foreach($w as $s=>$t){
$idiomas[]=$t.'<br />';
}
}
}
}
}
But it saves [choices] and [conditional_logic] to new array, and i only want [choices]
Thankyou so much

Answer 1

$new_array_choices = $array[0]['choices'];
Took me awhile to create a test code fiddle. I had to manually recreate the array.

Answer 2

Since you take the key in every foreach all the time, you can use it to ensure it's the array you want :
foreach($array as $k=>$v) {
if (is_array($v)) {
foreach($v as $l=>$w) {
if ($w && $l == 'choices') { // $w is the wanted array
foreach($w as $s=>$t) {
$idiomas[]=$t.'<br />';
}
}
}
}
}
I'm not sure what you are testing with if ($w) though

Answer 3

Replace $arr with your actual array and it should work nonetheless.
// your array (replace)
$arr = array(
"required" => 0,
"choices" => array(
"Catalan" => "Catalan",
"Castellano" => "Castellano",
"Ingles" => "Ingles",
),
"default" => NULL,
);
// the empty resulting array
$new_arr = array();
foreach($arr["choices"] as $key)
array_push($new_arr, $arr["choices"][$key]);
// your resulting array
print_r($new_arr);
Your desired array is saved in the array $new_arr.