I'm trying to get userclass to equal home when the user is on either usercp.php or profile.php, but I can't seem to get the following elseif to work:
if ($_SERVER['REQUEST_URI'] === '/usercp.php') {
$userclass = "home";
} elseif ($_SERVER['REQUEST_URI'] === '/profile.php') {
$userclass = "home";
} else {
$userclass = "norm";
}
I recommend you to try: echo $_SERVER['REQUEST_URI']; to see the value of the variable.
Don´t forget that REQUEST_URI returns the path relative to the server root directory. So, if You have your php file inside a directory called "test", the string returned by REQUEST_URI will be "/test/thefile.php"
Try something like this ?
if (strpos($_SERVER['REQUEST_URI'], 'usercp.php')) {
$userclass = "home";
} elseif (strpos($_SERVER['REQUEST_URI'], 'profile.php')) {
$userclass = "home";
}
Or echo your $_SERVER['REQUEST_URI'] and make comparison like Rizier123 comment.
Related
I have two WordPress sites using the multi-site function, the URLs are below:
A: sample.com
B: sample.com/en
I tried to write a code in PHP following these conditions, but when I access the RUL of A:sample.com, a browser(chrome) shows an error.
So would you mind telling me how should I solve this problem?
Thank you in advance.
the conditions for access
The first access is only to [A: sample.com]
Users whose browser language is set to Japanese access to [A:
sample.com]
All users whose browser language setting is not set to Japanese
access [B: sample.com/en]
The errors messages in the browser(chrome)
This page isn’t working
sample.com redirected you too many times.
Try clearing your cookies.
ERR_TOO_MANY_REDIRECTS
The code for adding in functions.php
<?php
$uri = $_SERVER['REQUEST_URI'];
$BASE_LANG = 'en';
if (!preg_match('/^[!-~][a-zA-Z]{2}[!-~]/', $uri)) {
$languages = explode(',', $_SERVER['HTTP_ACCEPT_LANGUAGE']);
$lang = $BASE_LANG;
if (isset($languages)) {
$browser_lamguage = $languages[0];
$base_languages = array('ja', 'en');
foreach ($base_languages as $base_language) {
if (preg_match("/^$base_language/i", $browser_lamguage)) {
$lang = $base_language;
break;
}
}
}
$url = get_site_url()."/$lang/";
if ($lang == 'ja') {
$url = get_site_url();
}
header("Location: $url");
exit();
}
?>
Development environment
CentOS (7 x86_64)
Apache (2.4.6 CentOS)
PHP (7.1.33)
wordpress(5.2.5)
Just make below change in your code:
if ($lang != 'ja') {
header("Location: $url");
exit();
}
Edited:
$uri = $_SERVER['REQUEST_URI'];
$BASE_LANG = 'en';
if (!preg_match('/^[!-~][a-zA-Z]{2}[!-~]/', $uri)) {
$languages = explode(',', $_SERVER['HTTP_ACCEPT_LANGUAGE']);
$lang = $BASE_LANG;
if (isset($languages)) {
$browser_lamguage = $languages[0];
$base_languages = array('ja', 'en');
foreach ($base_languages as $base_language) {
if (preg_match("/^$base_language/i", $browser_lamguage)) {
$lang = $base_language;
break;
}
}
}
$url = get_site_url()."/$lang/";
if ($lang != 'ja') {
header("Location: $url");
exit();
}
}
I have a group of pages, and I want to include one of them dependent on a variable in url, but the page is always appear is dashboard
link1 : index.php?pth=&page=dashboard
link2 : index.php?pth=modules/institution&page=inst_classification
if statement :
if (isset($page) && !empty($page)) {
$page = htmlspecialchars($_GET["page"]);
$pth = htmlspecialchars($_GET["pth"]);
}else{
$page ='dashboard';
$pth = '';
}
include ('../admin/template/'.$template_fldr.'/html/'.$pth.$page.'.php');
thanks!
You access $page before you write to it. You also never check for the existance of your pth value. Try:
if (empty($_GET['page']) || empty($_GET['pth'])) {
$page ='dashboard';
$pth = '';
}else{
$page = htmlspecialchars($_GET["page"]);
$pth = htmlspecialchars($_GET["pth"]);
}
include ('../admin/template/'.$template_fldr.'/html/'.$pth.$page.'.php');
You probably also need a / here in your include, if modules/institution/inst_classification.php is the file you are looking for:
include('../admin/template/'.$template_fldr.'/html/'.$pth.'/'.$page.'.php'); - but that is not clear from your question.
if (isset($_GET["page"]) && isset($_GET["pth"])) {
$page = htmlspecialchars($_GET["page"]);
$pth = htmlspecialchars($_GET["pth"]);
} else {
$page = 'dashboard';
$pth = '';
}
include ('../admin/template/'.$template_fldr.'/html/'.$pth.'/'.$page.'.php');
This is the button
<a href="index.php?p=contact">contact<a>
This is the php script:
<?php
$p = isset($_GET['p']);
if($p == "artist")
{
include 'artist.php';
}
if($p == "contact")
{
include 'contact.php';
}
if($p == "releases")
{
include 'releases.php';
}
if($p == "downloads")
{
include 'downloads.php';
}
else
{
include 'home.php';
}
?>
So my script should include contact.php when I hit the button, but instead of including only contact.php it includes all php files. (this happens also with the other buttons).
Right now your $p variable equals true (this is what isset returns).
Change $p = isset($_GET['p']); to $p = $_GET['p']; and you'll be good
Even better:
$p = isset($_GET['p']) ? $_GET['p'] : false;
in this case you're secured against p being null
EDIT:
There is also another issue with your code - last else statement. It is always true when $p is different than downloads. So either you change every if to else if like this:
if($p == 'artist')
{
include 'artist.php';
}
else if($p == 'contact')
{
include 'contact.php';
}
(...)
else
{
include 'home.php';
}
or change this to switch statement:
switch($p)
{
case 'artist':
include 'artist.php';
break;
(...)
default:
include 'home.php';
}
isset($_GET['p']) returns true or false, so the code comparing $p to some strings will always return true and run the code inside the if block.
Change $p = isset($_GET['p']) simply to $p = $_GET['p']
To make this (more) reusable, you should alter your script a bit. Create a simple whitelist, check it the parameter is allowed, and if yes, include the $_GET['p']'s value directly:
$allowed = false;
if (isset($_GET['p']))
{
switch $_GET['p'] {
case 'contact':
$allowed = true;
break;
case 'artist':
$allowed = true;
break;
// and so on for all your IFs
}
if ($allowed === true) {
include $_GET['p'].'.php'
}
else
{
die('illegal parameter found')
}
}
Is it possible to determine what to show depending on the URL?
I have an index file which is:
<?php include './includes/header.php'; ?>
<?php include './includes/menu.php'; ?>
<?php include './includes/content.php'; ?>
<?php include './includes/sidebar.php'; ?>
<?php include './includes/footer.php'; ?>
Note: I have different "content.php"'s
Is it possible to do something like:
If Url = url {
show only content for the url
}
and then have case system like
case: home.php
show some
etc
I know Wordpress can do it. Is it possible with PHP and MySQL and HTML?
EDIT: Instead of content.php i would want show the desired HTML code gotten from my db
Use this function to see your current page. Then use the "switch" case for proper include file:
## Get Current Page / Section
function cur_page()
{
$cur_page='';
if(isset($_SERVER['PHP_SELF']) && $_SERVER['PHP_SELF']!='')
{
$temp_var1 = explode('/', $_SERVER['PHP_SELF']);
$cur_page = $temp_var1[count($temp_var1)-1];
}
else if(isset($_SERVER['SCRIPT_NAME']) && $_SERVER['SCRIPT_NAME']!='')
{
$temp_var1 = explode('/', $_SERVER['SCRIPT_NAME']);
$cur_page = $temp_var1[count($temp_var1)-1];
}
else if(isset($_SERVER['REQUEST_URI']) && $_SERVER['REQUEST_URI']!='')
{
$temp_var1 = explode('/', $_SERVER['REQUEST_URI']);
$cur_page = $temp_var1[count($temp_var1)-1];
$temp_var2 = explode('?', $cur_page);
$cur_page = $temp_var2[0];
}
else if(isset($_SERVER['SCRIPT_FILENAME']) && $_SERVER['SCRIPT_FILENAME']!='')
{
$temp_var1 = explode('/', $_SERVER['SCRIPT_FILENAME']);
$cur_page = $temp_var1[count($temp_var1)-1];
}
return $cur_page;
}//end func.....
Querying from database.
I don't recommend MySql, and I hope you learn PDO instead, but just
for this example
function get_me_title($page) {
$query = "SELECT * FROM title WHERE title = $page";
$result = mysql_query($query);
foreach($result as $row) {
return $row[$page];
}
}
Now, you can use function .get_me_title('whatever') to query from database, and echo below
if(isset($_GET['page_id'])) {
$page = $_GET['page_id'];
switch($page) {
case "contact";
echo get_me_title('contact');
break;
case "about";
echo get_me_title('about');
break;
case "portofolio";
echo get_me_title('portofolio')
break;
default:
echo 'you are in home page';
}
}else {echo '404 ERROR! The Page you have requested does not exist';}
Instead of including content.php, you can include needed page.
For example, if You build Your urls, where, for example, $_GET['page'] will refer to needed page, then simply You can do this.
$availablePages = array('default' => 'home', 'about');
if (isset($_GET['page']) && in_array($_GET['page'], $availablePages) {
$page = $_GET['page'] . '.php';
} else {
$page = $availablePages['default'] . '.php';
}
include $page;
I think I'm doing something fundamentally wrong. Here is my code
index.php
<?php
if(isset($_POST['a'])){
$action = $_POST['a'];
} else if(isset($_GET['a'])){
$action = $_GET['a'];
} else {
$action = "home";
}
if($action == "home"){
$frontImages = glob('assets/images/frontpage/*');
include_once 'home.php';
}
?>
I var_dump($frontImages) inside of homp.php (which btw is showing just fine) but I'm getting that $frontImages is an undefined variable. Both the index.php file and home.php file is in the root folder and here is a image of the path directory:
So not sure what I'm doing wrong here.
use
<?php
if(isset($_REQUEST['a'])) {
$action = $_GET['a'];
} else {
$action = "home";
}
if($action == "home"){
while($acImg = glob('assets/images/frontpage/*')) {
$frontImages[] = $acImg;
}
include_once 'home.php';
}
?>
Now you have a Array but this works by me