I'm having some trouble implementing pagination in Laravel 5. Though probably not what you would think.
I can get everything to work but can't understand how to get it to pull the correct information on the second page.
Here is what I have:
Routes:
Route::resource('find-a-wp-theme', 'searchController');
Controller:
public function store(){
$themes['themes'] = Fulls::where("tags", "like", "%".$_POST['theme']."%")->orwhere("tags", "like", "%".$_POST['free']."%")->orwhere("title", "like", "%".$_POST['free']."%")->paginate(12);
return view('find-a-wp-theme', $themes);
}
View:
#if($themes)
#foreach($themes as $theme)
{{$theme['title']}}<br />
<img style="width:250px;" src="{{$theme['image']}}"><br />
#endforeach
{!! $themes->render() !!}
#endif
Up till here everything works just fine. My problem is that when I click the paginating button it takes me to mypage?page=2 which actually takes me to the resource index() and I can't understand how to implement this correctly.
Any help would be much appreciated!
Look at append in the docs. http://laravel.com/docs/5.0/pagination
If your trying to pass variables in your URL you need to use appends().
<?php echo $users->appends(['sort' => 'votes'])->render(); ?>
Related
I am working on a laravel project, where I get data from an API then I want to display it on pages. I want the return to be spread out across 4 pages, each page with 10 results each. What I have so far, seems like it should work, but I am missing one piece, so any advice and help would be appreciated. So this is how it is suppose to work with code:
1) The users types in a book title in a search box.
<form method=POST action='/search'>
#csrf
<input type="text" name="search_term"/>
<input type="submit" value="Search"/>
</form>
2) there input is then sent to my controller, which queries the google books api.
class search extends Controller {
public function search(){
$current_page = LengthAwarePaginator::resolveCurrentPage();
echo $current_page;
$term = request('search_term');
$term = str_replace(' ', '_', $term);
$client = new \Google_Client();
$service = new \Google_Service_Books($client);
$params = array('maxResults'=>40);
$results = $service->volumes->listVolumes($term,$params);
$book_collection = collect($results);
$current_book_page = $book_collection->slice(($current_page-1)*10,10)->all();
$books_to_show = new LengthAwarePaginator($current_book_page,count($book_collection),10,$current_page);
return view('library.search')->with(compact('books_to_show'));
}
}
3) the results are then displayed on my blade
#extends('home')
#section('content')
#foreach($books_to_show as $entries)
<div class="row">
<div class="col-sm-auto">
<img class="w-50 img-thumbnail" src={{$entries['volumeInfo']['imageLinks']['smallThumbnail']}}/>
</div>
<div class="col-sm">
{{$entries['volumeInfo']['title']}}<br/>
#if($entries['volumeInfo']['authors']!=null)
by:
#foreach($entries['volumeInfo']['authors'] as $authors)
{{$authors}}
#endforeach
#endif
</div>
</div>
#endforeach
{{$books_to_show->links()}}
#endsection
This all works fine and as expected. I get 10 results on the view, and then I have a bar at the bottom which give shows me 4 different pages to choose from.
When I first type in a search term such as "William Shakespeare" My page url is:
localhost:8000/search
But, when I click on any of the pages my url becomes:
http://localhost:8000/?page=2
I understand that the ?page=* is how the pagination determines which page you are viewing, and that should be sent back to the controller. But, I am missing something on sending it back to the controller I think.
Still kind of fresh to this, so any advice is more then greatly appreciated.
LengthAwarePaginator accepts a 5th parameter in its constructor: an array of options.
the path option
$books_to_show = new LengthAwarePaginator($current_book_page, count($book_collection), 10, $current_page, [
// This will fix the path of the pagination links
'path' => LengthAwarePaginator::resolveCurrentPath()
]);
By the way, on a totally different matter, Laravel makes your life easier by slicing the collection for you, check it out:
$current_book_page = $book_collection->forPage($current_page, 10);
Hope it helps :)
I have a simple controller function that fetch all records from db. but when i am trying to show all these records it show nothing. In fact it shows me hard coded foreach loop like this.
#foreach ($compactData as $value) {{ $value->Name }} #endforeach
this is my contoller function.
public function showallProducts()
{
$productstock = Product::all()->stocks;
$productoldprice = Product::all()->OldPrices;
$productcurrentprice = Product::all()->CurrentPrice;
$compactData=array('productstock', 'productoldprice', 'productcurrentprice');
return view('welcome', compact($compactData));
}
this is my view
<!doctype html>
<html lang="{{ app()->getLocale() }}">
<head>
</head>
<body>
<div class="flex-center position-ref full-height">
<div class="content">
<div class="title m-b-md">
Laravel
</div>
<div class="title m-b-md">
All products
</div>
<table>
<tbody>
#foreach ($compactData as $value)
{{ $value->Name }}
#endforeach
</tbody>
</table>
</div>
</div>
</body>
why it is behaving like this. any solution?? I am using phpstorm version 17. Is their any setting issue to run project because what ever project I ran it gives me the only page which i ran with only html?
My route is.
Route::get('/', function () {
$action = 'showallProducts';
return App::make('ProductController')->$action();
});
Have you checked your $compactData variable? Please dd($compactData) to see what it contains.
Problem 1
You are accessing a relational property as a property of Eloquent collection, like this:
Product::all()->stocks
which is not correct. Because the Collection object doesn't have the property stocks but yes the Product object might have a stocks property. Please read the Laravel documentation about Collection.
Problem 2
$compactData = array('productstock', 'productoldprice', 'productcurrentprice');
This line creating an array of 4 string, plain string not variable. So, your $compactData is containing an array of 4 string. If you want to have a variable with associative array then you need to do the following:
$compactData = compact('productstock', 'productoldprice', 'productcurrentprice');
Problem 3
return view('welcome', compact($compactData));
Here you are trying to pass the $compactDate to the welcome view but unfortunately compact() function doesn't accept variable but the string name of that variable as I have written in Problem 2. So, it should be:
return view('welcome', compact('compactData'));
Problem 4
Finally, in the blade you are accessing each element of the $compactData data variable and print them as string which might be an object.
You most likely have a problem with your web server.
Try to use Laravel Valet as development environnement.
Edit : I found this : Valet for Windows
I think you didn't mention the blade in the name of the view file by which it is saved. So change the name of the file by which it is save to something like:
filename.blade.php
and try again.
Explanation:
#foreach ($compactData as $value) this is the syntax of blade template engine, and to parse and excute it, you have to mention the blade extension in the name.
I built a laravel 5 application and now I am testing how it handles different inputs. Thus I encountered a weird problem. In the header I have a search field. It returns results, paginated by 10.
The problem
If a user inputs a letter, for an example "e" in English, everything works just fine. However, when a user enters a letter, for an example "e" in Bulgarian - the first page of the results is shown correctly and when a user hits page 2 the query in the search from "е" in Bulgarian changes to "%D0%B5" and no more results are shown. Here is an actual link to the website. http://podobri.eu
I guess this has something to do with the encoding but I can't see what I am doing wrong.
Here is the actual code
Route
Route::get('/search', [
'uses' => '\Podobri\Http\Controllers\SearchController#getResults',
'as'=>'search.results',
]);
SearchController
public function getResults(Request $request){
$query = $request->input('query');
$comments = Comment::where(function($query){
return $query;
})->orderBy('created_at', 'desc')->get();
if(!$query || $query==''){
return view('problems.index')->with('comments', $comments);
}
$problems = Problem::where(DB::raw("CONCAT(problem_title, ' ', problem_description)"), 'LIKE', "%$query%")
->orWhere('location', 'LIKE', "%$query%")
->orWhere('category', 'LIKE', "%$query%")
->orderBy('created_at', 'desc')->paginate(10);
Carbon::setLocale('bg');
return view('search.results')
->with('comments', $comments)
->with('problems', $problems)
->with('title', 'Резултати за "'."$query".'" | Подобри')
->with('description', 'Резултати за "'."$query".'" в системата на Подобри');
}
View
#foreach($problems as $problem)
<div>
#include('problems.partials.problemblock')
</div>
#endforeach
<!-- Paginating-->
{!! $problems->appends(Request::except('page'))->render() !!}
Search form
<form action="{{ route('search.results') }}" role="search" class="navbar-form navbar-left head-form-responsive">
<div class="form-group">
<input type="text" required id='searchQuery' title="Търсете за проблеми" value="{{ Request::input('query') }}" name="query" class="form-control"
placeholder="Търсете за проблеми"/>
</div>
<button type="submit" id='searchBtn' class="btn btn-default">Търсете</button>
</form>
It looks to me like your issue is happening because the paginator is appending a trailing slash with some odd redirect (not sure if you guys are using custom htaccess). Example, if you search for e, this is the URL:
http://podobri.eu/search?query=e
However, the URL for the second page is this:
http://podobri.eu/search/?query=e&page=2
Notice the slash in front of ?query. If you remove the slash, it works. So, how can you fix this?
This was actually fixed a few months ago. You can see this commit here: https://github.com/laravel/framework/commit/806fb79f6e06f794349aab5296904bc2ebe53963
So, if you are using L5.1 or 5.2, you can run composer update, and it'll fix itself. However, if you are using 5.0, it seems like it still has this bug so you can use the setPath method and try this instead:
{!! $problems->setPath('')->appends(Request::except('page'))->render() !!}
I had a similar problem and my solution was changed the method of the route.
Route::post('uri', 'Controller#function')
->name ('view.function');
for:
Route::any('uri', 'Controller#function')
->name ('view.function');
It's works for me.
Regards and good luck.
I am brand new to Laravel, and following a super basic tutorial.
However the tutorial did not come with an edit record section, which I am attempting to extend myself.
Route:
Route::controller('admin/products', 'ProductsController');
Controller:
class ProductsController extends BaseController
{
public function getUpdate($id)
{
$product = Product::find($id);
if ($product) {
$product->title = Input::get('title');
$product->save();
return Redirect::to('admin/products/index')->with('message', 'Product Updated');
}
return Redirect::to('admin/products/index')->with('message', 'Invalid Product');
}
..ECT...
I realise the controller is requesting an ID to use, but I cannot figure out how to pass it a product ID when the form is posted/get.
Form:
{{Form::open(array("url"=>"admin/products/update",'method' => 'get', 'files'=>true))}}
<ul>
<li>
{{ Form::label('title', 'Title:') }}
{{ Form::text('title') }}
{{ Form::hidden('id', $product->id) }}
..ECT...
{{ Form::close() }}
my initial idea was to pass the product id within the form URL like:
{{Form::open(array("url"=>"admin/products/update/{{product->id}}", 'files'=>true))}}
But no luck with that either.
The error I get is:
Missing argument 1 for ProductsController::postUpdate()
Interestingly if I type directly into the URL:
http://localhost/laravel/public/admin/products/update/3
It works and the item with id 3 is altered fine.
So can anyone help and inform me how to pass the id with a form?
Thanks very much
The first Problem here ist the following:
{{Form::open(array("url"=>"admin/products/update/{{product->id}}", 'files'=>true))}}
the {{product->id}} is wrong in two ways:
it should be {{$product->id}}
BUT it wouldn't work anyway because the inner {{..}} inside of the {{Form::...}} won't be recognized since it is inside a string and therefore part of the string itself.
You either have to write it this way:
{{Form::open(array("url"=>"admin/products/update/".$product->id, 'files'=>true))}}
or you give your route a name in your routes.php file and do it this way:
{{Form::open(array('route' => array('route.name', $product->id, 'files'=>true)))}}
I prefer the second way.
You also might want to look into Form Model Bingin
I followed a tutorial on Tutsplus about creating an ecommerce website using Laravel. The problem I'm having right now is when trying to route to a subfolder. In the tutorial, the instructor included a feature where you can view products by ID. And this is how he did it:
// StoreController.php
public function getView($id) {
return View::make('store.view')->with('store', Store::find($id));
}
This piece of code seems to be passing an id from the stores table. I think when a product is clicked, that's when the id is passed
// Routes.php
Route::controller('store', 'StoreController');
Also some of the templates:
// store\index.blade.php
<h2>Stores</h2>
<hr>
<div id="stores row">
#foreach($stores as $store)
<div class="stores col-md-3">
<a href="/store/products/view/{{ $store->id }}">
{{ HTML::image($store->image, $store->title, array('class' => 'feature', 'width'=>'240', 'height' => '127')) }}
</a>
<h3>{{ $store->title }}</h3>
<p>{{ $store->description }}</p>
</div>
#endforeach
</div><!-- end product -->
So.. How it goes is when I click on a product, it leads me to domain:8000/store/view/6 where 6 is the id.
This works fine but what I want to know is how do I route through a subfolder? Let's say I want it to be like this: store/view/products/6 considering that I have a folder called products and my view.blade.php is inside that like this: store/products/view.
In my StoreController class, I tried changing this
public function getView($id) {
return View::make('store.view')->with('store', Store::find($id));
}
to this
public function getView($id) {
return View::make('store.product.view')->with('store', Store::find($id));
}
but it does not seem to work giving me nothing but a Controller Method Not Found Error.
First, the view name View::make('store.product.view') has nothing to do with the URL.
You have to change the route:
Route::controller('store/view', 'StoreController');
And then adjust the name of your method in the controller because it should be the same as the segment of the URL after store/view
public function getProducts($id) {
return View::make('store.product.view')->with('store', Store::find($id));
}
I strongly recommend you read the Laravel docs on the topic