PHP MYSQL search always brings back 0 results - php

Question

Hello Im trying to write a search function in php, but I always get 0 results found.
<?php
$mysqli = new mysqli('localhost', 'root', 'testing123', 'test')
if ($mysqli->connect_error) {
die('Error : ('. $mysqli->connect_errno .') '. $mysqli->connect_error);
}
//collect
$output = '';
if(isset($_POST['search'])){
$searchq = $_POST['search'];
$searchq = preg_replace("#[^0-9a-z]#i","",$searchq);
$query = mysqli_query($mysqli, "SELECT * FROM Users WHERE UsernameLIKE '%$searchq%'");
$count = mysqli_num_rows($query);
// if the $result contains at least one row
if ($query->num_rows > 0) {
// output data of each row from $result
while($row = $query->fetch_assoc()) {
}
}
else {
echo '0 results';
}
}
?>
Any ideas how to fix?
EDIT 1. This still does not allow it to be worked out with even this commented out.
if(!empty($_POST['search'])){
$searchq = $_POST['search'];
//$searchq = preg_replace("#[^0-9a-z]#i","",$searchq);
$query = mysqli_query($mysqli, "SELECT * FROM Users WHERE Username LIKE '$searchq%'");
$count = mysqli_num_rows($query);
// if the $result contains at least one row
if ($query->num_rows > 0) {
// output data of each row from $result
while($row = $query->fetch_assoc()) {
}
}
else {
echo '0 results';
}
}

Answer 1

In order to match School, School Name, or School Name 1
Your query needs to read as and removing the starting % and just keeping the trailing %
WHERE SchoolName LIKE '$searchq%'"
Now, the reason why it's not finding School Name and School Name 1 is because it contains spaces and your regex is replacing those spaces by nothing.
$searchq = preg_replace("#[^0-9a-z]#i","",$searchq);
Either comment that line out or modify the regex.
By commenting it out, you can revert back to using:
WHERE SchoolName LIKE '%$searchq%'"