I am trying to trim the end of my URL after certain characters.
I have my URL in a SESSION variable.
if(strpos($_SESSION['LP'],'ordrer'))
{
$Order1 = $_SESSION['LP'];
$Order2 = strpos($Order1, "ordrer");
$Order = substr($Order1,0,$Order2);
//$Order1 = $Order1(explode('ordrer', $Order1);
}
I'm first putting my URL in variable. Then looking if there is "ordrer" in it with strpos and then cut the end of my URL after "ordrer".
Bassicly I have /Dossiers.php?ordrer=Numero or /Dossiers.php?ordrer=Status and I want to have /Dossiers.php?
But I does not do anything to the URL, why is that?
Also tried explode(), same result.
Thanks
I can't see anything wrong with your code - $Order should contain your URL. I've tested the following code where I put your URL into $url. Could it be that $_SESSION['LP'] is empty?
I've also created a second version at the bottom for you, using explode.
$url = "/Dossiers.php?ordrer=Numero";
//Your version
if (strpos($url,'ordrer'))
{
$Order1 = $url;
$Order2 = strpos($Order1, "ordrer");
$Order = substr($Order1,0,$Order2);
echo $Order; // the first part, including ?
}
//If there is no question mark, you'll just get the whole string
$parts = explode("?", $url);
$Order = $parts[0];
echo $Order; //The first part, excluding ?
Edit: Additional thought - is your problem that "ordrer" should be "order" ?
Related
$url = localhost/project/index.php?letter=0&position=0&bypass=1
How to change position=0 to position=1?
The new $url value will be:
$url = localhost/project/index.php?letter=0&position=1&bypass=1
You can use parse-str and parse-url approach with the help of http-build-query,
$url = "localhost/project/index.php?letter=0&position=0&bypass=1";
// fetching query paramters and save it to output variable
parse_str(parse_url($url,PHP_URL_QUERY),$output);
// changing position value
$output["position"] = 1;
// building back query string
$query = http_build_query($output);
// creating final string
echo parse_url($url,PHP_URL_PATH)."?".$query;
Demo
Output:-
localhost/project/index.php?letter=0&position=1&bypass=1
You have to use the str_replace() function to replace a specific text from string.
$url = str_replace('position=0','position=1',$url);
I've looked at every post on SO that remotely pertains to this and I just can't figure this out. This code is taken directly from another SO post and was marked as the correct working answer:
$query = $_GET;
// replace parameter(s)
$query['d'] = 'new_value';
// rebuild url
$query_result = http_build_query($query);
// new link
Link
Again, taken straight from another post. When I try this code, i change the $_GET to the actual URL that i want to alter. When the code gets to the $query['d'] part, it tells me I get an illegal string offset and the error is the index that's specified. So then I parse the URL, and then do parse_str($query, $output) which in turn allows me to do $output['d'] and THEN I can set a new value to that variable. If I echo it out, it's fine.
But then I get to the http_build_query line, and it tells me that it's expecting an array or object and I can't build the new URL. Here is my code:
$link = parse_url('https://www.google.com/search?source=hp&ei=85GhW6CNHoSqsgXnzoD4Ag&q=coding+tutorial&btnK=Google+Search&oq=coding+tutorial', PHP_URL_QUERY);
parse_str($link, $output);
$output['oq'] = 'new value';
$query_result = http_build_query($link);
echo $query_result;
This code yields that the http_build_query function wants an array or object...i guess i'm not giving it that in some way? What do I need to do to get this to work?
If you want to rebuild the full URL after modifying the query parameters, you could do this:
$url = 'https://www.google.com/search?source=hp&ei=85GhW6CNHoSqsgXnzoD4Ag&q=coding+tutorial&btnK=Google+Search&oq=coding+tutorial';
$link = parse_url($url, PHP_URL_QUERY);
parse_str($link, $output);
$output['oq'] = 'new value';
echo substr($url, 0, strpos($url, '?') + 1) . http_build_query($output);
Output:
https://www.google.com/search?source=hp&ei=85GhW6CNHoSqsgXnzoD4Ag&q=coding+tutorial&btnK=Google+Search&oq=new+value
there is an external page, that passes a URL using a param value, in the querystring. to my page.
eg: page.php?URL=http://www.domain2.com?foo=bar
i tried saving the param using
$url = $_GET['url']
the problem is the reffering page does not send it encoded. and therefore it recognizes anything trailing the "&" as the beginning of a new param.
i need a way to parse the url in a way that anything trailing the second "?" is part or the passed url and not the acctual querystring.
Get the full querystring and then take out the 'URL=' part of it
$name = http_build_query($_GET);
$name = substr($name, strlen('URL='));
Antonio's answer is probably best. A less elegant way would also work:
$url = $_GET['url'];
$keys = array_keys($_GET);
$i=1;
foreach($_GET as $value) {
$url .= '&'.$keys[$i].'='.$value;
$i++;
}
echo $url;
Something like this might help:
// The full request
$request_full = $_SERVER["REQUEST_URI"];
// Position of the first "?" inside $request_full
$pos_question_mark = strpos($request_full, '?');
// Position of the query itself
$pos_query = $pos_question_mark + 1;
// Extract the malformed query from $request_full
$request_query = substr($request_full, $pos_query);
// Look for patterns that might corrupt the query
if (preg_match('/([^=]+[=])([^\&]+)([\&]+.+)?/', $request_query, $matches)) {
// If a match is found...
if (isset($_GET[$matches[1]])) {
// ... get rid of the original match...
unset($_GET[$matches[1]]);
// ... and replace it with a URL encoded version.
$_GET[$matches[1]] = urlencode($matches[2]);
}
}
As you have hinted in your question, the encoding of the URL you get is not as you want it: a & will mark a new argument for the current URL, not the one in the url parameter. If the URL were encoded correctly, the & would have been escaped as %26.
But, OK, given that you know for sure that everything following url= is not escaped and should be part of that parameter's value, you could do this:
$url = preg_replace("/^.*?([?&]url=(.*?))?$/i", "$2", $_SERVER["REQUEST_URI"]);
So if for example the current URL is:
http://www.myhost.com/page.php?a=1&URL=http://www.domain2.com?foo=bar&test=12
Then the returned value is:
http://www.domain2.com?foo=bar&test=12
See it running on eval.in.
I have a method of pulling Youtube video data from API links. I use Wordpress and ran into a snag.
In order to pull the thumbnail, views, uploader and video title I need the user to input the 11 character code at the end of watch?v=_______. This is documented with specific instructions for the user, but what if they ignore it and paste the whole url?
// the url 'code' the user should input.
_gXp4hdd2pk
// the wrong way, when the user pastes the whole url.
https://www.youtube.com/watch?v=_gXp4hdd2pk
If the user accidentally pastes the entire URL and not the 11 character code then is there a way I can use PHP to grab either the code or whats at the end of this url (11 characters after 'watch?v='?
Here is my PHP code to pull the data:
// $url is the code at the end of 'watch?v=' that the user inputs
$url = get_post_meta ($post->ID, 'youtube_url', $single = true);
// $code is a variable for placing the $url in a youtube link so I can output it to an API link
$code = 'http://www.youtube.com/watch?v=' . $url;
// $code is called at the end of this oembed code, allowing me to decode json data and pull elements from json to echo in my html
// echoed output returns json file. example: http://www.youtube.com/oembed?url=http://www.youtube.com/watch?v=_gXp4hdd2pk
$json = file_get_contents('http://www.youtube.com/oembed?url='.urlencode($code));
Im looking for something like...
"if user inputs code, use this block of code, else if user inputs whole url use a different block of code, else throw error."
Or... if they use the whole URL can PHP only use a specific section of that url...?
EDIT: Thank you for all the answers! I am new to PHP, so thank you all for your patience. It is difficult for graphic designers to learn PHP, even reading the PHP manual can give us headaches. All of your answers were great and the ones ive tested have worked. Thank you so much :)
Try this,
$code = 'https://www.youtube.com/watch?v=_gXp4hdd2pk';
if (filter_var($code, FILTER_VALIDATE_URL) == TRUE) {
// if `$code` is valid url
$code_arr = explode('?v=', $code);
$query_str = explode('&', $code_arr[1]);
$new_code = $query_str[0];
} else {
// if `$code` is not a valid url like '_gXp4hdd2pk'
$new_code = $code;
}
echo $new_code;
Here's a simple option for you to do, unless you want to use regex like Nisse Engström's Answer.
Using the function parse_url() you could do something like this:
$url = 'https://www.youtube.com/watch?v=_gXp4hdd2pk&list=RD_gXp4hdd2pk#t=184';
$split = parse_url('https://www.youtube.com/watch?v=_gXp4hdd2pk&list=RD_gXp4hdd2pk#t=184');
$params = explode('&', $split['query']);
$video_id = str_replace('v=', '', $params[0]);
now $video_id would return:
_gXp4hdd2pk
from the $url supplied in the above code.
I suggest you read the parse_url() documentation to ensure you understand and grasp it all :-)
Update
for your comment.
You'd use something like this to make sure the parsed value is a valid URL:
// this will check if valid url
if (filter_var($code, FILTER_VALIDATE_URL)) {
// its valid as it returned true
// so run the code
$url = 'https://www.youtube.com/watch?v=_gXp4hdd2pk&list=RD_gXp4hdd2pk#t=184';
$split = parse_url('https://www.youtube.com/watch?v=_gXp4hdd2pk&list=RD_gXp4hdd2pk#t=184');
$params = explode('&', $split['query']);
$video_id = str_replace('v=', '', $params[0]);
} else {
// they must have posted the video code as the if check returned false.
$video_id = $url;
}
Just try as follows ..
$url =" https://www.youtube.com/watch?v=_gXp4hdd2pk";
$url= explode('?v=', $url);
$endofurl = end($url);
echo $endofurl;
Replace $url variable with input .
I instruct my users to copy and paste the whole youtube url.
Then, I do this:
$video_url = 'https://www.youtube.com/watch?v=_gXp4hdd2pk'; // this is from user input
$parsed_url = parse_url($video_url);
parse_str($parsed_url['query'], $query);
$vidID = isset($query['v']) ? $query['v'] : NULL;
$url = "http://gdata.youtube.com/feeds/api/videos/". $vidID; // this is used for the Api
$m = array();
if (preg_match ('#^(https?://www.youtube.com/watch\\?v=)?(.+)$#', $url, $m)) {
$code = $m[2];
} else {
/* No match */
}
The code uses a Regular Expression to match the user input (the subject) against a pattern. The pattern is enclosed in a pair of delimiters (#) of your choice. The rest of the pattern works like this:
^ matches the beginning of the string.
(...) creates a subpattern.
? matches 0 or 1 of the preceeding character or subpattern.
https? matches "http" or "https".
\? matches "?".
(.+) matches 1 or more arbitrary charactes. The . matches any character (except newline). + matches 1 or more of the preceeding character or subpattern.
$ matches the end of the string.
In other words, optionally match an http or https base URL, followed by the video code.
The matches are then written to $m. $m[0] contains the entire string, $m[1] contains the first subpattern (base URL) and $m[2] contains the second subpattern (code).
I am trying to set up a small script that can play youtube videos but thats kinda besides the point.
I have $ytlink which equals www.youtube.com/watch?v=3WAOxKOmR90
But I want to make it become www.youtube.com/embed/3WAOxKOmR90
Currently I have tried
$result = str_replace('https://youtube.com/watch?v=', "https://youtube.com/watch?v=", $ytlink);
But this returns it as standard
I have also tried
preg_replace('/https://youtube.com/watch?v=/, '/https://youtube.com/embed/', $ytlink);
but both of these dont work.
Instead of using ugly regexes, I recommend using parse_url() with parse_str(). This allows you to be flexible in the event that you want to change something or if Youtube decides to change their URL slightly.
$url = 'https://www.youtube.com/watch?v=3WAOxKOmR90';
// Parse the URL into parts
$parsed_url = parse_url($url);
// Get the whole query string
$query = $parsed_url['query'];
// Parse the query string into parts
parse_str($query, $params);
// Get the parameter you want
$v = $params['v'];
// Now re-build the URL how you want
echo $parsed_url['scheme'].'://'.$parsed_url['host'].'/embed/'.$v;
// Outputs: https://www.youtube.com/embed/3WAOxKOmR90
This works:
$ytlink = 'www.youtube.com/watch?v=3WAOxKOmR90';
$result = str_replace('watch?v=', 'embed/', $ytlink);
echo $result;
$url = 'www.youtube.com/watch?v=3WAOxKOmR90';
echo preg_replace('/.*?v=(\w+)/i', 'www.youtube.com/embed/$1', $url);