Ajax submit not working - php

I'll make it easy, I want to submit data without using a form, etc, etc, etc...
I have this code:
HTML
<span class="categ-edit">Edit</span>
<span class="categ-add">Add</span>
<span class="categ-delete">Delete</span>
JQUERY
$('.categ-edit').click(function() {
$.ajax({
url: 'categoryactions.php',
type: 'POST',
data: {action: 'edit'},
});
window.location.href = "categoryactions.php";
});
$('.categ-add').click(function() {
$.ajax({
url: 'categoryactions.php',
type: 'POST',
data: {action: 'add'},
});
window.location.href = "categoryactions.php";
});
$('.categ-delete').click(function() {
$.ajax({
url: 'categoryactions.php',
type: 'POST',
data: {action: 'delete'},
});
window.location.href = "categoryactions.php";
});
And in categoryactions.php I have this:
PHP
<?php
$action = $_POST['action'];
echo $action;
?>
But when it redirects me to categoryactions.php I get nothing. I'm not sure if that's the way to submit data with AJAX but at least I tried. If someone knows how to fix this, I'll be grateful!

You click handler is making two separate requests. First, you are sending a request with AJAX, then you are going to the page. When you look at the page, you won't see the result because the result was given to the AJAX request.
The point of AJAX is to avoid changing the page.
Try this:
$('.categ-edit').click(function() {
$.ajax({
url: 'categoryactions.php',
type: 'POST',
data: {action: 'edit'},
success: function(data) {
alert(data);
}
});
});

You are actually calling "categoryactions.php" twice. First as an asynchronous call (ajax) and the second time as a redirect: window.location.href = "categoryactions.php";
In the 2nd call, nothing is being posted so your output is empty. This line does not serve any purpose - you should remove it.
The ajax call happens in the background so you won't see the output from the echo in the browser. if you really want to verify it is working, replace the echo with a file call to write it to a file. Then check the file contents.

Using redirection with Ajax doesn't make sense. You need to use the success method.
$('.categ-delete').click(function() {
$.ajax({
url: 'categoryactions.php',
type: 'POST',
data: {action: 'delete'},
success: function(data){
alert(data);
//or, put response in a div
$('#someDivId').html(data);
}
});
});
The point of Ajax is to retrieve the response from a request to another page without changing the URL in the address bar. It retrieves the response for you in the variable that is the input to your success method, and then you do something with that.

Example AJAX with PHP
I can't exactly answer your question, but I will help you understand ajax requests to http server and how to handle responses accordingly.
Sample jQuery
$('.categ-edit').click(function() {
$.get('/path/to/file.php', function(data) {
console.log(data);
});
});
Sample file.php
<?php
echo json_encode('HELLO');

Related

Post variable not passing

Any idea why this doesn't work? I have tried to see if the button clicked actually works with alerts, had alerts as well as before and after the ajax code and they both worked.
var selectedCheckboxes = "12421";
jQuery(document).ready(function($){
$(".editArticle").on("click",function(){
$.ajax({
url: "test.php",
type: "POST",
data: { selectedCheckboxes: "selectedCheckboxes" },
success: function(response){
//do action
},
error: function(){
// do action
}
});
});
});
the link:
Edit
test.php
<?php
echo $_POST["selectedCheckboxes"];
?>
Try this instead:
Edit
If you want the output of the php in your page you have to do something like this in your javascsript
$(".editArticle").on("click",function(){
$.ajax({
url: "test.php",
type: "POST",
data: { selectedCheckboxes: selectedCheckboxes },
success: function(response){
$("body").html(response);
},
error: function(){
// do action
}
});
});
You may need to change the "body" tag.. or not
depends on what the teste.php returns
Well, if you don't want the output to be placed inside your current page html, maybe a different aproach would be better.
Maybe there are better answers but you could try something like:
<form method="post" action="test.php" onsubmit="javascript:$('#selectedCheckboxes').val(selectedCheckboxes);">
<input type="hidden" value="" name="selectedCheckboxes" id="selectedCheckboxes">
<input type="submit" value="Edit">
</form>
You would have to style the submit input
Does the idea help? No ajax though.
The reason you're not seeing the AJAX reqeust go through is because when the you click on the anchor tag, the browser is performing the default action of navigating to 'test.php', which cancels the AJAX call. Since you are simply GET'ing that page, and not POST'ing to it, there is nothing in $_POST. In order to prevent this default action, either use a span instead of an a tag (recommended), or prevent the default action, doing something like this:
Edit
If I get you right, you want to pass selectedCheckboxes as JSON to the Server. In this case you need to actually pass your selectedCheckboxes variable to the Server.
Like this:
$.ajax({
url: "test.php",
type: "POST",
data: selectedCheckboxes,
success: function(response){
//do action
},
error: function(){
// do action
}
});
The problem with your code is that you passed a new JSONObject containing a String that contains "selectedCheckboxes". You did not pass the actual variable.
Put a return false; after ajax call
You try to pass a variable selectedCheckboxes but unfortunately with double ("") quotes you passing a string as selectedCheckboxes
Use below code
var selectedCheckboxes = "12421";
var dataObject = {};
data[selectedCheckboxes] = 1;
jQuery(document).ready(function($){
$(".editArticle").on("click",function(){
$.ajax({
url: "test.php",
type: "POST",
data: dataObject ,
success: function(response){
//do action
},
error: function(){
// do action
}
});
});
});
Hope this helps...

jQuery ajax request same page PHP doesnt execute

I am trying to send a variable in a request to the same page and then check if the variable is set.
$.ajax({
url: "index.php",
type: "POST",
data: {idss:idss},
success: function(data){
console.log("hello");
}
});
if(isset($_POST['idss'])){
echo "Set";
}
However, when this runs I only see "hello" in the console and yet I dont see the output of 'echo' on the page.
Am I doing something wrong?
$.ajax({
url: "index.php",
type: "POST",
data: {idss:idss},
success: function(data){
console.log("hello");
$('#here').html(data['whatever_you_returned']);
}
});
<div id="here"></div>
The POST data is being sent to the page in your ajax request, not your current page.
index.php would have that POST data set.

AJAX call to return values from PHP not working

I have a AJAX script which sends value to PHP script and to retrieve the value from the PHP script. The part where the script sends the value is working fine. Its the problem with the retrieving values. I am not able to figure out what is wrong.
AJAX code:
$(document).ready(function() {
$("#raaagh").click(function() {
$.ajax({
url: 'ajax.php', //This is the current doc
type: "POST",
data: ({name: 145}),
success: function(data) {
console.log(data);
$.ajax({
url:'ajax.php',
data: data,
dataType:'json',
success:function(data1) {
var y1=data1;
console.log(data1);
}
});
}
});
});
});
PHP code:
<?php
$userAnswer = $_POST['name'];
echo json_encode($userAnswer);
?>
Please check whether "name" is posted before assigning the value to $userAnswer.
Both ajax scripts are sending to "ajax.php". In first ajax request "name" is posted, but in 2nd ajax request "name" is not posted.
To see warnings and errors, enable error reporting in php.
<?php
//To enable error reporting
ini_set('display_errors',true);
error_reporting(E_ALL);
data: {name: 145}
try this hope this will work.
Your nested AJAX call does not have the request type specified. The default is GET but your ajax.php is trying to find a POST.
$(document).ready(function() {
$("#raaagh").click(function() {
$.ajax({
url: 'ajax.php',
type: "POST",
data: ({name: 145}),
success: function(data) {
console.log(data);
$.ajax({
url:'ajax.php',
type: "POST", //<-- added here
data: {name:data}, //<-- also required for POST
dataType:'json',
success:function(data1) {
var y1=data1;
console.log(data1);
}
});
}
});
});
});
Set type:'POST' inside the second ajax call and try to use data1[0]. Also remember that you are sending a json string (that comes from the first ajax) with the second request. Basically you are encoding an encoded value,so when you receive the post value you should json_decode the post value

ajax jquery with codeigniter. url doesnt access controller

I am new to codeigniter and cannot get my ajax to work.
I am trying to make links load content into the main document on click.
I looked for instructions but could not figure it out. All works except the ajax returns alert('ERROR') message. nothing is loadded into <div id='load_here'></div>
Maybe I am missing something in config.php? Do i have to load some library for this to work?
Any ideas would be helpfull
//main document link
<span id='reg_link_rules'>Link</span>
<div id='load_here'></div>
// controller
class Register extends CI_Controller {
public function hello()
{
echo 'hello';
}
}
// jQuery
$(document).ready(function() {
$('#reg_link_rules').click(function(eve){
$.ajax({
type: "GET",
url: "register/hello",
complete: function(data){
$('#load_here').html(data);
},
error: function(){alert('error');}
});
});
});
I think the problem is that the ajax url does not access the controller.
Z:/home/codeigniter/www/register/test this is where i think it takes me
problem solved, the url needed to be http://codeigniter/index.php/register/hello
Try with url: "/register/hello".
Might do the trick.
Usually I do a
<script type="text/javascript">
base_url = '<?=base_url()?>';
</script>
At the beginning of my page and simply
base_url+"register/hello"
instead
That makes my ajax more reliable, even when / is incorrect.
complete: function(data){
$('#load_here').html(data);
},
should be
Just referencing another SO question ... Use success() or complete() in AJAX call
success: function(data){
$('#load_here').html(data);
},
AND
$.ajax({
type: "GET",
Should be
unless you want your form vars to be submitted along in the URL.
$.ajax({
type: "POST",
Hello You should add the base url to the URL Ajax.
$.ajax({
type: "GET",
url: <?php echo base_url();?>"register/hello",
complete: function(data){
$('#load_here').html(data);
},
Remember enable the helper URL in the Controller!
Cheers
you need to pass the bas_url to ajax file
<script type="text/javascript">
$(document).ready(function(e) {
var baseurl = <?php echo base_url();?>
$('#reg_link_rules').click(function(){
$.ajax({
url : baseurl+'index.php/register/hello',
data : '',
type: "POST",
success : function(){
}
})
return false;
})
});
</script>
Sometimes you have do add index.php to the string. Like so:
$.ajax({
type: "GET",
url: <?php echo base_url();?>"index.php/register/hello",
complete: function(data){
$('#load_here').html(data);
},
But it's all about your config file however. It was the mistake in my case.
Hope it helps.
You need to ensure two matter
please put your ajax part as url: ?php echo base_url();?>"register/hello", and type: "GET", and also need to check wheter it is routed the url on config/routes.php.

jQuery Ajax = success return page

Ok so I know long hand ajax but trying to use the jQuery short cut. I have two documents
form.php
submit.php
In my "form" page I am calling the "submit" page to process the insert. I am currently using the jquery ajax:
<script type="text/javascript">
jQuery('form').submit(function() {
string = jQuery("form").serializeArray();
jQuery.ajax({
type: "POST",
url: "submit.php",
data: string,
dataType: "json",
})
return false;
});
</script>
When I view firebug it is processing the ajax fine. I am getting 200 and post parameters are set. What I am trying to do is have the ajax return the submit.php file. I know it has something to do with the "success" function but I don't know how to add this. I tried a few things like:
<script type="text/javascript">
jQuery('form').submit(function() {
string = jQuery("form").serializeArray();
jQuery.ajax({
type: "POST",
url: "submit.php",
data: string,
dataType: "json",
success: function(html){
alert(html);
}
})
return false;
});
</script>
and
<script type="text/javascript">
jQuery('form').submit(function() {
string = jQuery("form").serializeArray();
jQuery.ajax({
type: "POST",
url: "submit.php",
data: string,
dataType: "json",
success: function(html){
$('.result').html(data);
}
})
return false;
});
</script>
but neither of these are working. Again I am simply trying to send the ajax request and then return the contents of the submit.php page. Not only does the submit.php page hold the script to process the php/ajax insert but it also display success statements like "insert was successful" so that is why I need to not only run the script in the page but also return the contents of that page. Thank you for any help.
Chagne the dataType:'json' to dataType:'html' for the callback that you wish to display the contents of submit.php.
You were close in your second attempt, but you made a typo. Try:
success: function (data) {
$('.result').html(data);
}
Also, unless your server is returning JSON, you probably want to change the dataType:
dataType: "html"

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