Select and then Insert Query (PHP with MYSQLI) Not working - php

Hello I've a table named as "register" in which i've some records Lets says (10)
I want to first count that records and then save it into another table named as "not" i.e. Notification(Handler Name)
Here's the code which i'm using but unfortunately its not working..
Here's my config.php
<?php
$con = new mysqli('localhost','root','','admin');
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
?>
and here's abc.php
<?php
include('config.php');
$sql2 = "INSERT INTO not VALUES((SELECT count(*) as count FROM register))";
$result2 = mysqli_query($con, $sql2);
if($result2->num_rows>0)
{
while($rw1=$result2->fetch_array())
{
$value1 = $rw1['count'];
echo $value1;
}
}
?>

not is reserved word. So you should use like this:
$sql2 = "INSERT INTO `not` VALUES((SELECT count(*) as count FROM register))";

Basically i'm working on a project similar to Facebook Notification System
I've a Registration Form through which users are registered and all entries will be saved in a database named as "admin" with table name as "register"
Clear or not ?
Suppose I've 10 Users and I want to first show No. 10 as Notification Number at top bar as a popup tooltip
Just follow this example which i'm using
[http://demos.9lessons.info/notifications_css/index.php][1]
After that I want to Perform this thing that when someone opens the notification bubble, that 10 Number Goes out and in backend, i'm thinking that to store that ROW COUNT into another table and after Jquery click function, that table value goes to ZERO and when any new user is registered, then it increments the counter with match the previous value..
Sounds or not ??

change your table name as suggested by #phpPhil
plus try this query
$sql2="INSERT INTO not SELECT count(*) as count FROM register";
UPDATED
made your connection in this file.
$con = new mysqli('localhost','root','','admin');
$sql = "SELECT count(*) as count FROM register";
this query will return only one or zero rows so dont use while
$result = $con->quer($sql) or die($con->error);
if($result->num_rows>0)
{
$rw=$result->fetch_array(MYSQLI_ASSOC);
$value = $rw['count'];
echo $value; here to check what you get here
//preiously you had check if value is not empty. which is wrong because it will never empty it will either 0 or any other value
if($value!=0)
{
$jh ="update noti set noti='$value'";
$res=$con->query($jh) or die($con->error);
}
else
{
$ab ="insert into noti(noti) values('$value')";
$res1=$con->query($ab) or die($con->error);
}
}

Related

Getting value from MySQL, and putting them into other table (multiple values at once)

First and formost, yes i know PHP5.6 is deprecated version, but i want to stick with it and fully learn PHP for myself, before updating to MySQLi.
I'm trying to make a text based game running MySQL and PHP, and currently trying to create a system that:
1.Gets information from user table, username and total actions done (+)
2.At the certain timestamps save all usernames and actions into separete table (-)
3.Resets actions column to 0 for ALL players. (+/- planning to use a mysql trigger and/or cron-job)
My questions:
2) How would you suggest me to insert usernames into seperate table? (only idea i come up is to explode array somehow get variables and sumbit to mysql, question is how to do so? )
3) regarding this number 3, would you suggest something else then triggers or cron-jobs?
Code example bellow
<?php
include './config/connect-db.php';
$result= mysql_query("SELECT * FROM user WHERE actions > 100 ORDER BY
actions DESC LIMIT 5");
while($row = mysql_fetch_array($result)){
if ($row['u_dmisijos'] >= 100) {
echo '<li>'.$row["u_name"].' ('.$row["actions"].')<br>';
} // if actions
} //while loop
?>
EDIT:
MySQL includes a lot of columns, there are only 2 specific I'm focusing on, u_name (username) and actions (actions).
EDIT2:
What i am expecting on second table: ID (AI), username of player with the most action points, username of player with second action points etc. And Datastamp.
expected SQL
ID, nr1, nr2, nr3, nr4, nr5, Datastamp.
Cheers!
I am not sure this will work or not as I have not tested it. But, I hope you might get a general idea.
<?php
$conn = mysql_connect("localhost", "mysql_user", "mysql_password");
if (!$conn) {
echo "Unable to connect to DB: " . mysql_error();
exit;
}
if (!mysql_select_db("mydbname")) {
echo "Unable to select mydbname: " . mysql_error();
exit;
}
$sql = "SELECT * FROM user WHERE actions > 100 ORDER BY actions DESC LIMIT 5";
$result = mysql_query($sql);
if (!$result) {
echo "Could not successfully run query ($sql) from DB: " . mysql_error();
exit;
}
if (mysql_num_rows($result) == 0) {
echo "No rows found, nothing to print so am exiting";
exit;
}
while ($row = mysql_fetch_assoc($result)) {
$q = "INSERT INTO `new_table` (`u_name`, `actions`) VALUES
($row['u_name'],$row['actions'] )";
mysql_query($q);
}
?>
Regarding resetting all actions to 0 you can create a functions like:
function resetActions(){
//update actions to 0
$q = "UPDATE table_name SET actions = 0";
mysql_query($q);
}
Now, whenever you need to reset it you can call this function. Or you can call this function in cron job as you required.

Select individal colums when fetching data from a database

I've just started learning PHP so this is quite a struggle for me, any help is appreciated!
So, I've managed to select my database, table and get data from it. But I need to select more data from the older columns.
Here is some of the code:
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
//execute the SQL query and return records
$result = mysqli_query($conn, "SELECT username FROM interview");
while($rowval = mysqli_fetch_array($result))
{
$username= $rowval['username'];
$username2= $rowval['username'];
$username3= $rowval['username'];
$username4= $rowval['username'];
}
?>
And I am displaying the data in a button, I want $username to display the first column and $username2 to display the second column etc...
I fetch the data using this code:
<?php echo $username; ?>
<?php echo $username2; ?>
<?php echo $username3; ?>
<?php echo $username4; ?>
Thanks!
I would suggest you re-factoring your "while" loop the following way for better scalability:
$usernames=array();
while($rowval = mysqli_fetch_array($result))
{
$usernames[] = $rowval['username'];
}
Then, you'll be able to access usernames like:
echo 'The first user name is: '.$usernames[0];
echo 'The second user name is: '.$usernames[1];
echo 'The third user name is: '.$usernames[2];
My php skills are a bit rusty, so take this with a grain of salt:
At first it is important to get the language right. A database table consists of rows and columns, the columns are the ones you select with the the part after the SELECT statement, if you write SELECT username what you select is the username column.
SELECT username FROM interview;
So if you want to select more columns from your table you have to put them in your SELECT statement. Let's say you want to select the username and the status of the interview, you would need to include the status in your SELECT statement like this:
SELECT username, status from interview;
Then you can access the interview status just like you did it with the username.
$result = mysqli_query($conn, "SELECT username, status from interview;");
while($rowval = mysqli_fetch_array($result))
{
$username= $rowval['username'];
$status = $rowval['status'];
}
Remember that what you get as the $rowVal is just a single row of your table. So if you want to collect all usernames and statuses from your table you have to use a datastructure to collect them.
$queryResult = mysqli_query($conn, "SELECT username, status from interview;");
$result = array();
while($rowval = mysqli_fetch_array($queryResult))
{
$username= $rowval['username'];
$status = $rowval['status'];
// With this action we build an array, that has each row's result as value.
$result[] = array('username' => $username, 'status' => $status);
}
To access the results you can then query the $result array like this:
// The interview status of the first entry in your table
$result[0]['status'];

how to update a single column of db without deleting its previous data?

i am updating a single column with many values using comma between them. they are working fine. but if update same column from other user the value inserted by previous users deleted. i want to keep values of previous user also with the insertion of new user value. and i also dont want to repeat the same value again because values i m using are unique ids..
// update student list
$venue = ($_GET['venue']);
$district = ($_GET['dis']);
if(isset($_POST['submit']))
//print_r ($_POST);
{
#$std_list=implode(',',$_POST['std_list']);
if(empty($std_list))
{
$error = 1;
$get_value = "Please select you event students.";
}
else
{
//$query = mysql_query("INSERT INTO events (std_list)
//VALUES('".$std_list."')") or die(mysql_error());
$query = mysql_query("UPDATE events SET std_list='".$std_list."' WHERE
id='".$district."' ") or die(mysql_error());
//echo "$msg";
echo "Students list submitted successfully";
}
}
if any query you can ask again. values i am inserting are integers only. Same integer cant be used by two different users.
try this?
$query = mysql_query("UPDATE events SET std_list = CONCAT( std_list, '".$std_list."') WHERE
id='".$district."' ") or die(mysql_error());

How to grab an int from my MySQL server via PHP?

I am a novice when it comes to PHP but I don't understand if my syntax is wrong in this statement, or how would I grab an int from my MySQL server.
I know that my server credentials are working fine. How would I fix this statement to give me a returned integer of the number of reviews in the userinfo table?
$numberofpreviousreviews = mysql_query("SELECT `number_of_reviews` FROM `userinfo`") or die(mysql_error()); //Check to see how many reviews user has previously created
$amountofreviews = $numberofpreviousreviews + 1;
$query2 = mysql_query("ALTER TABLE userinfo ADD `amountofreviews` VARCHAR(10000)") or die(mysql_error()); //Make another column in database for the new review
You need to fetch your results after you run your query. There are several ways to do this but using mysql_fetch_assoc() will work for you.
$numberofpreviousreviews = mysql_query("SELECT `number_of_reviews` FROM `userinfo`") or die(mysql_error()); //Check to see how many reviews user has previously created
$row = mysql_fetch_assoc($numberofpreviousreviews);
$amountofreviews = $row['number_of_reviews'] + 1;
FYI, you shouldn't be using mysql_* functions anymore. They are deprecated and going away. You should use mysqli or PDO.
Assume you have a table userinfo which has the following structure and data :
Scenario #1 :
If you want to retrieve the all number_of_reviews, then do like this,
$query = "SELECT `number_of_reviews` FROM `userinfo`";
$result = mysqli_query($db,$query);
while ($row = mysqli_fetch_assoc($result)) {
echo "Number of reviews : " . $row['number_of_reviews'] . "<br/>";
}
It will give you,
Number of reviews : 20
Number of reviews : 40
Since, the result has many rows, it will display like above.
Scenario #2:
If you want to retrieve only the specific number_of_reviews for some user id (which is unique). I take id as 1 as a example here. Then do like,
$query2 = "SELECT `number_of_reviews` FROM `userinfo` WHERE `id` = 1";
$result2 = mysqli_query($db,$query2);
while ($row2 = mysqli_fetch_assoc($result2)) {
echo $row2['number_of_reviews'] . "<br/>";
}
This will print,
20.
Because, number_of_reviews is 20 for id 1.

mysql compare table values

I am creating a poll in php. I have a table with an id column.
When a user submits a choice, I want the php to first query the database and check whether the table "id" has the id of the current user.
I am pretty new at mysql, can someone help me with the query?
Try this:
$q = "SELECT id FROM table WHERE id = '".mysql_real_escape_string($_POST['user_id'])."'";
$r = mysql_query($q);
if(mysql_num_rows($r) > 0) {
echo "User ID was found in table";
} else {
echo "User ID was not found in table";
}
$qryResult = mysql_query("SELECT userid FROM idtable WHERE userid='$theIdOfUser'");
if (mysql_num_rows($qryResult) == 0)
{
// add a new vote
}
else
{
// notify the user that double voting is prohibited
}
Try not to use names like "id" to avoid conflicts with reserved words and related complications and need to use quotes

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