I have a table:
name count
Name 1 1
Name 2 1
Name 3 1
Name 4 1
Name 5 2
Name 6 2
If I select Name 2 (count = 1), how do I select the next and previous item (Name 3, Name 1)? After all values are the same.
How to solve my problem?
If you want a single query then I think this might be the query you are loooking for.
select * from table where coun=(select coun from table where name='name1')
and name!='name1'
I just rename count column to coun as count is an agg. function in mysql.
hope it works for you..
Related
Here is the table structure. I want to fetch all the id_product which have value 2 and 601(here id_product = 5). If i use OR all the records will be populated which is not necessary.
id_product attribute_id Value
5 2 2
6 2 2
8 2 601
6 2 601
5 3 601
8 3 32
6 3 41
Any help would be appreciated. I don't want to use sub query :-p
You can use a group by query:
select
id_product
from
tablename
where
attribute_id=2 and values in (2,601)
group by
id_product
having
count(*)=2
this will select all products that have (attribute_id=2 and value=2) or (attribute_id=2 and value=601) in two different rows, and then it will count the number of rows returned and select only products that have two rows (one with value 2 and one with value 601).
Another option (it's not too clear from your question) is to use this where clause instead of the one on the query above:
where
(attribute_id=2 and value=2) or
(attribute_id=3 and value=601)
You can use this query in your case:
SELECT * FROM nameTable WHERE Values IN (2,601) and attribute_id = 2
assume I have a table that contain a column named post_id and it has the result like
1
1
1
2
2
3
1
1
I want to loop through all the records and count how many times they exist. What I could thought of is
by while loop
if(result[] = 1){$1++}, but the problem is the value of record is not fixed, it can be 9999..
I'd tried
while ($something= $item->fetch_array()) {
while($test[] = $something['post_id'] > 0){
//logic here
}
}
select post_id, count(*)
from table
group by post_id
This is something you can do in SQL. I believe it would be the following:
SELECT post_id, COUNT(*) FROM tablename GROUP BY post_id;
This will return, for each post_id in the table, that post_id and the count of rows with that post_id.
Have you try this.
Assume:
Table one
**Table one**
Column1
1
1
1
2
2
3
1
1
You can use this query to count it.
SELECT one.column1, COUNT(two.column1) FROM one as one, one as two;
I have table like this one
id name
1 John
2 Mike
3 Zed
4 Teacher
5 Aaron
...........
How to make mysql query to get rows in ASC order by name but put "Teacher" at the top or something that starts with "Teacher"?
select * from your_table
order by case when name = 'Teacher' then 1 else 2 end,
name
and for MySQL the following works since it returns 0 for false and 1 for true
select * from your_table
order by name <> 'Teacher',
name
Use FIELD function
SELECT * FROM table ORDER BY FIELD(`name`,'Teacher') ASC
select * from table order by case when name like "Teacher%" then 1 else 2 end,name
Names starting with Teacher will be on top sorted alphabetically, then the rest.
Example
Teacher
Teacher Aaron
Teacher Zed
Aaron
Zed
I have a Database table in MYSQL, it looks like this:
Project_ID user_ID name
11 1 fred
11 2 rick
11 1 fred
I want to get the names in the table, but when I display it I get the same name twice because the user_ID 1 appears twice in the table. I tried to display it with GROUP BY and SUM, but I don't want to do it this way. How do I get it not to return duplicate rows?
Use DISTINCT
SELECT DISTINCT user_ID
, verschil_ma
FROM project_uren
WHERE project_ID = 11
GROUP BY user_ID
Point 1 is that should the user be assigned to the project twice?
Point 2 - Use the DISTINCT keyword to return only unique records - http://dev.mysql.com/doc/refman/5.0/en/distinct-optimization.html
SELECT DISTINCT user_ID
FROM TABLE
WHERE Project_id = 11
That will return you 1 and 2 (You won't get 1 twice)
Thanks
$results = // query
$results = array_unique($results);
Is there a way I could somehow do the following?
Table ONE
id c_id type
-------------------
1 1 7
2 2 7
3 3 5
4 4 7
Table TWO
id title live
-------------------
1 row1 1
2 row2 0
3 row3 0
4 row4 1
The c_id column links the data from table ONE to table TWO. Example: in table ONE, if the c_id is 2, that row in table ONE will be directly linked to table TWO's row with id 2, which has a title of "row2".
I want to select from table ONE, everything with type 7, but only if their associated data in table TWO has live set to 1.
Here's how I thought I'd do it, but this doesn't seem to work:
SELECT * FROM ONE, TWO WHERE ONE.type='7' AND TWO.live='1' ORDER BY ONE.id DESC LIMIT 5
I would expect the above to return only rows 1 and 4 from table ONE, because although table ONE has three rows with type "7", only rows 1 and 2's associated row in table TWO have live set to 1.
You were close... try using an implicit join:
SELECT ONE.* FROM ONE, TWO WHERE ONE.type='7' AND TWO.live='1' AND ONE.c_id = TWO.id ORDER BY ONE.id DESC LIMIT 5
select * from one join two on c_id = two.id where type=7 and live = 1
order by one.id desc limit 5