Insert data from one table to another in joined table - php

Question

This sends "customers.id" to another php file :
echo '<a class="btn btn-primary" href="createworkorder.php?id='.$row['id'].'">Add Workorder</a>';
This pulls the id date just sent :
$id = null;
if ( !empty($_GET['id'])) {
$id = $_REQUEST['id'];
}
if ( null==$id ) {
header("Location: customers.php");
}
This looks at values/ and inserts data from extra workorder table form post :
$id = $POST['name'];
$date = $_POST['date'];
$installer = $_POST['installer'];
$salesman = $_POST['salesman'];
$category = $_POST['category'];
$status = $_POST['status'];
if ($valid) {
$pdo = Database::connect();
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$sql = "INSERT INTO workorder (date, installer, salesman, category, status) values(?, ?, ?, ?, ?)";
$q = $pdo->prepare($sql);
$q->execute(array( $id,$date,$installer,$salesman,$category,$status));
Database::disconnect();
header("Location: workorders.php");
}
<form class="form-horizontal" action="createworkorder.php" method="post">
<div class="control-group <?php echo !empty($dateError)?'error':'';?>">
<label class="control-label">Date</label>
<div class="controls">
<input name="date" type="text" placeholder="Date" value="<?php echo !empty($date)?$date:'';?>">
<?php if (!empty($dateError)): ?>
<span class="help-inline"><?php echo $dateError;?></span>
<?php endif; ?>
</div>
</div>
<div class="control-group <?php echo !empty($installerError)?'error':'';?>">
<label class="control-label">Installer</label>
<div class="controls">
<input name="installer" type="text" placeholder="Installer" value="<?php echo !empty($installer)?$installer:'';?>">
<?php if (!empty($installerError)): ?>
<span class="help-inline"><?php echo $installerError;?></span>
<?php endif;?>
</div>
</div>
for some odd reason, it looks like everything executes(no errors), but no data shows up in my workorders table. This is what is supposed to happen
Pull customers.id from user selection, and store into workorder.name
Pull extra information(date/installer/salesman/etc) from form, and use all of the data to insert into workorder table.
Does anyone see if there is something dumb causing this not to happen?

Answer 1

It's been awhile since I spoke PHP, but are you inserting too many variables?
Specifically, in the code below, is including $id throwing it off? If you have to include $id, should you modify the INSERT query to include a spot for the id?
$q->execute(array( $id,$date,$installer,$salesman,$category,$status));