Searching multidimensional array subarray - php

Question

hi i have following array
$langarr[0][0] = gb
$langarr[0][1] = 1
$langarr[1][0] = de
$langarr[1][1] = 2
$langarr[2][0] = fr
$langarr[2][1] = 3
$langarr[3][0] = it
$langarr[3][1] = 5
Now i wanna search to unset like
if(($keyy = array_search('de', $langarr[][0])) !== false) {
unset($langarr[$keyy]);
}
So i wanna search in the langarr[any][0] and if matched I want to delete the whole dataset like unset($langarr[X]);
How can this be achieved?

Answer 1

$langarr = array();
$langarr[0][0] = "gb";
$langarr[0][1] = "1";
$langarr[1][0] = "de";
$langarr[1][1] = "2";
$langarr[2][0] = "fr";
$langarr[2][1] = "3";
$langarr[3][0] = "it";
$langarr[3][1] = "5";
// Get the key of search array
$value = recursive_array_search("de",$langarr);
// print the key
print_r($value);
// unset the array "de" which has key "1"
unset($langarr[$value]);
// print the resultant array
print_r($langarr);
function recursive_array_search($needle,$haystack) {
foreach($haystack as $key=>$value) {
$current_key=$key;
if($needle===$value OR (is_array($value) && recursive_array_search($needle,$value) !== false)) {
return $current_key;
}
}
return false;
}

Answer 2

Use array_filter(). It takes a (anonymous) function as the second argument. The function itself receives an array element as its argument. If that function returns false, the array element is removed from the array.
So to take your example, if $needle is 'de', the subarray is removed.
$langarr = array(
array('gb', 1),
array('de', 2),
);
$needle = 'de';
$langarr = array_filter($langarr, function($row) use($needle) {
return ($row[0] != $needle);
});
Online test

Answer 3

<?php
$langarr[0][0] = "gb";
$langarr[0][1] = 1;
$langarr[1][0] = "de";
$langarr[1][1] = 2;
$langarr[2][0] = "fr";
$langarr[2][1] = 3;
$langarr[4][0] = "it";
$langarr[4][1] = 4;
print_r($langarr);
foreach($langarr as $key=>$data){
if($data[0]=='de'){
unset($langarr[$key]);
}
}
print_r($langarr);
?>