How can I make a submenu - php

Question

I have the next database:
I have the below function:
<?php
$connection = mysql_connect("localhost", "root", "password") or die(mysql_error());
mysql_select_db("database1", $connection) or die(mysql_error());
function loop_array($array = array(), $parent_id = 0)
{
if (!empty($array[$parent_id])) {
echo '<ul>';
foreach ($array[$parent_id] as $items) {
echo '<li>';
echo ''.$items['title'].'';
loop_array($array, $items['id']);
echo '</li>';
}
}
}
function displays_menus_revised()
{
$sql = "SELECT * FROM pages";
$query = mysql_query($sql) or die(mysql_error());
$array = array();
if (mysql_num_rows($query)) {
while ($rows = mysql_fetch_array($query)) {
$array[$rows['parent_id']][] = $rows;
}
loop_array($array);
}
}
?>
My problem is the funtion show the records like in the left picture. I want the function to show the records like in the right picture. Can you tell me where is the problem? What i must change that the function show records like in the right picture? Thanks.

Answer 1

So nice code, with such a small slip. Only the closing 'ul' is missing.
function loop_array($array = array(), $parent_id = 0)
{
if (!empty($array[$parent_id])) {
echo '<ul>';
foreach ($array[$parent_id] as $items) {
echo '<li>';
echo ''.$items['title'].'';
loop_array($array, $items['id']);
echo '</li>';
}
echo '</ul>';
}
}