hello all i am trying to find the recent birthday of the registered members on the site and also store the result of query into session so that next time the query need not to be executed so to reduce the page load time and also server load
i am having this code
if(!isset($_SESSION['dob']) || $_SESSION['dob'] =='' ){
$frndlist=$_SESSION['friendlist']; //comma seperated list of friends
$CurrMOnth= date('m'); // this month
$BirthDLAST0n=date('d', strtotime(' - 7 day'));
$BirthDGRATEn=date('d', strtotime(' + 7 day'));
$GEttheBIrthdaYS=mysqli_query($connection,"select id,name,dob from members
where (id IN ($frndlist)) and (MONTH(dob) = '$CurrMOnth') and
(DAY(dob) > '$BirthDLAST0n' and DAY(dob) < '$BirthDGRATEn' )
order by dob desc limit 10");
$_SESSION['dob']=$GEttheBIrthdaYS;}else{
$GEttheBIrthdaYS=$_SESSION['dob'];
}
while($theBdaYSreYAr90=mysqli_fetch_array($GEttheBIrthdaYS)){ //print }
but the problem here is result of query is stored into session but it is never accepted by the mysqli_fetch_array it says error.
this is problem because i am trying to store object onto session
is there any alternative to store the result into something so that the same query need not to be executed gain again ....
and also the birthday script is not good it dosent displays the birthday of people whose DOB is at the last or begning of months.
please let me know how to store the result of query into session or cookie
as cookie stores very less size i dont think cookie is good option.
Looks like you're trying to put a whole array into the session var, just break it up.
$result = mysql_fetch_array($GettheBIrthdaYS);
$_SESSION['dob'] = $result['dob'];
Also make your limit 1, unless you want more than 1 record, which if you do then you will need to change everything.
Related
I am trying to convert three separate database columns into a date (day,month,year) and calculate the age so only users over the age of 15 or 18 can purchase certain products. The code below doesnt work as it echoes '0 days, 0 months, 0 years' and still adds the product to the basket. Which means the age calculation doesnt work, and my first if statement doesnt work either.
<?php
$username = $_SESSION['solentuser'];
echo "$username's account!<br>";
$conn = new PDO("mysql:host=localhost;dbname=u;","u","p");
$productID= htmlentities($_GET['ID']);
//startdate
$result=$conn->prepare("SELECT * FROM users WHERE username=:username");
$result->bindParam(":username",$username);
$result->execute();
$row=$result->fetch();
$birthdate = $row['yearofbirth'] . $row['monthofbirth'] . $row['dayofbirth'];
$presentdate = date('Ymd');
$birthday = new DateTime($birthdate);
$currentdate = new DateTime($presentdate);
$age = $birthday->diff($currentdate);
echo $age->format('<br>%d Days %m Months %y Years<br>');
//enddate
$results=$conn->prepare("SELECT * FROM products where ID=:productID");
$results->bindParam(":productID",$productID);
$results->execute();
$row=$results->fetch();
if($row['agelimit'] <= $age){
if($row['stocklevel'] >= 1){
$result=$conn->prepare("INSERT INTO basket(productID,username,qty) values(:productID,:username,1)");
$result->bindParam(":productID",$productID);
$result->bindParam(":username",$username);
$result->execute();
$result=$conn->prepare("UPDATE products SET stocklevel=stocklevel-1 WHERE ID=:productID");
$result->bindParam(":productID",$productID);
$result->execute();
echo "You have successfully added this product to your basket!";
}
else{
echo "This product is out of stock!";
}
}
else{
echo "You are not old enough to purchase this product!";
}
//print_r($conn->errorInfo());
?>
any suggestions as to where the error is? i have read that it is possible to write an if statement inside an if statement, so why does this one not work?
thank you!
I'd echo out $birthdate and verify there's a valid date there. (We aren't getting back single digits, a date of 2009-05-04 getting represented as '2009', '5' and '4' such that when we concatenate them, we get 200954, or maybe extra spaces. (We're not seeing the datatypes of the three separate columns.)
We might try adding some delimiters in there, so we'd get 2009-5-4, likely we could get that converted into a DateTime, using the correct format string.
If I had separate values for month, day and year, I would use PHP mktime, and then create a DateTime object from that.
(MySQL does provide a DATE datatype that allows for a very large range of valid dates, and doesn't allow invalid dates to be stored. Storing three separate columns to represent a single date just smells like the wrong way to do it. (If I actually needed the separate month and day columns (to allow indexing for some queries), I would add those in addition to the birthdate DATE column, not in place of it, with triggers to keep the values in sync with the birthdate column.)
Also, $age is a DateInterval object. You seem to be aware that we can use the format method to extract integer number of years.
$age_yrs = $age->format('%y');
We're guessing that the database column age_limit is integer years.
if( $row['agelimit'] <= $age_yrs ) {
Right before that if statement, we can confirm that what we think to be true is actually true...
echo " age_yrs=" . $age_yrs;
echo " row_age_limit=" . $row['age_limit'];
Looking closely at the debugging output helps us identify if the problem is before the if statement or after, so we aren't chasing down a problem in a section of code where there isn't a problem, the problem is somewhere else, on a preceding line.
I encourage you to develop the skills needed to debug programs that you write. It seems like you are making some (wrong) assumptions about what the variables are containing.
Adding echo and var_dump during development is a first step in verifying that what you think to be true is actually true.
I'd go as far as recommending that you look at every line of code you write as possibly going wrong, especially in edge cases.
https://ericlippert.com/2014/03/05/how-to-debug-small-programs/
(StackOverflow is a question/answer community, not a debugging service.)
I am providing 24 hours trial membership in my android application. I do not know more about PHP. I want check user registration time and want disable trial membership if 24 hours got passed. I have made little PHP file for that.
$sql = "SELECT id, email, registration_time FROM user WHERE trial = 1";
$result = $conn->query($sql);
if($result) {
while($row = $result->fetch_row()) {
$id = $row[0];
$email = $row[1];
$registrationTime = strtotime($row[2]);
$currentTime = strtotime("-1 day");
if($currentTime > $registrationTime) {
$update = "UPDATE user SET trial = 0 WHERE email = '$email'";
$conn->query($update);
$update = "UPDATE number_list SET disable = 1 WHERE user_id = $id";
$conn->query($update);
}
}
}
Its not providing any result even I have one user which time passed more than 48 hours.
How can I solve this issue?
try this and check
$currentTime=date('m-d-Y',strtotime($registrationTime . "-1 days"))
You should use a prepared statement to update the database for all the users with the same email (your first update query). Also see the documentation.
If someone registers with an e-mail address like test'; DROP ALL TABLES; --#gmail.com1 this code will dutifully remove your database. Never put user data into code directly like that.
Now let's look at the example code;
$sql = "SELECT id, email, registration_time FROM user WHERE trial = 1";
$result = $conn->query($sql);
if($result) {
while($row = $result->fetch_row()) {
You're saying there is no result at all. I assume that you've tested the output with a debug statement. E.g. putting echo 'users exist'; in between here. The first thing to do would be to check your user table if there are any rows. Does this SQL query produce results?
Assuming that it does, there doesn't appear to be anything wrong with the SQL statement. Assuming you have a table called user with four columns id, email, registration_time, and trial it should produce results.
Next, what you want to do is read the query function documentation. As you can see there, when a query fails, for whatever reason, it returns FALSE. Try writing an 'else' code block and logging the error that occurs. You can fetch it using the error function mysqli::error. Try appending this code;
} else {
echo "MySQL Error: " . $conn->error;
}
Where you can replace the echo with your error handling of choice.
It's probably a good idea to write a wrapper for mysqli if you're going to execute more than a few queries in your application. That way, you can write error handlers in your wrapper class for what your application should do if a query or database connection fails.
What could also be the case is that, while your initial query succeeds and fetches some rows, the time check fails. You may want to do some stricter date/time parsing than using strtotime and hoping for the best. Assuming you're using a TIMESTAMP column to store the data, you can use this:
function readDatabaseTimestampValue($value) {
$dateTime = date_create_from_format("Y-m-d H:i:s", $value);
$timestamp = $dateTime->getTimestamp();
return $timestamp;
}
Check the exact time data returned from your database. Dates and times are complicated, and if things are reinterpreted, say the day number in SQL may become the year in the PHP app, which can cause strange bugs. E.g. you can do this by doing say:
echo "24 hours ago: " . strtotime("-1 day") . ", user data: " . $row[2];
Next, you probably have some bugs in the logic. '24 hours ago' is better done by doing this, as using '-1 day' will cause weird issues when people mess with the calendar:
$timestamp = time() - 86400;
There's 86,400 seconds in a day (well, excluding DST and leap seconds, but you want 24 hours of subscription time, not 23 hours around the 21st of March).
Finally, there's problems if the same E-mail address is present more than once in the table. You will set 'trial' to 0 for one user, but may set the 'disable' flag for another if two users register within the same 24-hour period with the same e-mail. If the latter is guaranteed to be unique then this is no issue. Otherwise, you may want to update by id in both tables.
Next, we can look at some optimization. Right now, you fetch everything from the database. But you can do much better/faster by having an index on registrationTime, and using the database's sorting features. E.g. let's say we know the exact date/time of 24 hours ago as $yesterday in PHP we can write a query like:
SELECT id, email, registration_time FROM user WHERE trial = 1 AND registration_time > ?
Bind the $yesterday variable to the parameter. Now you no longer need the if() statement; the database does it for you. Also, as your database grows, you're not checking the old records one-by-one every time the code runs.
1Note, that may not be a legal e-mail address, but there's probably ways to do evil things even with a legal mail address.
I'm trying to count the unique visitors each day on my website.
This is the script i made:
<?php
require_once 'database.php';
$dateQuery = $db->prepare("SELECT count(*) AS hits FROM tracked GROUP BY DATE(date), hostadrr");
$dateQuery->execute();
$rows = $dateQuery->fetchAll(PDO::FETCH_ASSOC);
$array = array();
foreach ( $rows as $row ) {
$array[] = [(int)$row['hits']];
}
$json = json_encode($array);
echo $json;
?>
This array I get from the json_encode is then this:
[[3],[1],[1],[2],[10],[3],[1],[2]]
It is correct that there are 8 arrays inside an array, this represents each day. But the number inside each array are just the total number on clicks on my website, not grouped by the host address of the user. What am i doing wrong here? The array should be: [[1],[1],[1],[1],[1],[1],[1],[1]] (because i'm testing it on my own computer ;) )
First of all, always try to strip down your code to the minimal problem. For example, don't mix JSON encoding, PHP and MySQL and be astonished, that the result isn't what you look like.
Start with the SQL query:
SELECT count(*) AS hits FROM tracked GROUP BY DATE(date), hostadrr
Did you try to run that on console or in phpMyAdmin? Is the correct result showing up?
I would guess not. Why? Because this query only returns a number of hits without any relation to a date or a host address. So, even though you say that the data is correct for the total hits in a day, you can't even be sure if it is the right order or if it doesn't leave out days without any hits.
Since you do not provide your SQL schema, I can only assume one. But your query should at least look something like this:
SELECT
date AS date,
hostadrr AS host,
count(*) AS hits
FROM
tracked
GROUP BY
DATE(date),
hostadrr
ORDER BY
date ASC
Now, you'll get one line for each date/host combination along with the respective number of hits and you can assign that to an array, i.e.
$array[$row['date']][$row['host]] = (int) $row['hits'];
How would I go about programming a daily message on my site that changes daily? I'm thinking of preloading all the messages in a MySQL database.
Any help would be appreciated!
Thanks,
I've tried
$msg_sql = "SELECT * FROM ".TABLE_PREFIX."quotes ORDER BY rand(curdate()) LIMIT 3";
$msg_res = mysqli_fetch_assoc(mysqli_query($link, $msg_sql));
But this only grabs the first MySQL result?
If you want a real message changing daily, you actually don't need to rely on a database or anything fancy. A simple idea might be to create a directory (say /var/www/motds) and populate it with files named YYYY-MM-DD.txt (where YYYY is a 4 digit year number, MM is a two digit month number and DD is a 2 digit day number).
Then, the only thing you need to do in order to display your motd is:
$filename = '/var/www/motds/'.date("Y-m-d").'.txt';
if (file_exists($filename)) {
echo file_get_contents($filename);
}
If you want your daily messages to be taken from a pool of entries (that you can pre-load), you might do something as follows:
$files = scandir('/var/www/motds'); // put files into an array
$messagecount = count($files) - 2; // .. and . shall not be considered
$day = date("z"); // what day do we have today?
echo file_get_contents('/var/www/motds/' . $files[($day % $messagecount) + 2]);
There are plenty of ways to get this done. You list PHP in your tags, so maybe check here:
PHP Script: Quote of the Day
or maybe here
I'm counting the right answers field of a table and saving that calculated value on another table. For this I'm using two queryes, first one is the count query, i retrieve the value using loadResult(). After that i'm updating another table with this value and the date/time. The problem is that in some cases the calculated value is not being saved, only the date/time.
queries look something like this:
$sql = 'SELECT count(answer)
FROM #_questionsTable
WHERE
answer = 1
AND
testId = '.$examId;
$db->setQuery($sql);
$rightAnsCount = $db->loadResult();
$sql = 'UPDATE #__testsTable
SET finish = "'.date('Y-m-d H:i:s').'", rightAns='.$rightAnsCount.'
WHERE testId = '.$examId;
$db->setQuery($sql);
$db->Query();
answer = 1 means that the question was answered ok.
I think that when the 2nd query is executed the first one has not finished yet, but everywhere i read says that it waits that the first query is finished to go to the 2nd, and i don't know how to make the 2nd query wait for the 1st one to end.
Any help will be appreciated. Thanks!
a PHP MySQL query is synchronous ie. it completes before returning - Joomla!'s database class doesn't implement any sort of asynchronous or call-back functionality.
While you are missing a ';' that wouldn't account for it working some of the time.
How is the rightAns column defined - eg. what happens when your $rightAnsCount is 0
Turn on Joomla!'s debug mode and check the SQL that's generated in out the profile section, it looks something like this
eg.
Profile Information
Application afterLoad: 0.002 seconds, 1.20 MB
Application afterInitialise: 0.078 seconds, 6.59 MB
Application afterRoute: 0.079 seconds, 6.70 MB
Application afterDispatch: 0.213 seconds, 7.87 MB
Application afterRender: 0.220 seconds, 8.07 MB
Memory Usage
8511696
8 queries logged.
SELECT *
FROM jos_session
WHERE session_id = '5cs53hoh2hqi9ccq69brditmm7'
DELETE
FROM jos_session
WHERE ( TIME < '1332089642' )
etc...
you may need to add a semicolon to the end of your sql queries
...testId = '.$examID.';';
ah, something cppl mentioned is the key I think. You may need to account for null values from your first query.
Changing this line:
$rightAnsCount = $db->loadResult();
To this might make the difference:
$rightAnsCount = ($db->loadResult()) ? $db->loadResult() : 0;
Basically setting to 0 if there is no result.
I am pretty sure you can do this in one query instead:
$sql = 'UPDATE #__testsTable
SET finish = NOW()
, rightAns = (
SELECT count(answer)
FROM #_questionsTable
WHERE
answer = 1
AND
testId = '.$examId.'
)
WHERE testId = '.$examId;
$db->setQuery($sql);
$db->Query();
You can also update all values in all rows in your table this way by slightly modifying your query, so you can do all rows in one go. Let me know if this is what you are trying to achieve and I will rewrite the example.