PHP mysql_fetch_array/Row not displaying Unique elements - php

Question

I am trying to create a php based search function, with following code:
<?php
$d_name=$_POST['id'];
//connect to the database
$db=mysql_connect ("localhost", "root", "") or die ('I cannot connect to the database because: ' . mysql_error());
//-select the database to use
$mydb=mysql_select_db("pgr");
if(!$mydb)
echo "db not selected";
//-query the database table
$d_name=(int)$d_name;
$sql="SELECT * FROM omimentry WHERE OMIM_ID=$d_name";
//-run the query against the mysql query function
$result=mysql_query($sql) or die(mysql_error());
$n=mysql_fetch_array($result);
//-create while loop and loop through result set
if($n)
{
echo "<table border = 1 width=\"95%\" border=\"0\" cellpadding=\"2\" cellspacing=\"2\" class=\"text_black\">
<tr class=\"yellow\">
<td width=\"10%\" align=\"center\" valign=\"middle\" class=\"text_black_bold\">OMIM_ID</td>
<td width=\"20%\" align=\"center\" valign=\"middle\" class=\"text_black_bold\">location(chromosome)</td>
<td width=\"30%\" align=\"center\" valign=\"middle\" class=\"text_black_bold\">phenotype</td>
<td width=\"20%\" align=\"center\" valign=\"middle\" class=\"text_black_bold\">MIMnumber</td>
<td width=\"20%\" align=\"center\" valign=\"middle\" class=\"text_black_bold\">Gene</td>
<td width=\"20%\" align=\"center\" valign=\"middle\" class=\"text_black_bold\">GeneMIMnumber</td>
<td width=\"20%\" align=\"center\" valign=\"middle\" class=\"text_black_bold\">geneid</td>
<td width=\"30%\" align=\"center\" valign=\"middle\" class=\"text_black_bold\">protein</td>
</tr> ";
while($rows=mysql_fetch_row($result))
{
echo "
<tr class=\"text_black\" align=\"left\" valign=\"middle\">
<td width=\"10%\">$rows[1]</td>
<td width=\"20%\">$rows[2]</td>
<td width=\"30%\">$rows[3]</td>
<td width=\"10%\">$rows[4]</td>
<td width=\"20%\">$rows[5]</td>
<td width=\"20%\">$rows[6]</td>
<td width=\"20%\">$rows[7]</td>
<td width=\"30%\">$rows[8]</td>
</tr>";
}
echo " </table> " ;
}
else
echo "Sorry Data Not Available";
?>
The problem, which is rather unique, is that this code is displaying those queries which have duplicate entries(and even for those, it is displaying result for the last row, not all rows with duplicate OMIM_ID). And for unique OMIM_ID, there are no results, even though there is no explicit error.
Table Scheme:
int OMIM_ID
varchar2 location(chromosome)
varchar2 phenotype
int MIMnumber
varchar2 Gene
int geneMIMNumber
int geneid
varchar2 Protein
Any clues on what I am doing wrong ?
--Update--
Even after updating my code to:
<?php
$d_name=$_POST['id'];
$db = new PDO('mysql:host=localhost;dbname=pgr;charset=utf8', 'root', '');
if(!$mydb)
echo "db not selected";
//-query the database table
$d_name=(int)$d_name;
$stmt = $db->prepare("SELECT * FROM table WHERE id=?");
$stmt->execute(array($d_name));
$rows = $stmt->fetchAll(PDO::FETCH_ASSOC);
echo "<br>";
echo "<br>";
foreach($rows as $name => $value) {
echo "<tr><th>".htmlspecialchars($name).
"</th><td>".htmlspecialchars($value)."</th></tr>";
?>
I am getting same error.
Update: A more clear view on problem.
Database:
Table:
int OMIM_ID|varchar2 location(chromosome)|varchar2 phenotype|int MIMnumber|varchar2 Gene|int geneMIMNumber|int geneid|varchar2 Protein
Entries:
2141|24q.xx|Some disease|4651|SomeID|56525|5625|SomeProteinID
2141|21q.xx|Some disease|4651|SomeID|56545|5625|SomeProteinID
2142|24q.xx|Some disease|4651|SomeID|56525|5625|SomeProteinID
Now, given 2141 as query, the code will display 2nd entry in result, not the first one, which should have been included too.
If 2142 is the query, there is no output, ideally, the possible output should have been the row described by OMIM_ID 2142.

Answer 1

I do not know what is in your tables and what duplicates you are referring to. Because you got trashed so bad, I risked getting trashed helping you with unconventional code.
The comments about using depreciated mysql had no bearing on your code but they just don't like others that come here for a solution to think it is OK to use mysql. They do not realize when you post a question how frustrated you are and how they are adding to your frustration. They mean well but in your case you changed your code to accommodate them and you not realizing it had nothing to do with a solution.
NOTE: this solution uses depreciated mysql and not the newer mysqli
This will eliminate duplicates:
while ($row = mysql_fetch_array($results, MYSQL_NUM)) {
$data[] = serialize(array($row[1],$row[2],$row[3],$row[4],$row[5]));
}
$data = array_unique($data);
To try and keep the first duplicate:
while ($row = mysql_fetch_array($results, MYSQL_NUM)) {
$data[] = serialize(array($row[1],$row[2],$row[3],$row[4],$row[5]));
}
$data = array_reverse ($data);
$data = array_unique($data);
ksort($data); // puts them back in original order.
OR
while ($row = mysql_fetch_array($results, MYSQL_NUM)) {
$columns = serialize(array($row[1],$row[2],$row[3],$row[4],$row[5]));
if (!in_array($columns,$data)){
$data[] = serialize(array($row[1],$row[2],$row[3],$row[4],$row[5]));
}
}
Then the new loop is:
foreach($data as $key => $value){
$row = unserialize($value);
}
There are other ways to use this to eliminate some dups and exclude others.
$uniqueRows = serialize(array($row[1],$row[2]));
$data[$uniqueRows] = array($row[3],$row[4],$row[5]);