SQL Syntax error - SET - php

Question

SQL error in a PHP script, I'm very new to SQL. It's probably something silly that's been asked loads before, but I'm probably searching for the wrong thing and therefore can't find an answer - I did look!
SQL error
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'SET approved = '1' WHERE primary = '16'' at line 1
The problem line:
$query = "UPDATE $table SET approved = '1' WHERE primary = '$id';";
Rest of my code:
<?PHP require ('config.php');
$id = $_GET['id'];
$query = "UPDATE $table SET approved = '1' WHERE primary = '$id';";
$execute = mysqli_query($conn,$query);
if ($execute){
echo "Entry $id successfully approved.";
}
else { echo "Error: " . $sql . "<br>" . mysqli_error($conn);};
?>

Answer 1

Try this way to set your $table variable first as it causes Syntax Error & add backtick (`) to your primary column name, because it's RESERV Keyword of MYSQL, But this may be not the main reason here.
<?php
require ('config.php');
try {
$id = $_GET['id'];
$approved=1;
$table="your_table_name"; // set table name here
$database="your_database_name";
$dbUser="your_user_name";
$dbPass="your_password";
$dbh = new PDO("mysql:host=your_host_name;dbname=$database", $dbUser, $dbPass);
$dbh->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$stmt = $dbh->prepare("UPDATE $table SET approved =? WHERE `primary` = ?");
$stmt->execute(array($approved,$id));
echo "Entry $id successfully approved.";
} catch(PDOException $e) {
echo $e->getMessage();
}
?>