menu link which show a div in another div - php

Question

I created a menu with links (#) which aims to show & hide a div thanks to the onclick attribute.
For example the link "home" can hide/show the div "contentHome", the link "contact" can hide/show the div "contentContact".
The problem I have is that the container div "content" includes the div "contentHome" and "contentContact" when i click on the 2 links one time...
Here is a part of my code :
<li><a href="#" onclick="toggle('contentHome');" ><?php echo $lang['MENU_ACCUEIL'];?>
<div id="content">
<div id="contentHome">
<img src="Images/photo.jpg" class="imgphoto" alt="Simplepic" />
<?php echo $lang['TEXTE_ACCUEIL'];?>
<img src="Images/work.png" class="imgwork" height="100" width="100" alt="Travaux" />
<?php echo $lang['TEXTE_SOON'];?>
</div>
<div id="contentContact">
...
</div>
</div>
The position is static, I can't put a z-index and when I put display:none;, divs don't want to load.
What do you think ? I just wanted to create a dynamic menu with div but the php includes makes me struggle...

Answer 1

Here i've created some example of toggle with divs.
<li>Toggle Red</li>
<li>Toggle Blue</li>
<div id="content">
<div class="toggled-item" id="contentHome">
<div style="width:200px; background-color:#f00; height:200px;"></div>
</div>
<div class="toggled-item" id="contentContact">
<div style="width:200px; background-color:#00f; height:200px;"> </div>
</div>
</div>
<script>
$(document).ready(function(){
$("#lnk_contentHome, #lnk_contentContact").click(function(){
$(".toggled-item").hide();
var target = $(this).attr("id").split("_")[1];
$("#" + target).toggle();
});
});
</script>
https://jsfiddle.net/ow7dd12f/5/
Hope helps.