SQL value won't change as image changes in dynamic Lightbox gallery? - php

Question

I have tried many hours just to get this tiny piece of information to show, I need help before I decide to brake my laptop in two pieces.
I am trying to get an uploaded image to display a caption along with username (person who uploaded it) and date. These three values are stored in my database, the upload works fine. As I loop through the directory to display my images, I cannot get these values (passed as variables) to display correctly, rather the last upload input is the only one that displays for every image in my gallery.
I assume there is something wrong in my loop code and will post it here in hope that it is a simple overlooked fact.
//Open directory
$dir_handle = opendir($thumb_dir) or die('Error opening thumbnail directory.');
while ($file = readdir($dir_handle)) { //go through files
//if ($file == '.' || $file == '..') continue;
$file_parts = explode('.', $file); //split filename and put extensions in array
$ext = strtolower(array_pop($file_parts)); //last element file extension
//Filename w/o extension.
$title = implode('.', $file_parts); //only filename
$title = htmlspecialchars($title); //security measure
$dbconnect = mysqli_connect('localhost', 'peter', '1234', 'dt091g');
$query = 'SELECT username, date FROM image_info';
$result = mysqli_query($dbconnect, $query);
while ($row = mysqli_fetch_assoc($result)){
$username = $row['username'];
$date = $row['date'];
}
//add every image if good extension
if (in_array($ext, $allowed_exts)) {
echo '<a class="example-image-link"
href="'.$img_dir.$file.'"
data-lightbox="example-set"
data-title="'.$username.$date.'">
<img class="example-image" src="'.$thumb_dir.$file.'" alt="hello"/>
</a>';
$i++; //increment the image counter
}
}
closedir($dir_handle); ?>
I am assuming I must incorporate the unique ID somehow, and I have tried myself blind, but still end up with only the last value for any row of my db table.
Appreciate any kind of input, even if you're just writing to say 'Duh! You idiot'.
EDIT: Showing a record of image_info
$image_info = array( array('id' => '50','username' => 'Peter','date'
=> '05052015','filename' => '20140808_220541.jpg','mimetype' => 'image/jpeg','filesize' => '2404856','caption' => 'Norwegian
Mountains'));