Attempting to add count function to a complex query PHP MYSQL - php

Question

I have a complex query consisting of lots of Inner and Left Joins and i am attempting to get the number of record back in a certain table using the COUNT Function of SQL.
I am attempting to get the number of records in the 'held_proposals' table for each proposal using the proposal_id since I'll be outputting the data into a table using a foreach loop.
In essence I would like to show how many students have 'held' a proposal against each proposal.
This was my attempt:
SELECT p.proposal_id, p.proposal_title, p.description, u.user_record_id, u.forename, u.surname, c.course_title, h.*,
GROUP_CONCAT(DISTINCT t.tag_title) AS tags FROM proposal p
LEFT JOIN user u on u.user_record_id = p.user_record_id
LEFT JOIN course_details c on c.course_code = p.course_code
LEFT JOIN record r on r.proposal_id = p.proposal_id
LEFT JOIN proposal_tags pt on pt.proposal_id = p.proposal_id
LEFT JOIN tag_details t on t.tag_code = pt.tag_code
LEFT JOIN (
SELECT h.student_record_id, COUNT(*) AS Held
FROM held_proposals h
) H on h.proposal_id = p.proposal_id
WHERE p.source = "Supervisor"
AND (r.status_code not in (3,8) OR r.status_code IS NULL)
GROUP BY p.proposal_id;
the table currently looks like this:
I would like to add the value returned from the 'held_proposals' table for each proposal at the end of the table as another column.
Could any please provide me with some guidance as to how I can achieve this in the SQL query. Thank you in advance.

Answer 1

You need to group the count inside the query which you are joining something as
SELECT
p.proposal_id,
p.proposal_title,
p.description,
u.user_record_id,
u.forename,
u.surname,
c.course_title, coalesce(h.Held,0) as `Held`,
GROUP_CONCAT(DISTINCT t.tag_title) AS tags
FROM proposal p
LEFT JOIN user u on u.user_record_id = p.user_record_id
LEFT JOIN course_details c on c.course_code = p.course_code
LEFT JOIN record r on r.proposal_id = p.proposal_id
LEFT JOIN proposal_tags pt on pt.proposal_id = p.proposal_id
LEFT JOIN tag_details t on t.tag_code = pt.tag_code
LEFT JOIN (
SELECT proposal_id, COUNT(*) AS Held
FROM held_proposals group by proposal_id
) h on h.proposal_id = p.proposal_id
WHERE p.source = "Supervisor"
AND (r.status_code not in (3,8) OR r.status_code IS NULL)
GROUP BY p.proposal_id;