Laravel skip directory from framework - php

Question

I am facing a problem, the mapping of my site looks like this:
- app
- bootstrap
- public_html
- archives
- css
- js
index.php
- vendor
composer.json
etc...
My .htaccess is located in public_html. I want to skip the directory public_html/archives from the whole framework. How would I do that? I want the route mysite.com/archives to be accessible outside Laravel.
Edit:
Here is my htaccess file
<IfModule mod_rewrite.c>
<IfModule mod_negotiation.c>
Options -MultiViews
</IfModule>
RewriteEngine On
# Redirect Trailing Slashes...
RewriteCond %{REQUEST_URI} "/public/archives/" <--- ADDED!
RewriteRule ^(.*)/$ /$1 [L,R=301]
# Handle Front Controller...
RewriteCond %{REQUEST_FILENAME} !-d
RewriteCond %{REQUEST_FILENAME} !-f
RewriteRule ^ index.php [L]

Answer 1

As others have noted, Laravel won't process any files or directories that exist because of the following rules:
RewriteCond %{REQUEST_FILENAME} !-d
RewriteCond %{REQUEST_FILENAME} !-f
First, take this rule out of your .htaccess file:
RewriteCond %{REQUEST_URI} "/public/archives/"
Then, after the RewriteEngine On line, you need to add this rule:
RewriteRule ^archives/?$ - [PT]
So your .htaccess file will look like this:
<IfModule mod_rewrite.c>
<IfModule mod_negotiation.c>
Options -MultiViews
</IfModule>
RewriteEngine On
RewriteRule ^archives/?$ - [PT]
# Redirect Trailing Slashes...
RewriteRule ^(.*)/$ /$1 [L,R=301]
# Handle Front Controller...
RewriteCond %{REQUEST_FILENAME} !-d
RewriteCond %{REQUEST_FILENAME} !-f
RewriteRule ^ index.php [L]
</IfModule>
Alternatively, you can just add the following line before RewriteCond %{REQUEST_FILENAME} !-d:
RewriteCond %{REQUEST_URI} !^/archives/?.*$