Select child records from tables mysql - php

I got the bellow piece of select statement that got level 2 child records, having problems to got deeper, can anyone help out?
SELECT
id_mobile AS ID_PROJETO,
UM.qtd_UC,
AM.qtd_AMBIENTE
FROM projetos_mobile AS PM
LEFT JOIN (
SELECT
COUNT(id) AS qtd_UC,
projeto,
data_hora_importacao,
id_uc_mobile
FROM ucs_mobile
WHERE data_hora_importacao = '2015-05-15 17:21:02'
GROUP BY projeto) AS UM
ON PM.id_mobile = UM.projeto
LEFT JOIN (
SELECT
COUNT(id_uc_mobile) AS qtd_AMBIENTE,
id_uc_mobile
FROM ucs_mobile
LEFT JOIN (
SELECT
uc
FROM ambientes_mobile AS s
WHERE data_hora_importacao = '2015-05-15 17:21:02') AS G
ON G.uc = ucs_mobile.id_uc_mobile
WHERE data_hora_importacao = '2015-05-15 17:21:02') AS AM
ON UM.id_uc_mobile = AM.id_uc_mobile
WHERE PM.data_hora_importacao = '2015-05-15 17:21:02'
http://sqlfiddle.com/#!9/2eecf
here is a sqlfiddle if anyone want to try a solution. I have the specific hierarchy: projeto>uc>ambiente>secao>medicoes
ucs_mobile.projeto refers to projetos_mobile.id_mobile
ambientes_mobile.uc refers to ucs_mobile.id_uc_mobile
secoes_iluminacao_mobile.ambiente refers to ambientes_mobile.id_ambiente_mobile
I need a count of each child for the parent I pass, I will have 5 functions that
return the count of each child for a given parent, for example, for a projeto parent I should have count(ucs),count(ambientes),count(secoes),count(medicoes)
So, hope you guys can help me. The database is terrible ugly but that's is what I got. Appreciate any help.

When you have really large queries like this, it can often be helpful to break them down individually, starting from the ground up and patching them together.
I started by just getting the count of each ucs_mobile row for each projetos_mobile value. You can do that by joining the two tables on the related row, and using COUNT(DISTINCT um.id) to get the number of rows. There are other ways to do it, but this particular method will scale better for the rest of your query:
SELECT pm.id, COALESCE(COUNT(DISTINCT um.id), 0) AS qty_uc
FROM projetos_mobile pm
LEFT JOIN ucs_mobile um ON um.data_hora_importacao = '2015-05-15 17:21:02' AND um.projeto = pm.id_mobile
GROUP BY pm.id;
The COALESCE function will be used to fill 0 counts. As long as you remember to use the DISTINCT keyword, and group by the proper id, you can just add in the child rows like so:
SELECT
pm.id,
COALESCE(COUNT(DISTINCT um.id), 0) AS qty_uc,
COALESCE(COUNT(DISTINCT am.id), 0) AS qty_am,
COALESCE(COUNT(DISTINCT sim.id), 0) AS qty_sim
FROM projetos_mobile pm
LEFT JOIN ucs_mobile um ON um.data_hora_importacao = '2015-05-15 17:21:02' AND um.projeto = pm.id_mobile
LEFT JOIN ambientes_mobile am ON am.data_hora_importacao = um.data_hora_importacao AND am.uc = um.id_uc_mobile
LEFT JOIN secoes_iluminacao_mobile sim ON sim.data_hora_importacao = am.data_hora_importacao AND sim.ambiente = am.id_ambiente_mobile
GROUP BY pm.id;
Here is an SQL Fiddle example. NOTE I changed your sample data slightly to ensure my query was working as expected.
Also, a side note. I noticed as you went along that you kept using the same date in your WHERE clauses, so I just joined each table on the date as well, and made sure that in my very first join I looked for the date specified, which in turn will carry its way over to the other tables.

Related

SQL - select column inside different table if not null

I am trying to make a "recipe" system inside a game. The player can own a company and craft items in there.
I currently fetch the recipes per company type but I don't know how to write the query in a way that I can also fetch the item names and images if the item_id is not empty.
This is working:
SELECT a.recipe_id,
a.item1_id,
a.item1_uses,
a.item2_id,
a.item2_uses,
a.item3_id,
a.item3_uses,
a.item4_id,
a.item4_uses,
a.item5_id,
a.item5_uses,
a.newitem_id,
a.newitem_uses,
a.craft_description,
a.craft_button
FROM
company_recipes AS a,
company_types AS b
WHERE
a.type_id = b.type_id
AND
b.type_id = '".$type."';
"
A recipe can contain for example two items needed to craft something new, but it could also be 5. So if it's only 2, I only want to fetch the img, name of these 2 and the rest can be skipped.
I have a different table store_items that contains the img and name of the item. I was thinking something along the lines of an IF ELSE or CASE WHEN inside the query, but I'm not sure how I'd do that.
Something like: SELECT c.img, c.name FROM store_items AS c IF a.item1_id is not NULL.
I feel like I'm close to the solution, but missing the last step.
Thanks for the tips #jarlh, I've changed the code and came to this result. If you have any more tips to do it better I'm happy to listen. (I'm still a junior and thought myself by trial and error, so I might not have the best solutions at times... Which is why tips are highly appreciated).
SELECT cr.recipe_id,
cr.item1_id,
cr.item1_uses,
si1.name,
si1.img,
cr.item2_id,
cr.item2_uses,
si2.name,
si2.img,
cr.item3_id,
cr.item3_uses,
si3.name,
si3.img,
cr.item4_id,
cr.item4_uses,
si4.name,
si4.img,
cr.item5_id,
cr.item5_uses,
si5.name,
si5.img,
cr.newitem_id,
cr.newitem_uses,
si_new.name,
si_new.img,
cr.craft_description,
cr.craft_button
FROM
company_recipes AS cr
INNER JOIN company_types AS ct ON cr.type_id = ct.type_id
LEFT JOIN store_items AS si1 ON cr.item1_id = si1.item_id
LEFT JOIN store_items AS si2 ON cr.item2_id = si2.item_id
LEFT JOIN store_items AS si3 ON cr.item3_id = si3.item_id
LEFT JOIN store_items AS si4 ON cr.item4_id = si4.item_id
LEFT JOIN store_items AS si5 ON cr.item5_id = si5.item_id
LEFT JOIN store_items AS si_new ON cr.newitem_id = si_new.item_id
WHERE
ct.type_id = '".$type."';
I'm basically fetching everything now and handle the NULLs in the php code now.
Without seeing more info its had to see what you are trying achieve but you could start by using the the users inpute of the game to determine what data is first required before futher filtering. Try this:
Declare #Value int
set #Value = #User_input --- uses what ever the game user will
SELECT
a.recipe_id,
a.item1_id,
a.item1_uses,
a.item2_id,
a.item2_uses,
a.item3_id,
a.item3_uses,
a.item4_id,
a.item4_uses,
a.item5_id,
a.item5_uses,
a.newitem_id,
a.newitem_uses,
a.craft_description,
a.craft_button
--- you can insert more columns but i stopped here as i dont know what data you have in the other tables.
FROM
company_recipes a
INNER JOIN company_types b ON a.type_id = b.type_id
INNER JOIN store_items c ON c.type_id = b.type_id
WHERE
b.type_id = #Value; --- '".$type."';

Assistance with MySQL left outer join and differentiating query results from same key

I am trying to learn about SQL joins and trying to apply them to an application I am building. I am doing a query to find a "game record" on a schedule based on a specific game id. But on this game record; for the "h_team" and the "v_team"; only the ids of the teams are on the game record. And so what I want to do is join the "teams" table and look up the two different team_names of the "h_team" and "v_team". I have it also pull in a "division name" as well using a join since only the division id is stored on the game record. I have gotten this all to work fine; except I do not know how to get the results separately for the "team_name" for h_team and v_team. Basically the key for each one is just "team_name"; I will paste in my code and then explain further:
$array_game_id6=32;
$sql = "SELECT * FROM playoff_schedule LEFT OUTER JOIN teams on playoff_schedule.h_team = teams.team_id || playoff_schedule.v_team = teams.team_id LEFT OUTER JOIN playoff_divisions on playoff_schedule.po_div_id = playoff_divisions.po_div_id WHERE tom_game_id=$array_game_id6";
foreach ($dbh->query($sql) as $resultsg39)
{
$h_team=$resultsg39[h_team];
$v_team=$resultsg39[v_team];
$po_div_id=$resultsg39[po_div_id];
$round=$resultsg39[round];
$game_id=$resultsg39[game_id];
$date=$resultsg39[date];
$timestamp=$resultsg39[timestamp];
$h_score=$resultsg39[h_score];
$v_score=$resultsg39[v_score];
$tom_game_id=$resultsg39[tom_game_id];
$h_name=$resultsg39[team_name];
$div_name=$resultsg39[playoff_name];
}
the problem comes in when i am trying to get the results of the query and store them all in the different variables…
the last two "$h_name" and "$div_name" are being pulled from the JOINs all the prior ones are on the game record itself…
what I want to do is store both the names from "v_team" and "h_team" in the respective variables $h_name and $v_name;
I have it storing the $h_name no problem; but i do not know how to make it store both $h_name and $v_name separately as they are both values in the column "team_name" from "teams" table. So I just need to somehow make it so when i get my results it can tell the difference between the two different "team_names" and I can store them in the two different variables…
If this is not clear please let me know.
Thanks!
***** UPDATE 10:49pm EST 2/5/2015
have made some progress on this but my query is not working; I think it is a problem with the aliases and such are not right; here is my non-working query as it is right now:
$sth = $dbh->prepare("SELECT home_team.team_name as home_team_name, visiting_team.team_name as visiting_team_name,
h_team, v_team, po_div_id, round, game_id, date, timestamp, h_score, v_score, tom_game_id, playoff_name FROM playoff_schedule
LEFT OUTER JOIN teams as home_team on playoff_schedule.h_team = teams.team_id
LEFT OUTER JOIN teams as visiting_team on playoff_schedule.v_team = teams.team_id
LEFT OUTER JOIN playoff_divisions on playoff_schedule.po_div_id = playoff_divisions.po_div_id
WHERE tom_game_id=$array_game_id6");
$sth->execute();
$article_list = $sth->fetchAll(PDO::FETCH_ASSOC);
foreach ($article_list as $row => $link) {
$h_team=$link['h_team'];
$v_team=$link['v_team'];
$po_div_id=$link['po_div_id'];
$round=$link['round'];
}
if anyone can spot a problem with my new query I would really appreciate it!
I think what you are trying to do is:
select home_team.team_name as home_team_name,
visiting_team.team_name as visiting_team_name
from playoff_schedule
join team as home_team on playoff_schedule.h_team = teams.team_id
join team as visiting_team on playoff_schedule.v_team = teams.team_id
You can join to the same table as many times as you want to. In this case, it makes sense, because you really are trying to get two different bits of information.
Based on your last edit, the following query appears to work:
SELECT home_team.team_name AS home_team_name,
visiting_team.team_name AS visiting_team_name,
h_team,
v_team,
playoff_schedule.po_div_id,
round,
game_id,
date,
timestamp,
h_score,
v_score,
tom_game_id,
playoff_name
FROM playoff_schedule
LEFT OUTER JOIN teams AS home_team
ON playoff_schedule.h_team = home_team.team_id
LEFT OUTER JOIN teams AS visiting_team
ON playoff_schedule.v_team = visiting_team.team_id
LEFT OUTER JOIN playoff_divisions
ON playoff_schedule.po_div_id = playoff_divisions.po_div_id
WHERE tom_game_id=$array_game_id6
You can check the query and the schema at: SQLFiddle
A couple of thing that might be happening:
Is the query itself running?
What happens if you run the query in a mySQL client?
Are there any PHP errors in your log?
Could you post the schema itself?
Is $array_game_id6 actually an array of values? In that case, you need to use "in" as opposed to "=" in your where clause.
With regard to your updated query, I think the main thing you are missing is using the aliases in your JOIN conditions. You should keep your table aliases consistent throughout your query. Also, IMO its better to keep table aliases short so they are easier to read:
So applying those things to your query:
SELECT h.team_name as h_team_name, v.team_name as v_team_name, s.h_team, s.v_team, s.po_div_id, s.round, s.game_id, s.date, s.timestamp, s.h_score, s.v_score, s.tom_game_id, s.playoff_name
FROM playoff_schedule s
LEFT OUTER JOIN teams h ON (
s.h_team = h.team_id
)
LEFT OUTER JOIN teams as v ON (
s.v_team = v.team_id
)
LEFT OUTER JOIN playoff_divisions d ON (
s.po_div_id = d.po_div_id
)
WHERE s.tom_game_id = ?
Now I'm not 100% sure of your schema so I may have referenced some of the columns to the wrong table but you should be able to sort that out.

Better way to do this subquery

Let's say I have this query:
<?
$qi = $db->prepare('SELECT one.id, one.Value, two.Name, three.nfid, temp.Name AS Alias
FROM one
INNER JOIN two ON one.fid = two.id
LEFT OUTER JOIN three ON two.fid = three.fid
LEFT OUTER JOIN (SELECT id,Name FROM two) AS temp ON three.nfid = temp.id
WHERE one.rid = ?
ORDER BY one.id ASC');
$qi->execute( array( $id ) );
?>
Connections between the tables are:
Table one contains a number of rows with the fields one.Value, one.rid and one.fid.
fid is a connection to table two which contains the two.Name of the items (one.fid = two.id).
But sometimes the item is an alias for another item, which is why table three exists. It contains the fields three.fid and three.newfid where three.newfid = two.id (but for another item with another two.Name)
The query is supposed to fetch all rows from one with a certain one.rid and get one.Value, two.Name and if there is an three.fid for this one.fid, get two.Name for three.newfid and call it Alias.
Is there a way to improve this query or solve the problem in another way? Perhaps reshape the layout of the database? It is currently quite slow. The example here have been simplified to make it more general.
Thank you.
The subquery in parentheses forces MYSQL to ignore its indexes, which makes it take a long time. Better to directly join two as temp. As long as you always put two.[field] and temp.[field], it will tell them apart just fine.
SELECT one.id, one.Value, two.Name, three.nfid, temp.Name AS Alias
FROM one
INNER JOIN two ON one.fid = two.id
LEFT OUTER JOIN three ON two.fid = three.fid
LEFT OUTER JOIN two AS temp ON three.nfid = temp.id
WHERE one.rid = ?
ORDER BY one.id ASC

Mysql Join Won't Select

I have been doing a lots of research online and from my understanding i think my query is ok
That is why i need your help to point me out what im doing wrong.
What My Query Should Do
My query should fetch our stock level from both warehouse
Problem Is
if the product is not in both warehouse the query dont give any result.
Ok so first i have two database of warehouse stock level. that look like that.
Databases
-warehouse1
-warehouse2
Table
-product
Columns
-id
-SKU
-qty
So my Query is
SELECT
warehouse1.product.id as 1_id,
warehouse2.product.id as 2_id ,
warehouse1.product.SKU,
warehouse1.product.qty as 1_qty,
warehouse2.product.qty as 2_qty
FROM `warehouse1`.`product`
LEFT JOIN `warehouse2`.`product`
ON
(`warehouse1`.`product`.`SKU` = `warehouse2`.`product`.`SKU`)
WHERE
warehouse1.product.SKU = '$sku'
OR
warehouse2.product.SKU = '$sku'
ORDER BY
(1_qty + 2_qty) DESC
if i make the where clause like this
WHERE warehouse1.product.SKU = '$sku'
it is then working but i can't get stock from both warehouse.
What should i do if i want to receive the stock level from both warehouse even if there is no product that im asking for in this database.
Thanks
Try a FULL OUTER JOIN. You're using a LEFT JOIN. That requires that the DB fetch all records that match your WHERE clause on the LEFT side of the join, which is warehouse1, and any potentially matching records from warehouse2 (the right side of the join). If a SKU exists only in warehouse2, you don't see it.
Switching to a FULL OUTER JOIN forces the DB to fetch all matching records from BOTH sides of the join, regardless of which side(s) the matching records exist on.
you can also do this with a union
(SELECT
warehouse1.product.id as 1_id,
warehouse1.product.SKU,
warehouse1.product.qty as 1_qty
FROM `warehouse1`.`product`
WHERE
warehouse1.product.SKU = '$sku' )
union
(SELECT
warehouse2.product.id as 2_id ,
warehouse2.product.SKU,
warehouse2.product.qty as 2_qty
FROM `warehouse2`.`product`
WHERE warehouse2.product.SKU = '$sku' )
Combine your OR's in () (... OR ...):
SELECT
warehouse1.product.id as 1_id,
warehouse2.product.id as 2_id ,
warehouse1.product.SKU,
warehouse1.product.qty as 1_qty,
warehouse2.product.qty as 2_qty
FROM `warehouse1`.`product`
LEFT JOIN `warehouse2`.`product`
ON
(`warehouse1`.`product`.`SKU` = `warehouse2`.`product`.`SKU`)
WHERE (warehouse1.product.SKU = '$sku'
OR
warehouse2.product.SKU = '$sku')
ORDER BY
(1_qty + 2_qty) DESC

How do I echo out a name -only if- specific rows in one table match specific rows in another based on an id?

Here's my problem: I'm making a crafting system for a game, and I already have my database filled with information for resources required to craft items.
Here are what my relevant tables look like:
table #edible_resources
(edible_resource_id, edible_resource_name, hunger_points, degeneration_id)
table #edible_ground
(id, resource, amount, location)
table #req_crafting_edible
(req_crafting_edible_id, edible_resource_id, req_resource_amount, created_item_id)
table #items
(item_id, item_name, degeneration_id, is_grounded, is_stackable, can_equip, can_edit)
What I want to do is -only- echo out the craftable item's name if, and only if -all- required resources (and their required amounts) are on the ground in the location of the character.
I have a query that comes close:
SELECT items.item_name, items.item_id FROM items
INNER JOIN req_crafting_edible
ON req_crafting_edible.created_item_id = items.item_id
INNER JOIN edible_ground
ON edible_ground.resource = req_crafting_edible.edible_resource_id
AND edible_ground.amount >= req_crafting_edible.req_resource_amount
WHERE edible_ground.location = $current_location
GROUP BY items.item_name
ORDER BY items.item_name
But this shows me craftable items regardless if I have ALL the required items in the area. It shows me items as long as I have -one- of their required resources.
Is there a way to only show the name of a craftable item only if I have -all- the required resources (and their amounts) in edible_ground where location = $current_location?
For more information on what I've tried:
$get_char = mysql_query("SELECT current_char FROM accounts WHERE account_id ='".$_SESSION['user_id']."'");
$current_char = mysql_result($get_char, 0, 'current_char');
$get_loc = mysql_query("SELECT current_location FROM characters WHERE character_id = $current_char");
$current_location = mysql_result($get_loc, 0, 'current_location');
//---------------------------------------------------------------COOKED FOOD
$get_food = mysql_query("SELECT items.item_name, items.item_id FROM items
INNER JOIN req_crafting_edible
ON req_crafting_edible.created_item_id = items.item_id
INNER JOIN edible_ground
ON edible_ground.resource = req_crafting_edible.edible_resource_id
AND edible_ground.amount >= req_crafting_edible.req_resource_amount
WHERE edible_ground.location = $current_location
GROUP BY items.item_name
ORDER BY items.item_name");
while ($food = mysql_fetch_array($get_food)){
echo $food['item_name'].'<br>';
}
This returns:
Baked Fish
Charred Fish
Fish Soup
Glazed Berry
Cake
Grilled Fish
Sashimi
Seafood Soup
Sushi
Udon
On the ground:
1 fish
1 honey
Even though fish soup, berry cake, udon etc needs much more than just the one fish that's in the area.
Can anyone help me figure this out? I'd be forever grateful; I've spent a few days already trying to myself. Please?
And before anyone says anything, I know I need to start using mysqli; unfortunately I didn't even realize it existed when I started to make the game (and learn PHP at the same time months ago), so I'll have to painfully go back and change it all in an update.
You want a HAVING clause to check the count of the records you are grouping through the INNER JOINs.
HAVING count(*) = (
SELECT count(*)
FROM req_crafting_edible
WHERE req_crafting_edible.created_item_id = items.item_id
)
Edit:
So basically you need to know two pieces of information:
How many different resources are required
Do each of those resources have the required amounts
The first is solved by the sub query above.
Your query as-is satisfies the second point but only for 1 resource.
HAVING basically does some special magic on your group clause. HAVING count(*) means there are X records being grouped together. Because of how the join works, you will have 1 item.name for each resource. The sub select gives you the count of how many different resources, and therefore grouped records, are needed for that item. Comparing that sub query with the count(*) of the grouping ensures you have all the needed resources.
And here is the final query, modifying your code above:
SELECT items.item_name, items.item_id
FROM items
INNER JOIN req_crafting_edible
ON req_crafting_edible.created_item_id = items.item_id
INNER JOIN edible_ground
ON edible_ground.resource = req_crafting_edible.edible_resource_id
AND edible_ground.amount >= req_crafting_edible.req_resource_amount
WHERE edible_ground.location = $current_location
GROUP BY items.item_name
HAVING count(*) = (
SELECT count(*)
FROM req_crafting_edible
WHERE req_crafting_edible.created_item_id = items.item_id
)
ORDER BY items.item_name
You only actually want the data from the items table, right? If so I would move to using an exists model:
SELECT I.item_name, I.item_id FROM items I
WHERE NOT EXISTS
(SELECT created_item_id
FROM req_crafting_edible R
WHERE R.created_item_id = I.item_id
AND NOT EXISTS
(SELECT G.resource
FROM edible_ground G
WHERE G.resource = R.edible_resource_id
AND edible_ground.location = $current_location
AND G.amount >= R.req_resource_amount))
ORDER BY I.item_name
I don't have your database to check this, but the logic goes like this:
Find the items that don't have any unsatisfied requirements.
Find the unsatisfied requirements for the current item. (IE. Find
requirements that don't have resources on the ground)
Find the edible resources that match the current requirement, are at
this location, and have enough.
I don't work in mysql as much at the moment, but let me know if this doesn't work.

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