how to get information from a link in php [closed] - php

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If give you a link like http://login.php?workerid=abc,
how can we get the information of workerid in php? Thanks.
Maybe $_GET function, but do not know exactly how to make that work.

you can get information from url like this
$data=$_GET['workerid'];

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Determine source of code that is making a query [closed]

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Exist any way to know the source page that is calling the query and store it?
Are you looking for $_SERVER['PHP_SELF'] ?
Check also print_r($_SERVER) if something is more accurate for what you need

Pass a URL as a get parameter in php [closed]

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http://example.com/geturl.php?url=http://example.org/index.php?parafile=1698%3A1562%3A0%3A0&para_action=print_ticket&parafile=dance://here.kodas/print&token=3ec2b0d3e6e0ca152bc024cc3f30f16c
So i want each of this parameters in a different varaible in the geturl.php file. I am using the regular get url
You can use anything like this :
$url = "http://example.com/geturl.php?url=".urlencode($urlPart);
$_server[QUERY_STRING] solved my problem

How can i change the url in the udropship [closed]

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I have this magento website, http://www.sample.com/udropship, want to change to http://udropship.sample.com
Please anybody who can help with this should please provide an answer.
This has nothing to do at all with php, mysql, css nor ajax. This a matter of DNS-setup. You should start at your DNS service, which is most probably also your webhost in your case.

If Current Domain is X, Then Include [closed]

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I'm trying to use some basic code to include a file if the current domain is http://example.com
How do I do this?
if (...){
include("../clicky.php");
}
$_SERVER can help in many ways
if($_SERVER['HTTP_HOST']=="example.com")
{
include("whatever");
}

Is there a way to have my webpage automatically load a preselected page once a certain php function is complete [closed]

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Essentially the title, please keep it simple, im not accustom with code.
You can use header('Location:yourpage.php') at the end of your function.
Header

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