php array multidimensional search for bad words - php

Question

im trying to search in an array for badwords.
my array looks like:
Array
(
[base] => 2312783821823912
[charset] => utf-8
[Product] => Samsung PD291 Printer
[meta] => Array
(
[description] => fucking nice Printer
[keywords] =>
)
[n2] => Array
(
[w1] => Array
(
[0] => printer
)
[w2] => Array
(
[0] => Menu
[1] => Main menu
[2] => Social
[3] => Speakers
[4] => 2015
[5] => Highlight
[6] => And... Action!
[7] => Short
[8] => Platin
[9] => Gold
[10] => Silber
[11] => Bronze
[12] => partner
)
)
}
I have an badword array like: $bad = array("fuck", "....);
Now im little bit confused what would be the fastest way to scan all values of the first array and return true or false if it contains badwords?
any advice would help ;-)
Thanks!
//edit:
Thanks # everybody...
I will use:
class BadWordFilter {
private static $bad = "/fuck|ass/i";
public static function hasBadWords($input) {
foreach ($input as $element) {
if (is_array($element)) {
if (self::hasBadWords($element)) {
return true;
}
} else {
if (preg_match(self::$bad, $element)) {
return true;
}
}
}
return false;
}
}
I have tested it, and it will be the fastest solutions for my problem ;-))
Thanks everybody

Answer 1

I think the fastest way is to json_encode the array and scan the json string for the bad words.
Not tested but something like this should work:
function badWordsExists($input_array, $blacklist){
$jsonstring = json_encode($input_array);
foreach($blacklist as $string) {
if(strpos($jsonstring, $string) !== false) {
return true;
}
}
return false;
}
Using regex should be faster but this is just an example to give you a idea how it may work.

Answer 2

You can do it with a recursive search which ends its task when a bad word is found. Note, that converting it to json is sub-optimal, since you convert it into a string and then try to find the bad words in the string. It is time-consuming, especially if you have many arrays to check for bad words.
public class BadWordFilter {
private static $bad = array(); //use your array instead
public static function hasBadWords($input) {
foreach ($element in $input) {
if (is_array($element)) {
if (self::hasBadWords($element)) {
return true;
}
} else {
foreach ($bad as $badWord) {
if(strpos($element, $badWord) !== false) {
return true;
}
}
}
}
return false;
}
}

Answer 3

A recursive function is the answer here. The below code will detect any string in at any element of a given array.
<?php
function containsWord($haystack, $badWord)
{
foreach ($haystack as $index => $item) {
if (is_array($item)) {
containsWord($item, $badWord);
} else {
if (strpos($item, $badWord) !== false) {
echo "'$badWord' has been detected in '$item' at index '$index'";
return true;
}
}
}
echo "$badWord is not in the array";
return false;
}
$array = [1 => [4=> 'badword', 5=> 'qw'], 2 => 'b', 3 => 'c'];
containsWord($array, 'bad');
The output of the above code will be:
'bad' has been detected in 'badword' at index '4'
Hope this helps :)