When I try to use this structure:
<form name="confirm" method="get" accept-charset="utf-8" enctype="multipart/form-data" action="confirm_sent.php?name=<?PHP echo $name; ?>">
...........//sth doing at here
<input type="submit" class="popUpButton" name="confirmButton" id="submitPage4" value="Confirm" />
The name was get from the URL:
http://localhost/reserve/app/confirm.php?name=$name
But, when I click the button confirmButton it will directly to confirm_sent.php
but at the URL there the value of name does not show out only show this:
http://localhost/reserve/app/confirm_sent.php?confirmButton=Confirm
So, I would like to ask that it is my concept wrong or did I do it the wrong way?
Thanks for the help / advice... :)
Sorry for any inconvenience.
If you use method="GET", you can't put parameters in the action URL. You should use a hidden input field instead:
<form name="confirm" method="get" accept-charset="utf-8" action="confirm_sent.php">
<input type="hidden" name="name" value="?PHP echo $name; ?>">
But if you need to use multipart/form-data, because you have a file input, you can't use method="GET", you have to use method="POST". In that case, you can either have the parameter in the URL or in a hidden field.
<form name="confirm" method="post" accept-charset="utf-8" enctype="multipart/form-data" action="confirm_sent.php?name=<?PHP echo $name; ?>">
The name parameter will be in $_GET['name'], all the other inputs will be in $_POST (except the file inputs will be in $_FILES).
Related
I'll try and explain this as best as I can. Basically, I'm using a form to receive a comment. Upon hitting submit, the action creates a link similar to this: http://localhost:8080/camagru/comment.php?comment=test&post=Post
I have a variable with the image name in it that I want to pass as well, so something like this: http://localhost:8080/camagru/comment.php?img=test.png&comment=test&post=Post
I've tried using <form action="<?php echo commentpost.php?img=$img?>"> But everytime the submit button is pressed, it erases the img variable from POST and only puts in the new variables from the form.
Any suggestions?
add new hidden field in form tag like that
<form action="commentpost.php" method="post">
<input type="hidden" value="<?php echo $img ?>" name="img" />
<input type="submit" value="Save" name="IsSubmit" />
</form>
Now you can able to use $_POST['img']
The img variable is in GET.
If you want it in POST, try <input type="hidden" name="img" value="test.png">
use quotes in your case:
<form action="<?php echo "commentpost.php?img=$img"; ?>">
the best practice is to insert hidden element into your form:
<input name="img1" type="hidden" value="test.png" />
<input name="img2" type="hidden" value="test2.png" />
I have a simple registration form.
I want to pass value entered in one page to other in a text field.
how to pass and access it from next page in php.
this is my first php page.
Thanks in advance.
You can add hidden fields within HTML and access them in PHP:
<input type="hidden" name="myFieldName" value="someValue"/>
Then in PHP:
$val = $_POST['myFieldName'];
If you're going to ouput this again you should use htmlspecialchars or something similar to prevent injection attacks.
<input type="hidden" name="myFieldName" value="<?=htmlspecialchars($_POST['myFieldName']);?>"/>
Suppose this the form input in page A
<form name="" action="" method=post enctype="multipart/form-data">
<input type="text" name="myvalue" value="">
<input type=submit>
</form>
In page B
In the page you want to get values put this code
<?PHP
foreach ($_REQUEST as $key => $value ) {
$$key=(stripslashes($value));
}
?>
<form name="" action="" method=post enctype="multipart/form-data">
<input type="text" name="myvalue" value="<?PHP echo $myvalue" ?>">
<input type=submit>
</form>
So yo can use or attach variable value to another form do what else you want to do
use following code, that should help you.
<form action ="formhandler.php" method ="POST" >
<input name = "inputfield" />
<input type="submit" />
</form>
on formhandler.php file yo need to enter following code to get the value of inputfiled.
$inputfield = isset($_POST['inputfield'])?$_POST['inputfield']:"";
// now you can do what ever you want with $inputfield value
echo($inputfield);
I have the following form in my form.php file:
<form action="operation.php?part=dictionary&operation=<?php echo (($_GET['action']=='addword')?'save':'edit&id='.$_GET['id'])?>" method="get">
.....
....
</form>
And in my operation.php file:
if($_GET['operation']=='save'){
echo "This is true";
}else{
die(mysql_error());
}
And it shows the message that it does not recognize the operation parameter.
So if anyone have any idea of how to distinguish the operation between save and edit would be really appreciated. Thanks you
You can try using:
<form action="operation.php" method="get">
<input type="hidden" name="part" value="dictionary">
<input type="hidden" name="operation" value="<?php echo (($_GET['action']=='addword')?'save':'edit&id='.$_GET['id'])?>">
</form>
Setting a form's method to "GET" results in ignoring all GET-parameter added to the action of the form. In order to get those parameter to work you will have to add them as hidden input fields otherwise you switch your form's method to "POST". This results in setting POST-parameter according to form fields and setting GET-parameter according to the link additions made at form's action.
You need to use hidden parameters to submit values to your form, like so:
<form action="operation.php" method="GET">
<input type="hidden" name="part" value="dictionary" />
<input type="hidden" name="operation" value="<?php echo (($_GET['action']=='addword')?'save':'edit&id='.$_GET['id'])?>" />
</form>
in order to edit my entries i want to:
<form id="pregunta" name="pregunta" class="form_pregunta" method="post" action="pregunta.php?id=26">
<h2>Titulo de la pregunta</h2><input name="q" id="q" class="q" value="este es mi tÃtiulo " type="text">
<h2>Describe tu pregunta</h2>
<textarea name="texto" id="texto" style="width: 98%;"><p>esta es mi descripcion</p></textarea>
<h2>Etiquetas</h2>
<input name="tags" id="tags" onmouseover="mostrar_tooltip('nube_e','','0','70','')" onmouseout="ocultar_tooltip('nube_e')" value="dos,tres,una,">
<input name="responde_a" style="display: none;" id="responde_a" value="0">
<button name="pregunta" id="pregunta" type="submit">form_edit_question_button</button>
</form>
And then in file.php
i'd like to $_get['id'] and $_post['inputs']
but when i go:
if(isset($_POST['edit_pregunta'])){
echo 'lalalalalalalalalalalalalalala';
post_edit_pregunta();
}
it won't ever enter :S. is that normal or i'm missing something... i wanted not to have a hidden input with the id of the post i want to edit..
I'm not 100% sure, but forms don't send their name when submitted, much less their id.
You could do the following instead:
<form id="edit_pregunta" method="post" action="file.php?id='$this->id'">
<input type="hidden" name="edit_pregunta" value="anything">
... //inputs here
</form>
and your if should now enter.
It looks like you're checking for your form's "id" attribute. This is not sent when the form is submitted, only values in <input>, <select>, <textarea> and <button> are sent.
You should check for one of those.
Edit: Your button name is "pregunta", so that is the POST variable you should be checking for, eg
if(isset($_POST['pregunta'])){
Just to comment in general on mixing params in the form's "action" and inputs, you can mix them as long as the form method is "post". You cannot set GET params in the form's action and use the "get" method
<!-- Good -->
<form action="proc.php?id=123" method="post">
<input name="foo" value="foo">
<input type="submit">
</form>
<!-- Bad -->
<form action="proc.php?id=123" method="get">
<input name="foo" value="foo">
<input type="submit">
</form>
There should be no problem at all with having get and post variables in the same request, but are you sure your syntax is correct? If this is normal php, shouldn't you write
<form id="edit_pregunta" method="post" action="file.php?id=<?php echo $this->id; ?>">
... //inputs here
</form>
[Edit]
The problem is (if I'm correct and this is standard php) that you generate a form that looks something like this:
<form id="edit_pregunta" method="post" action="file.php?id='$this->id'">
... //inputs here
</form>
This will make id look like this: '$this->id' (including the '-signs). When what you want is something like this:
<form id="edit_pregunta" method="post" action="file.php?id=51">
... //inputs here
</form>
Then $_GET['id'] would be 51.
[Edit2]
Also, I think you need to change
if(isset($_POST['edit_pregunta'])){
with
if(isset($_POST['pregunta'])){
If I'm not mistaken the name of a form doesn't get sent to the server, however, the name of the submit-button does, but I might be wrong about that part.
Yes you can, I've done it several times.
Probably something else is wrong with your code.
Is there any control with name="edit_pregunta" or is it just the id of the form? IDs are not sent to the server.
Simply adding the id to the form will not create the $_POST['edit_pregunta'] you verify.
Instead, inside the form tag, add an <input name="foo" />; in the php script verify $_POST['foo']
While the HTTP spec doesn't disallow query parameters in POST methods, it is somewhat unusual. You'd be better off using a hidden input field in the form to pass any non-user values up to the script.
That said, the syntax for your form is wrong. You need to use "echo" to insert the value of $this->id into the action.
Use input type="submit" in place of button tag.
You need name for form submission and activate php script!
HTML Code:
<form action="change.php" method="POST">
<input type="password" name="p1" class="change_text" placeholder="New Password"/></br>
<input type="password" name="p2" class="change_text" placeholder="Re-Password"/></br>
<input type="submit" name="change" value="Change Password" id="change" />
</form>
PHP Code:
<?php
if (isset($_POST['change']) {
$p1=$_POST['p1'];
}
?>
Can i send a input value into form action ?Let say, on the form the phone number taken.Now can i send the phone number as form action parameter "number"? Is their any way to send it?
<form method="post" action="abc.php?number=ph_number" enctype="multipart/form-data">
<input type="text" name="ph_number" value=""/>
<input type="submit" name="search" value="SEND"/>
</form>
How can i do it?
Thanks in advance
riad
<form method="GET" action="abc.php" enctype="multipart/form-data">
<input type="text" name="number" value=""/>
<input type="submit" name="search" value="SEND"/>
</form>
Change action="abc.php?number=ph_number" to action="abc.php
Change name="ph_number" to name="number"
When you click submit, the value contained in "number" text field will be passed to abc.php.
Receive the value with $value = $_REQUEST['number']; in abc.php.
You can leave an empty action, and use the onSubmit event to load a javascript function that does whatever and redirects to the page according to the input value.
Html
<form .. action="" onsubmit="return abcByPhone(this);">
Javascript
function abcByPhone(form) {
url = from.number.value;
...
}
EDIT:
I actually didn't read the question properly. I thought you wanted to redirect to different pages according to the input. Using plain GET (like the others mentioned) is fine for this.