Display array values in a table - php

Question

I have the following code, which currently displays the array values in resArr and resArr2 separately. I would like to display this data in a table, showing the value of array resArr in column 1 and the value of resArr2 in column 2. I have tried experimenting with tr and td however for some reason this has no effect on the output.
Could anyone provide me with any possible solution please?
$resArr = json_decode($res, 1);
$resArr2 = json_decode($res2, 1);
foreach ($resArr as $key => $value)
{
echo "<tr>";
if(!is_array($value))
{
if($key == 'attire' or $key == 'category' or $key == 'location' or $key == 'name' or $key == 'website' or $key == 'checkins' or $key == 'likes')
{
echo "<td>";
echo $key . ':' . $value;
echo "<br />\n";
echo "</td>";
}
}
echo "</tr>";
}
foreach ($resArr2 as $key => $value)
{
//to eliminate array to string conversion error
if(!is_array($value))
{
if($key == 'attire' or $key == 'category' or $key == 'location' or $key == 'name' or $key == 'website' or $key == 'checkins' or $key == 'likes')
{
echo $key . ':' . $value;
echo "<br />\n";
}
}
}

Answer 1

I belive you want something like this:
$resArr = json_decode($res, 1);
$resArr2 = json_decode($res2, 1);
$labels = array('attire','category','location','name','website','checkins','likes');
$count1=0;
echo '<table border="1">';
echo '<tr><th>key</th><th>resArrLabel</th><th>resArr2Label</th></tr>';
foreach ($labels as $label)
{
echo '<tr>';
echo '<th>'.$label.'</th>';
echo '<td>'.(array_key_exists($label, $resArr) ? $resArr[$label] : '').'</td>';
echo '<td>'.(array_key_exists($label, $resArr2) ? $resArr2[$label] : '').'</td>';
echo '</tr>';
}
echo '</table>';
It was much faster becouse use only one loop and add th label to each column and row. Try to add more css style.

Answer 2

You have to iterate both arrays at the same time. Try this
$resArr = json_decode($res, 1);
$resArr2 = json_decode($res2, 1);
$count1=0;
echo "<table border='1'>";
foreach ($resArr as $key => $value)
{
echo "<tr>";
if(!is_array($value))
{
if($key == 'attire' or $key == 'category' or $key == 'location' or $key == 'name' or $key == 'website' or $key == 'checkins' or $key == 'likes')
{
echo "<td>";
echo $key . ':' . $value;
echo "<br />\n";
echo "</td>";
}
}
$count2=0;
foreach ($resArr2 as $key => $value)
{
if($count1==$count2){
//to eliminate array to string conversion error
if(!is_array($value))
{
if($key == 'attire' or $key == 'category' or $key == 'location' or $key == 'name' or $key == 'website' or $key == 'checkins' or $key == 'likes')
{
echo "<td>";
echo $key . ':' . $value;
echo "<br />\n";
echo "</td>";
}
}
}
$count2++;
}
echo "</tr>";
$count1++;
}
echo "</table>";

Answer 3

Look at the results displayed for me. I am using sample array.
$resArr = array('attire'=>'1','category'=>'2','location'=>'3');
$resArr2 = array('attire'=>'a','category'=>'b','location'=>'c');
echo "<table border='1'>";
$count1=0;
foreach ($resArr as $key => $value)
{
echo "<tr>";
if(!is_array($value))
{
if($key == 'attire' or $key == 'category' or $key == 'location' or $key == 'name' or $key == 'website' or $key == 'checkins' or $key == 'likes')
{
echo "<td>";
echo $key . ':' . $value;
echo "<br />\n";
echo "</td>";
}
}
$count2=0;
foreach ($resArr2 as $key => $value)
{
if($count1==$count2){
//to eliminate array to string conversion error
if(!is_array($value))
{
if($key == 'attire' or $key == 'category' or $key == 'location' or $key == 'name' or $key == 'website' or $key == 'checkins' or $key == 'likes')
{
echo "<td>";
echo $key . ':' . $value;
echo "<br />\n";
echo "</td>";
}
}
}
$count2++;
}
echo "</tr>";
$count1++;
}
echo "</table>";