Parse Error on isset? [PHP] - php

Question

I'm quite new to HTTP/PHP coding and I'm having a little trouble with isset in PHP.
This is my current code below, it's supposed to check if the username and password is Admin and Password, if so, it will echo them some info.
However, it doesn't work. There is no errors, it just accepts all usernames and passwords.
$username = isset($_POST['password']);
$password = isset($_POST['username']);
$date = date('d-m-y');
$time = date('h:m:s');
$day = date('l');
if($username == 'Admin' and $password == 'Password')
{ //echo bla bla bla..

Answer 1

isset just checks if a variable is set. Your usercase, on the otherhand, needs to check the actual values:
if(isset($_POST['username']) and
$_POST['username'] == 'Admin' and
isset($_POST['password']) and
$_POST['password'] == 'Password') {
// echo...
In order to use isset() being passed in your variable(s) as you have it now, you need to use a ternary operator.
I.e.:
$username = isset($_POST['password']) ? $_POST['password'] : "default";
Consult Example #3 and others on
http://php.net/manual/en/language.operators.comparison.php

Answer 2

You can read the use isset in php isset , where it appears that isset has a value of true or false . so the value of the variable $username be true or false , so also in the variable $password. So if you will check value of the POST action you can use
if(isset($_POST['username']) && isset($_POST['password'])){
$username = $_POST['username'];
$password = $_POST['password'];
$date = date('d-m-y');
$time = date('h:m:s');
$day = date('l');
if($username == "Admin" && $password == "Password")
{ //echo bla bla bla..
}
}

Answer 3

try this,
if(isset($_POST['password']) && isset($_POST['username'])){
$username = $_POST['password'];
$password = $_POST['username'];
$date = date('d-m-y');
$time = date('h:m:s');
$day = date('l');
// code here
if($username == 'Admin' and $password == 'Password'){
// Okay
}else{
// not Okay
}
} else {
// error
}