creating an array from database - php

Question

I'm using a array to get a range between 1011-2371 but I'didnt need all digits. It's a long list thats why I import the CSV to the database.
I want to create a array from a database table.
But I can't get it.
Here's a rough mockup of the old php:
<form method="post" action="<?php echo $_SERVER['PHP_SELF']?>">
<input type="text" placeholder="1234AB" name="postcode" />
<input type="submit" value="verstuur" />
</form>
<?php
if($_SERVER['REQUEST_METHOD'] == "POST") {
$postcode = range(1011,2371);
if(preg_match('/^[1-9][0-9]{3} ?[a-zA-Z]{2}$/', $_POST['postcode'])) {
if(in_array($_POST['postcode'],$postcode)) {
echo 'FreshFoods is beschikbaar bij jou in de buurt.';
} else {
echo 'FreshFoods is nog niet beschikbaar bij u in de buurt.';
}
} else {
echo 'Voer 4 cijfers en 2 letters in als postcode. Voorbeeld 1234AB';
}
}
?>
and this is what I try do get the array from the database:
<form method="post" action="<?php echo $_SERVER['PHP_SELF']?>">
<input type="text" placeholder="1234AB" name="postcode" />
<input type="submit" value="verstuur" />
</form>
<?php
require_once 'db_config.php';
if($_SERVER['REQUEST_METHOD'] == "POST") {
$postcode = array();
$result = mysql_query("SELECT postcode FROM postcode_check");
if(preg_match('/^[1-9][0-9]{3} ?[a-zA-Z]{2}$/', $_POST['postcode'])) {
if(in_array($_POST['postcode'],$postcode)) {
echo 'FreshFoods is beschikbaar bij jou in de buurt.';
} else {
echo 'FreshFoods is nog niet beschikbaar bij u in de buurt.';
}
} else {
echo 'Voer 4 cijfers en 2 letters in als postcode. Voorbeeld 1234AB';
}
}
?>
the db_config.php file looks like:
<?php
$db = array (
'host' => 'localhost',
'user' => 'root',
'pass' => 'root',
'dbname' => 'testzip'
);
if(!mysql_connect($db['host'], $db['user'], $db['pass']))
{
trigger_error('Fout bij verbinden: '.mysql_error());
}
elseif(!mysql_select_db($db['dbname']))
{
trigger_error('Fout bij selecteren database: '.mysql_error());
}
else
{
$sql = "SET SESSION sql_mode = 'ANSI,ONLY_FULL_GROUP_BY'";
if(!mysql_query($sql))
{
trigger_error('MySQL in ANSI niet mogelijk');
}
}
?>

Answer 1

you have to use mysql_fetch_array or mysql_fetch_assoc to fetch the result from database.
<form method="post" action="<?php echo $_SERVER['PHP_SELF']?>">
<input type="text" placeholder="1234AB" name="postcode" />
<input type="submit" value="verstuur" />
</form>
<?php
require_once 'db_config.php';
if($_SERVER['REQUEST_METHOD'] == "POST") {
$postcode = array();
$result = mysql_query("SELECT postcode FROM postcode_check");
while ($row = mysql_fetch_array($result)) {
$postcode[] = $row['postcode'];
}
if(preg_match('/^[1-9][0-9]{3} ?[a-zA-Z]{2}$/', $_POST['postcode'])) {
if(in_array($_POST['postcode'],$postcode)) {
echo 'FreshFoods is beschikbaar bij jou in de buurt.';
} else {
echo 'FreshFoods is nog niet beschikbaar bij u in de buurt.';
}
} else {
echo 'Voer 4 cijfers en 2 letters in als postcode. Voorbeeld 1234AB';
}
}
?>
Try this code.

Answer 2

You need to fetch the result. Your regex will never match your sample data from the db though so you will always get the nog niet message. or voorbeeld. Never 'FreshFoods is beschikbaar bij jou in de buurt'
<form method="post" action="<?php echo $_SERVER['PHP_SELF']?>">
<input type="text" placeholder="1234AB" name="postcode" />
<input type="submit" value="verstuur" />
</form>
<?php
require_once 'db_config.php';
if($_SERVER['REQUEST_METHOD'] == "POST") {
$postcode = array();
$result = mysql_query("SELECT postcode FROM postcode_check");
while($row = mysql_fetch_assoc($result)){
$postcode[] = $row['postcode'];
}
if(preg_match('/^[1-9][0-9]{3} ?[a-zA-Z]{2}$/', $_POST['postcode'])) {
if(in_array($_POST['postcode'],$postcode)) {
echo 'FreshFoods is beschikbaar bij jou in de buurt.';
} else {
echo 'FreshFoods is nog niet beschikbaar bij u in de buurt.';
}
} else {
echo 'Voer 4 cijfers en 2 letters in als postcode. Voorbeeld 1234AB';
}
}
?>