Am I using mysqli_fetch_row() the right way ??
I know the customer name and I wanna find out the Env_lines value in that same record. There is only one record with that customer name. I'm not getting an output when i do echo $env_lines. What might be the problem?
<?php require_once("config.php") ?>
<?php require_once("functions.php") ?>
test
<?php
$customer = 'Bickery';
echo ' <br> 1)'.$customer;
$sql_customer = "SELECT * FROM `Customer` WHERE Cust_Name = '$customer' LIMIT 0,1";
echo ' <br> 2)'.$sql_customer,'<br>';
$customer_selection = mysqli_query($conn,$sql_customer);
var_dump($customer_selection);
$customer_row = mysqli_fetch_row($conn, $customer_selection);
$env_lines = $customer_row["Env_Lines"];
echo ' <br> 3)'.$env_lines;
?>
https://gist.github.com/anonymous/520319ac72e7f08419c4
Manual Says
mixed mysqli_fetch_row ( mysqli_result $result )
Does that show anywhere that you need to give it your connection reference? No
Remove your first parameter from here
$customer_row = mysqli_fetch_row($conn, $customer_selection);
^
Then
Fetches one row of data from the result set and returns it as an enumerated array, where each column is stored in an array offset starting from 0 (zero). Each subsequent call to this function will return the next row within the result set, or NULL if there are no more rows
That means this is not the right function to fetch an associative array, mysqli_fetch_assoc is (amongst others).
$customer_row = mysqli_fetch_assoc($customer_selection);
And oh, PHP guys on SO think this is our duty; here it goes
How can I prevent SQL injection in PHP?
Related
I have some problems here.
I tried fetching a data from column(which datatype is float) with the highest number and displays it. But it only shows the count of row(which is 1)
how to I get the exact 'Number' that I need?
PHP
<?php
$sql= mysqli_query($con, "SELECT MAX(payment_price) FROM client_record WHERE payment_status ='Settled'");
$row = (int)mysqli_fetch_array($sql);
echo $row;
?>
What it shows:
1
What I need to see:
//the exact price that MAX() fetched
20,000
As function you use, has a name mysqli_fetch_array, this means that result of this function is array. Casting array type to int type doesn't do what you expect.
Instead, what you need to use is just:
$row = mysqli_fetch_array($sql);
print_r($row);
// what you need is something like
echo $row['MAX(payment_price)'];
Try the following:
<?php
$sql= mysqli_query($con, "SELECT MAX(payment_price) as max FROM client_record WHERE payment_status ='Settled'");
$row = mysqli_fetch_array($sql);
echo $row['max'];
When you convert an array into an int it only converts it as a boolean value. Not the value of the array. So, use the index 'max' to get the value you want, as you can see I edited the MySql query to add as max it will provide the value for 'max'.
i'm still new towards php but after searching through multiple topics i can't seem to figure this one out.
$query2 = "SELECT COUNT(MAP_CODE2) FROM TCODE_MAPPING WHERE MAP_CODE2 = 'ABC123'";
$result2 = odbc_exec($connect,$query2);
echo $result2;
i have a query above that i'd like to use to get the total number of rows within the query that i've set, however for some reason i keep getting hit by the error
Array to string conversion in /var/www/html/xxx.php on line 85
Would highly appreciate if anyone could help out on what i'm doing wrong. Thank you!
Problem is:-
You are trying to echo a result-set object of array type.
Solution (check the code comments):-
$query2 = "SELECT COUNT(MAP_CODE2) AS MYCOUNT FROM TCODE_MAPPING WHERE MAP_CODE2 = 'ABC123'"; // given a name to the count
$result2 = odbc_exec($connect,$query2); //prepare and execute query
while (odbc_fetch_row($result2)) { //iterate over result-set object
echo odbc_result($result, "MYCOUNT"), "\n"; // echo count
}
What is happening here is you are echoing an array object type that is also a resource type and php echo only string and other primitive type variables.
so you need to use a loop to access the row or to get row count and access row just use a foreach($results as $result)
to get row count visit this sqlsrv-num-rows . on this official php link you can get more example how to fetch data.
When I'm trying to get the number of rows on a SQL request and if not, the connection that follow fails.
But in any case (also if the request should return 0), it returns 1.
Here's my code :
$str = 'SELECT count(*) FROM admins WHERE mail = ? AND mdp = ?';
$arr = array($mail, $pass);
$rqt = sendRqt($str, $arr);
$tab = $rqt->fetchColumn();
$cnt = count($tab);
echo $cnt;
I don't understand why there's no time it returns 0
The problem is the use of the php function count().
You already have the correct number in your $tab variable as a string (probably, depends on php configuration / version) so you can echo it or cast it to an integer to make sure it is a number.
However, in php:
count(0) === 1
count('0') === 1
See here for example.
You should remove count($tab).
the SQL "COUNT(*)" allways returns a row with the count (quantity) of values, so if you apply the php count() function, always will return 1 because there is one row that contains the value of the COUNT sql function
I believe COUNT() needs a column name.WRONG!! count(*) should count all rows, but I still reccomend a column name like id or something. You could also use an AS to make life a little easier
$str = 'SELECT count(`COLUMNNAME`) AS cnt FROM table WHERE ....
For an application I'm trying to count the total of friends. I want to do this with a function but it isn't returning anything. It tells me this:
Warning: mysqli_query() expects at least 2 parameters, 1 given
But I only need one parameter. I think I'm totally wrong.
This is the function:
public function GetTotalOfFriends($user_id){
$db = new Db();
$select = "SELECT COUNT FROM friendship WHERE (friendship_recipient_id ='" . $user_id ."' OR friendship_applicant_id = '" . $user_id . "') AND friendship_status = 'accepted'";
$result = $db->conn->query($select);
$row = mysqli_query($result);
$total = $row[0];
echo $total;
I'm trying to print it out in this way:
$friend = new Friendship;
$numberoffriends = $friend->GetTotalOfFriends($user_id);
<?php echo $numberoffriends; ?>
You are mixing up a couple of things. The line $result = $db->conn->query($select); already seems to execute a query, but then you try to bypass your database wrapper by passing that query result again to mysqli_query.
Apart from that, I think your query itself is also wrong. COUNT needs a parameter, indicating a field or value to count. Quite often COUNT(*) is used, but COUNT('x') might be more efficient in some cases. You can also use a specific field name, and COUNT will count the non-null values for you.
The result you got is a mysql_result object, which you need to use to get to the actual data of the query result.
The documentation of this object is here and I suggest that you read it thoroughly.
One possible way to do this is using this:
$resultArray = $result->fetch_row();
This will result in the first (and only) row of your query. It is represented as an array, with one value (since your query returns only one column). You can fetch that value like this:
return $resultArray[0];
You could also use any of the other fetch methods if you want your data in a different fashion.
I have been working on this for a while now, I know it's simpler than what I am making it, but I just can't get it. I have some code where I am trying to query an enum either 1 or 0 from my table so this is exactly what I have to do this.
$username = 'test'
$passResult = mysql_query("SELECT usrSetPass FROM members WHERE usr='.$username.'");
Now I have all the connection stuff down I think, I get no errors there, but when I print this thing out in my echo I get this,
Heres my echo:
echo 'Hello, '.$username.', you Result is: '.$passResult.'!';
What I want to get is:
Hello, test, your Result is: 1
or
Hello, test, your Result is: 0
Now what I get is:
Hello, test, your Result is: Resource id #6
Now no matter what I do I get the same thing, I have no idea what I'm doing wrong here guys if someone could point this out that would be awesome. What this enum is being use essentially for a boolean just to see if the user has personally set a password not the computer generated version.
mysql_query returns a result resource, essentially a pointer to the memory where the results are buffered. That result set can contain many rows, as you can select many rows, so you need to fetch the row(s) you want then the column(s) you want from those rows.
/* execute the query and get a result resource back */
$passResult = mysql_query("SELECT usrSetPass FROM members WHERE usr='" . mysql_real_escape_string($username) . "'");
/* retrieve the first row from $passResult */
$row = mysql_fetch_assoc($passResult);
/* assign the usrSetPass column's value from that row to $passed */
$passed = $row['usrSetPass'];
Also, your query is wrong. You enclosed it in double quotes, so you're not actually breaking out of the string and concatenating $username when you use the single quotes and dots inside. I've corrected it above.
mysql_query doesn't return a value, it returns a resource (see here in the manual).
The returned result resource should be passed to another function for dealing with result tables (like mysql_fetch_array() or mysql_fetch_assoc()), to access the returned data.
Example based on your initial code:
$username = 'test';
$passResult = mysql_query("SELECT usrSetPass FROM members WHERE usr='".$username."'");
while ($row = mysql_fetch_assoc($passResult)) {
echo $row['usrSetPass'];
}