Search value in array and if not found added - php

Question

I have an array with the following format:
$array = Array(
Array('id' => 77, 'title' => 'title'),
Array('id' => 43, 'title' => 'title2'),
Array('id' => null, 'title' => 'title3'),
Array('id' => null, 'title' => null),
);
This array is populated dynamically, this is just an example. Also, i have a second array with the format:
$searchingArray = Array('43', '5');
The main idea is to search if values from $searchingArray are in $array and if not exists then added. My function is:
function addId($id, $ignoreIfFound=false) {
foreach ($array as $values) {
if ($values['id'] and $values['id'] == $id) {
if (!$ignoreIfFound) {
$array[] = Array('id' => $id, 'title' => 'test5');
break;
}
else{
// do nothing
}
}else{
$array[] = Array('id' => $id, 'title' => 'test5');
break;
}
}
}
foreach ($searchingArray as $id) {
$this->addId($id, true);
}
For given example the result should be:
$array = Array(
Array('id' => 77, 'title' => 'title'),
Array('id' => 43, 'title' => 'title2'),
Array('id' => null, 'title' => 'title3'),
Array('id' => null, 'title' => null),
Array('id' => 5, 'title' => 'test5'),
);
Can you tell me what it is wrong with my code?

Answer 1

This should work for you:
First extract the id column out of your array with array_column(). After this simply loop through your search array and check with in_array() if they id already exists or not. If not simply add it to the array.
$ids = array_column($array, "id");
foreach($searchingArray as $search) {
if(!in_array($search, $ids)) {
$array[] = ["id" => $search, "title" => "title" . $search];
}
}