PHP - Combining Multiple Items Into One - php

I am attempting to create an end-user page where I present different servers that are available to check-out. A server at any given time can have either an "Available" status or a "Reserved" status. I'm using a MySQL backend. This is how I am doing my query:
SELECT *, COUNT(CASE WHEN Status = 'Available' THEN 1 ELSE NULL END) AS Amount
FROM products GROUP BY id
This is the result I get:
id,Server_Type,Status,Amount
1,BL460,Available,1
2,BL460,Available,1
3,BL460,Reserved,0
4,BL460,Reserved,0
5,BL460,Reserved,0
6,DL360,Available,1
7,DL360,Reserved,0
8,DL360,Reserved,0
Where Reserved is equal to 0, and Available is equal to 1. I only want the end-user to be able to checkout a server in Available status.
To the question: What I want to do in the page is present the list of servers on the page in this way, where Available is equal to the amount:
BL460 - Amount: 2
DL360 - Amount: 1
How can I achieve this format in PHP?

Another option is a crosstab query -
SELECT `Status`,
SUM(IF(`Server_Type` = 'BL460' AND `Status` = 'Available', `Amount`, 0)) AS `BL460`,
SUM(IF(`Server_Type` = 'DL360' AND `Status` = 'Available', `Amount`, 0)) AS `DL360`
FROM `products`
GROUP BY `Status`
Your table would look like this -
Status | BL460 | DL360 |
Available | 2 | 1 |
Reserved | 0 | 0 |
Here is an EXAMPLE
Even better would be to flip things around -
SELECT `server_type`,
SUM(IF(`status` = 'Available', 1, 0)) AS `Available`,
SUM(IF(`status` = 'Reserved', 1, 0)) AS `Reserved`
FROM `servers`
GROUP BY `server_type`;
Which would result in a table that looks like this (based on data in the fiddle) -
server_type | Available | Reserved
BL460 | 3 | 1
DL360 | 1 | 2
Here is that EXAMPLE
Here I could continue to add servers to the table without having to worry about adding them to the query as you would have to do in the first query. If you add an additional status you would have to change the query.
Note in both cases there is no need for an Amount column as the status is the item counted. By placing the load on the database server it makes it much easier to output the HTML as you are just going row bu row as you normally would.

Well, that would probably be easier if you do it directly in your SQL query:
SELECT Server_Type, COUNT(*) AS Count FROM products WHERE Status = 'Available' GROUP BY Server_Type
This should give you exactly the table you want.
If you want to do it in PHP, the easiest solution would probably be to loop through your SQL result and count the number of available servers per Server_Type in an associative array where the Server_Type is your array key:
$amounts = array();
foreach($sql_result as $entry) {
if($entry['Amount'] == 1) {
if(isset($amounts[$entry['Server_Type']])) {
$amounts[$entry['Server_Type']]++;
} else {
$amounts[$entry['Server_Type']] = 1;
}
}
}
echo $amounts;
Edit: in order to print the values as described in the question, you could use the following code snippet:
foreach($amounts as $name=>$amount) {
echo $name + " - Amount: " + $amount + "<br>";
}

Related

MYSQL: List all column names where their values = "Yes"

I have a table like so:
User_Id Column1 Column2 Column3
1 Yes No Yes
2
I want to use mysql query to list all the column names (there are more than 3) which match the User_Id '1' and have a value of 'Yes'.
I get an error:
Trying to get property 'num_rows' of non-object
Here is what I have tried:
<?php $myStats = $mysqli->query("SELECT COLUMN_NAME FROM user_services.columns WHERE myColumn = 'Yes'");
if ($myStats->num_rows > 0) {
// output data of each row
while($row = $myStats->fetch_assoc()) {
$rows[] = $row; }
return $rows; ?>
Please can someone show me where I am going wrong?
Thanks in advance.
The CONCAT_WS function comes in handy here:
SELECT CONCAT_WS(',', IF(Column1='Yes', 'Column1', NULL),
IF(Column2='Yes', 'Column2', NULL),
IF(Column3='Yes', 'Column3', NULL)) AS columns
FROM user_services.columns
WHERE User_Id = 1;
If you have more than 3 columns, then you may add more terms to above CONCAT_WS call. Your problem mainly seems to be a SQL one, so I won't add any PHP code.
Note that your design might be better off if your column strings were spread across rows, rather than columns. For instance, consider the following alternative:
User_Id | number | val
1 | 1 | Yes
1 | 2 | No
1 | 3 | Yes
Then, if you wanted all column numbers which were yes for user 1, you could simply do:
SELECT
User_Id,
GROUP_CONCAT(number ORDER BY number) columns
FROM yourTable
WHERE
User_Id = 1
GROUP BY
User_Id;

Get value from table with 3 unique ID's (redundant sql query)

$query = "SELECT COUNT(id) FROM complaint WHERE ID_complntCategory = ?";
$complntCategory = $database->prepare($query);
try {
$complntCategory->execute(array());
$complntCategory->setFetchMode(PDO::FETCH_ASSOC);
foreach ($complntCategory as $key) {
$totaalM = $key['1'];
$totaalV = $key['2'];
$totaalG = $key['3'];
}
}
catch(PDOException $e) {
echo "Error";
}
Above you see my PHP code, and here is what I'm trying to do:
I'm trying to get the amount of rows from the table 'complaint' into 3 different variables (totaalM, totaalV and totaalG). The totaalM variable should contain the amount of rows 'WHERE ID_complntCategory = 1'.
For the other variables the 'ID_complntCategory' should be 2 and 3
('ID_complntCategory' is either 1, 2 or 3)
There should be a way where I don't have to write 3 queries, right?
I'm clearly approaching this the wrong way, and I'm not sure how I should tackle this problem...
What you are trying to do is called pivot rows into columns, but MySQL doesn't have pivot table operator like other RDBMS, but you cane use the case expression like this in one query:
SELECT
SUM(CASE WHEN ID_complntCategory = 1 THEN 1 ELSE 0 END) AS totaalM,
SUM(CASE WHEN ID_complntCategory = 2 THEN 1 ELSE 0 END) AS totaalV,
SUM(CASE WHEN ID_complntCategory = 3 THEN 1 ELSE 0 END) AS totaalG,
COUNT(Id) AS Total
FROM complaint;
Or you can make it shorter like this:
SELECT
SUM(ID_complntCategory = 1) AS totaalM,
SUM(ID_complntCategory = 2) AS totaalV,
SUM(ID_complntCategory = 3) AS totaalG,
COUNT(Id) AS Total
FROM complaint;
Demo
This will give you something like this:
| totaalM | totaalV | totaalG | Total |
|---------|---------|---------|-------|
| 2 | 3 | 1 | 7 |
Here you need some magic, involving special SQL and PDO features.
First, you need an SQL query that is giving you desired results in one query. To get that you need a GROUP BY operator:
SELECT ID_complntCategory, count(*) FROM complaint GROUP BY ID_complntCategory
it will give you counts split by ID_complntCategory.
Next, you can use one of PDO's magnificent features, PDO::FETCH_KEY_PAIR fetch mode, that will give you an array where key would be category id and value is count
$sql = "SELECT ID_complntCategory, count(*) FROM complaint GROUP BY ID_complntCategory";
$stmt = $database->prepare($sql);
$key = $stmt->fetchAll(PDO::FETCH_KEY_PAIR);
$totaalM = $key['1'];
$totaalV = $key['2'];
$totaalG = $key['3'];
note that you should never catch a PDO errors only to say "error". Let PHP error reporting to do it instead.

Availability Calculating logic in php

This is a mysql query result. Now I have to calculate the available quantity in php based on per challan Id. The expected result will be:
ChallanId | Avaiable Qty | unitCostPrice | totalPrice
11 | 7 | 2 | 14
12 | 10 | 1 | 10
How it can be done in php? useing foreach or any other tricks.
Though you want to achieve this for PHP solution, but here I think SQL query also can do that:
select
ChallanId,
sum(case when Narration = 'in' then ItemIn when Narration = 'out' then 0 - ItemOut end) as Avaiable_Qty,
unitCostPrice,
sum(case when Narration = 'in' then ItemIn when Narration = 'out' then 0 - ItemOut end) * unitCostPrice as totalPrice
from (your query here...)
having Avaiable_Qty > 0
group by ChallanId
I would do the calculation in SQL by having a smarter query.
select
ChallanId,
UnitCostPrice,
sum(`ItemIn`)-sum(`ItemOut`) as AvailableQty,
(sum(`ItemIn`)-sum(`ItemOut`))*UnitCostPrice as totalPrice
from tbl
group by ChallanId
Live demo
This is psuedo-code kind of, since you didn't share your implementation with PHP.
Firstly, you can assume the Narration from whether ItemIn or ItemOut is not zero, in fact it is probably better to do that since you could then introduce items in as well as items out with the same line. But that's not the question.
$output = array();
foreach ($dbResults as $row) {
// Create an output entry
if (!array_key_exists($row['ChallanID'], $output)) {
$output[$row['ChallanID']] = array('Qty' => 0, 'CostPrice' => 0, 'Total' => 0);
}
// Add to totals
$output[$row['ChallanID']]['Qty'] += ($row['ItemIn'] - $row['ItemOut']);
$output[$row['ChallanID']]['CostPrice'] = $row['UnitCostPrice']; // you may want to average this instead?
$output[$row['ChallanID']]['Total'] += $output[$row['ChallanID']]['Qty'] * $output[$row['ChallanID']]['CostPrice'];
}
$output should now contain your desired output. Untested.

Very slow mysql request + php

The ideia is: select all professions from a table. After this count how many professionals have the profession id in his category column. The category column store the professions id's separeted by commas (1, 2, 3, 420). The professions table has 604 rows.
I have the following piece of code:
<?php
$select_professions = mysql_query("SELECT * FROM professions");
if(mysql_num_rows($select_professions) == "0"){
echo"No registers in DB";
}else{while($row_professions = mysql_fetch_assoc($select_professions)){
$id = $row_professions['id'];
$count_profiles = mysql_query("SELECT
COUNT(FIND_IN_SET(professions.id, professional.category) > 0) AS profile_numbers
FROM
professions
INNER JOIN
professional
WHERE
FIND_IN_SET(professions.id,professional.category) > 0
AND
professions.id = $id
GROUP BY
professions.id");
$reg_profiles = mysql_fetch_assoc($count_profiles);
$numProfiles = $reg_profiles['profile_numbers'];
if($numProfiles > 4){
$style = 'display:none';
}else{
$style = '';
}
?>
My basic question is WHY this is so slow in Google Chrome?
Its taking like 15 seconds to load entire page with these results in a html table. In Edge or Firefox is taking about 5 seconds. I heard about Chrome using so much memory lately but I don't believe its soo slowly. In time this is the first time I use the FIND_IN_SET function on mysql. Is that may are slowing down the request? Anyone knows what I'm doing wrong or how can be optimized? This is actualy working but we know that 15 seconds of waiting makes the user give up or think that page is not working. I have to say too that if I do the same consultation on my HeidiSQL it takes 1 second.
I recommend to normalize this:
The category column store the professions id's separeted by commas (1,
2, 3, 420)
This is an n:n relationship. Your layout:
professionals:
id | catgeory
12 | 1,2,4,50
professions
id | desc
1 | prof A
2 | prof B
...
The string operations (split the list, normalize internal, query result in to temp, ...) is very cost intensive. Better:
professionals:
id | ...
12 | ..
profrelations
pid | cid
12 | 1
12 | 2
12 | 4
12 | 50
professions
id | desc
1 | prof A
2 | prof B
...
This would skip the COUNT(FIND_IN_SET(professions.id, professional.category) > 0) as a string operation (even twice):
SELECT COUNT(cid) AS profile_numbers from professionals, profrelations where
professionals.id = profrelations.pid AND profrelations.pid = $id;
etc. You might restructure the above query like this, as long as you won't actually need any column from professions.
You can add a unique index on the cols (pid, cid) in table profrelations as one professional actually can have one profession only one times.
Remark
The different behaviour in two browser might result from the server caching the query: You're doing the query with Chrome, it's slow, but the result gets cached. Next with FF, server will respond with the cached result as its the same query again - fast. Try it three times or the other way round, should then be the same in all browsers.
At first,
this operation COUNT(FIND_IN_SET(professions.id, professional.category) > 0) will not return result that you expected. Count in above expression will return 1 even if find_in_set returns 0.
Secondly, I wouldn't use join in this case at all. This tables have no direct relation by identifiers.
I would optimize the query as following:
SELECT COUNT(professions.id) AS profile_numbers FROM professions, professional
WHERE FIND_IN_SET(professions.id,professional.category) > 0 AND professions.id = $id
GROUP BY professions.id

Collect values from DB, group matching values, count it and use in other code

This is what my customers_basket table looks like:
customers_id | products_id | basket_quantity
3 | 56:3121fefbe6043d6fc12e3b3de2c8fc38 | 3
3 | 56:fb4c9278fcfe6225b58c06711a7e62ef | 1
3 | 56:8e334fce09556108f5416e27154b6c27 | 1
3 | 52:f3b9f38e4ddd18035bc04cd264b0f052 | 1
This is the query I'm using:
$products_in_cart_query = "SELECT products_id FROM customers_basket WHERE customers_id = " . $_SESSION['customer_id'] ."";
$products_in_cart = $db->Execute($products_in_cart_query);
$products_in_cart_model = $products_in_cart->fields['products_id'];
$products_in_cart_model = substr($products_in_cart_model, 0, strpos($products_in_cart_model, ":"));
The end result I get is 56,56,56,52
First of all, how do I use the first line's quantity field? I'd need to list that products_id 3 times since quantity is 3. Therefore, the end result needs to be: 56,56,56,56,56,52
or, for easier understanding (56,56,56),56,56,52
And second, how do I count how many same values I have? In this case, I have 5x56 and 1x52. I need to use those counts in my further calculation.
EDIT: further calculations explained
I need to know how many of each product_id I have and then run something like this:
foreach(product_id) {
$shipping_cost += FIXED_VALUE * basket_qty;
}
To get the basket quantity, you have to select it. It would be best if the first portion of the product ID was stored in a separate column, rather than having to do messy operations like substringing.
Query 1: 2-character codes and corresponding quantities
SELECT SUBSTR(products_id, 1, 2) AS product_code, basket_quantity
FROM Customers_Basket
WHERE customers_id = 3;
Query 2: 2-character codes and summed quantities
SELECT product_code, SUM(basket_quantity) AS total_quantity
FROM (SELECT SUBSTR(products_id, 1, 2) AS product_code, basket_quantity
FROM Customers_Basket
WHERE customers_id = 3
)
GROUP BY product_code;
If you really, really, really desperately want 3 rows of data for the product ID 56:3121fefbe6043d6fc12e3b3de2c8fc38, then you have to know ways to generate rows. They're truly painful in the absence of convenient SQL support (so much so, that you'd do better to select a row in PHP with the quantity and then generate the appropriate number of rows in your array in the client-side (PHP) code). I'm going to assume that some variation on these queries will get you the information you want.

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