PDO query not displaying results? - php

Okay so i am new to PDO statements so i am unsure if i have done a syntax error or whatnot. The php file does not show any errors:
<?php
include('db_config.php');
$itemName = 'Item1';
$sql = "SELECT * FROM order WHERE itemName = $itemName;";
$stmt = $conn->prepare($sql);
$stmt->execute();
while ($row = $stmt->fetch(PDO::FETCH_ASSOC))
{
echo $row['itemName'];
}
?>
My objective is to pull an item using bootstraps datepicker, but for the purpose of this testing i am using the itemName.
The php file comes up blank?
I have checked the field names, db_config, and am unsure where the issue is coming from.
Please let me know if i have done an error in my statement or anything that seems wrong.

Firstly, you're using a MySQL reserved word, being order and it requires special attention; mainly using ticks around it.
Then since we're dealing with a string, $itemName needs to be wrapped in quotes.
<?php
include('db_config.php');
$itemName = 'Item1';
$sql = "SELECT * FROM `order` WHERE itemName = '$itemName';";
$stmt = $conn->prepare($sql);
$stmt->execute();
while ($row = $stmt->fetch(PDO::FETCH_ASSOC))
{
echo $row['itemName'];
}
?>
Either use ticks around your table name, or rename it to "orders", it's not a reserved keyword.
"The php file does not show any errors:"
That's because you're not checking for them.
Add $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); right after the connection is opened.
Now, if you're going to use PDO, use PDO with prepared statements, they're much safer.
As per a comment you left under your question containing the MySQL error:
1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'order
Read it near 'order it starts at "order".
Now, if ever your query should ever contain any character that MySQL will complain about, such as a quote etc. then you will need to escape your query and use prepared statements.
For example, if using:
$itemName = "Timmy's Sour Dough";
would translate to
WHERE itemName = 'Timmy's Sour Dough'
in turn throwing a syntax error.
So, it's best to immediately escape any data right away.
Edit
Your use of prepare and new to PDO collectively suggest that you are already trying to use prepared statements, just not the right way. You're just a little off from a well prepared statement. One correct way in your code would be
$sql = "SELECT * FROM `order` WHERE itemName = ? ";
$stmt = $conn->prepare($sql);
$stmt->execute(array($itemName));
Notice how we have a ? in your query then we are sending a value for it in your execute call. There you go :)
Using PDO with prepared statements will take care of that.

You're completely ignoring the main reason people use PDO. Prepared statements are what you should be using, which would make your query look like this:
$itemName = 'Item1';
$sql = "SELECT * FROM order WHERE itemName = ?";
$stmt = $conn->prepare($sql);
$stmt->bindParam(1, $item, PDO::PARAM_STR);
$stmt->execute();
Read up on bindParam().
In future, turn on your error reporting at the beginning of the script with this:
ini_set('display_errors', 1);
error_reporting(E_ALL);
That will save you a lot of time.

Looks like there is an error in you sql statement. since itemName is either a varchar or text in your database, you need to put it in single quotes in the query:
$sql = "SELECT * FROM order WHERE itemName = '$itemName';";

Related

Select all posts made on the same date

I have a table structure like this:
sender| receiver| message|date|time
----------------------------------
How do I select all the messages written on the same date, with them appearing at the top, just like Facebook Chat?
I've tried something like this:
<?php
$con=mysql_connect("localhost","root","");
$db=mysql_select_db ("chat",$con);
$query=" select * from chat where sender='$send'
and receiver='$rec' order by date";
$result=mysql_query($query);
while($r2=mysql_fetch_array($result))
echo "<div>{$r2['date']}</div>";
{
echo"<div>{$r2['message']}</div>";
}
?>
You're trying to run an SQL query directly from PHP, which you can't do - you'll need to connect to your database first. Then you need to pass the $send and $rec variables to your database, preferably through prepared statements to prevent SQL injection.
It depends on whether you're using MySQLi or PDO as to exactly how you should do that, but I'll assume you're not using the mysql_ constructor, as that was deprecated as of PHP 5.5, and is removed in PHP 7.
As such, here's an example of how to do this through MySQLi with prepared statements:
<?php
$mysqli = new mysqli("example.com", "user", "password", "database");
$stmt = $mysqli->prepare(
"SELECT * FROM tablename WHERE sender = ? && receiver = ?");
$stmt->bind_param("ss", $send, $rec);
// "ss' is a format string, each "s" means string
// Each variable gets passed to the question marks, in order
$stmt->execute();
$stmt->bind_result($result);
You then have the results stored in $result, and are free to manipulate from there.
Hope this helps! :)

Using PHP variable in SQL query

I'm having some trouble using a variable declared in PHP with an SQL query. I have used the resources at How to include a PHP variable inside a MySQL insert statement but have had no luck with them. I realize this is prone to SQL injection and if someone wants to show me how to protect against that, I will gladly implement that. (I think by using mysql_real_escape_string but that may be deprecated?)
<?php
$q = 'Hospital_Name';
$query = "SELECT * FROM database.table WHERE field_name = 'hospital_name' AND value = '$q'";
$query_result = mysqli_query($conn, $query);
while ($row = mysqli_fetch_assoc($query_result)) {
echo $row['value'];
}
?>
I have tried switching '$q' with $q and that doesn't work. If I substitute the hospital name directly into the query, the SQL query and PHP output code works so I know that's not the problem unless for some reason it uses different logic with a variable when connecting to the database and executing the query.
Thank you in advance.
Edit: I'll go ahead and post more of my actual code instead of just the problem areas since unfortunately none of the answers provided have worked. I am trying to print out a "Case ID" that is the primary key tied to a patient. I am using a REDCap clinical database and their table structure is a little different than normal relational databases. My code is as follows:
<?php
$q = 'Hospital_Name';
$query = "SELECT * FROM database.table WHERE field_name = 'case_id' AND record in (SELECT distinct record FROM database.table WHERE field_name = 'hospital_name' AND value = '$q')";
$query_result = mysqli_query($conn, $query);
while ($row = mysqli_fetch_assoc($query_result)) {
echo $row['value'];
}
?>
I have tried substituting $q with '$q' and '".$q."' and none of those print out the case_id that I need. I also tried using the mysqli_stmt_* functions but they printed nothing but blank as well. Our server uses PHP version 5.3.3 if that is helpful.
Thanks again.
Do it like so
<?php
$q = 'mercy_west';
$query = "SELECT col1,col2,col3,col4 FROM database.table WHERE field_name = 'hospital_name' AND value = ?";
if($stmt = $db->query($query)){
$stmt->bind_param("s",$q); // s is for string, i for integer, number of these must match your ? marks in query. Then variable you're binding is the $q, Must match number of ? as well
$stmt->execute();
$stmt->bind_result($col1,$col2,$col3,$col4); // Can initialize these above with $col1 = "", but these bind what you're selecting. If you select 5 times, must have 5 variables, and they go in in order. select id,name, bind_result($id,name)
$stmt->store_result();
while($stmt->fetch()){ // fetch the results
echo $col1;
}
$stmt->close();
}
?>
Yes mysql_real_escape_string() is deprecated.
One solution, as hinted by answers like this one in that post you included a link to, is to use prepared statements. MySQLi and PDO both support binding parameters with prepared statements.
To continue using the mysqli_* functions, use:
mysqli_prepare() to get a prepared statement
mysqli_stmt_bind_param() to bind the parameter (e.g. for the WHERE condition value='$q')
mysqli_stmt_execute() to execute the statement
mysqli_stmt_bind_result() to send the output to a variable.
<?php
$q = 'Hospital_Name';
$query = "SELECT value FROM database.table WHERE field_name = 'hospital_name' AND value = ?";
$statement = mysqli_prepare($conn, $query);
//Bind parameter for $q; substituted for first ? in $query
//first parameter: 's' -> string
mysqli_stmt_bind_param($statement, 's', $q);
//execute the statement
mysqli_stmt_execute($statement);
//bind an output variable
mysqli_stmt_bind_result($stmt, $value);
while ( mysqli_stmt_fetch($stmt)) {
echo $value; //print the value from each returned row
}
If you consider using PDO, look at bindparam(). You will need to determine the parameters for the PDO constructor but then can use it to get prepared statements with the prepare() method.

Query not inserting data

trying to submit data from a form but does not seem to be working. Can't spot any problems?
//Include connect file to make a connection to test_cars database
include("prototypeconnect.php");
$proId = $_POST["id"];
$proCode = $_POST["code"];
$proDescr = $_POST["descr"];
$proManu = $_POST["manu"];
$proCPU = $_POST["cpu"];
$proWPU = $_POST["wpu"];
$proBarCode = $_POST["barcode"];
$proIngredients = $_POST["ingredients"];
$proAllergens = $_POST["allergenscon"];
$proMayAllergens = $_POST["allergensmay"];
//Insert users data in database
$sql = "INSERT INTO prototype.Simplex_List (id, code, descr, manu, cpu, wpu, barcode, ingredients, allergenscon, allergensmay)
VALUES ('$proId' , '$proCode', '$proDescr' , '$proManu' , '$proCPU' , '$proWPU' , '$proBarCode' , '$proIngredients' , '$proAllergens' , '$proMayAllergens')";
//Run the insert query
mysql_query($sql)
First and foremost, please do not use mysql_*** functions and please use prepared statements with
PDO http://php.net/manual/en/pdo.prepare.php
or mysqli http://php.net/manual/en/mysqli.quickstart.prepared-statements.php instead. Prepared statements help protect you against sql injection attempts by disconnecting the user submitted data from the query to the database.
You may want to try using mysql_real_escape_string http://php.net/manual/en/function.mysql-real-escape-string.php to ensure no stray " or ' is breaking your query.
$proId = mysql_real_escape_string($_POST["id"]);
$proCode = mysql_real_escape_string($_POST["code"]);
$proDescr = mysql_real_escape_string($_POST["descr"]);
$proManu = mysql_real_escape_string($_POST["manu"]);
$proCPU = mysql_real_escape_string($_POST["cpu"]);
$proWPU = mysql_real_escape_string($_POST["wpu"]);
$proBarCode = mysql_real_escape_string($_POST["barcode"]);
$proIngredients = mysql_real_escape_string($_POST["ingredients"]);
$proAllergens = mysql_real_escape_string($_POST["allergenscon"]);
$proMayAllergens = mysql_real_escape_string($_POST["allergensmay"]);
Additionally ensure your form is being submitted by calling var_dump($_POST) to validate the data
You can also see if the query is erroring by using mysql_error http://php.net/manual/en/function.mysql-error.php
if (!mysql_query($sql)) {
echo mysql_error();
}
advices about PDO, prepared statements were done.
1) Do you have a database and connection to it?
Look at your prototypeconnect.php and find database name there. check that its name and password is similar that u have.
2) Do you have a table named prototype.Simplex_List in your database?
a) IF YOU HAVE:
check if your mysql version >= 5.1.6
http://dev.mysql.com/doc/refman/5.1/en/identifiers.html
b) IF YOU HAVE BUT ITS NAME is Simplex_List:
b-1) if your database name IS NOT prototype:
replace your
$sql = "INSERT INTO prototype.Simplex_List
with
$sql = "INSERT INTO Simplex_List
b-2) if your database name IS prototype:
you should escape your $_POST data with mysql_real_escape_string as #fyrye said.
c) IF YOU HAVE NOT:
you should create it
3) Check your table structure
does it have all theese fields id, code, descr, manu, cpu, wpu, barcode, ingredients, allergenscon, allergensmay?
if you have there PRIMARY or UNIQUE keys you should be sure you are not inserting duplicate data on them
but anyway replace your
$sql = "INSERT INTO
with
$sql = "INSERT IGNORE INTO
PS: its not possible to help you without any error messages from your side

PHP+MySQL wrong syntax in where clause

This is my query
$query = "SELECT * FROM ham WHERE Call = $call";
I've tried with it all kinds of configurations with backticks and single quotes. Every time I get this:
Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'CALL = LZ1IRQ' at line 1
'LZ1IRQ' is an actual value I set using an HTML form via POST.
$call = mysqli_escape_string($con, $_POST['call']);
CALL is reserved keyword in MySQL. I think you cannot use this keyword as you are using now. See this official list of reserved keywords.
If you are required to use reserved key then you should wrap it in back-ticks.
I can infer you are using mysqli so the best and most secure is to bind parameters, with this solution you prevent sql injection at the same time:
$mysqli = new mysqli('localhost', 'my_user', 'my_password', 'world');
$stmt = $mysqli->prepare("SELECT * FROM ham WHERE Call =?");
$stmt->bind_param('s', $call);
Change your query to this
$query = "SELECT * FROM ham WHERE Call = {$call}";
Try this
$query = "SELECT * FROM ham WHERE `Call` = '".$call."' ";

PDO Database access WHERE title = $title

I'm trying to learn to use PDO instead of MySQLi for database access and I'm having trouble selecting data from the database. I want to use:
$STH = $DBH->query('SELECT * FROM ratings WHERE title=$title ORDER BY date ASC');
$STH->setFetchMode(PDO::FETCH_ASSOC);
while($row = $STH->fetch()) {
echo $row['title'];
}
but I'm getting this error:
Fatal error: Call to a member function setFetchMode() on a
non-object in
/home/owencont/public_html/owenstest.com/ratemystudents/index.php
on line 6
If I take out the WHERE statement it works fine. How can I select a row based on if it's value matches a variable?
Thanks,
Owen
It's likely a SQL syntax error, because you forgot to quote $title. It ended up as bareword in the query (also not even interpolated as string), resulting in an error. And your PDO connection was not configured to report errors. Use ->quote() on arguments before the ->query():
$title = $DBH->quote($title);
$STH = $DBH->query("SELECT * FROM ratings WHERE title=$title ");
Or better yet, use parameterized SQL:
$STH = $DBH->prepare("SELECT * FROM ratings WHERE title=? ");
$STH->execute(array($title));
Take a look at PDO::prepare and PDOStatement::execute. The safest way to add user content to a query is to prepare a basic statement and bind the parameter to it. Example (note the question mark in the SQL statement):
$STH = $DBH->query('SELECT * FROM ratings WHERE title=? ORDER BY date ASC');
$STH->execute( array( $title ) );
while( $row = $STH->fetch( PDO::FETCH_ASSOC ) );
Make PDO throw errors so you can see what exactly goes wrong. See How to squeeze error message out of PDO?
You are probably missing quotes around $title but this scenario really calls for prepared statements instead.
remove the variable out of the sql statement because its a php variable
$STH = $DBH->query('SELECT * FROM ratings WHERE title=' . $title . 'ORDER BY date ASC');
Use double quotes instead of single quotes as a parameter of the query-method.
The reason you're getting this error is because the query-method fails and so the $STH object isn't created. You should implement some error handling.

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