Date comparison in php cannot be done - php

Question

i cannot compare dates in php.My code look like this:
$sqldt="select to_char(sysdate-2,'dd-mon-yyyy') from dual";
$stmtdt = $obj->executeQuery($sqldt);
$rowdt = oci_fetch_array($stmtdt,OCI_BOTH);
$startdate = date('d/m/y', strtotime($rowdt[0]));
$enddate=date('d/m/y');
$workdate=date('d/m/y', strtotime($wdate)); //here wdate is our selected date which is passed from previous page.
echo "start date=".($startdate); //showing correctly
echo "end date=".($enddate);//showing correctly
echo "work date=".($workdate);//showing correctly
$S_WORKDATE=strtotime($workdate);
$S_STARTDATE=strtotime($startdate);
$S_ENDDATE=strtotime($enddate);
now when i compare dates like this
if($S_WORKDATE<$S_ENDDATE)
{
echo "worked";
}
else
{
echo "failed";
}
whatever comparison like '<' or'>' or '<=' or '>=' is return incorrect result after code execution.please do help

Answer 1

/ is not work with strtotime() function in dd/mm/yyyy format.
So, You may change / to -
$startdate = date('d-m-y', strtotime($rowdt[0]));
$enddate=date('d-m-y');
$workdate=date('d-m-y', strtotime($wdate));
OR u may directly compare like
if($workdate<$enddate)
{
echo "worked";
}
else
{
echo "failed";
}

Answer 2

Please look at the code that i have given below,
$startdate = new date('d/m/y');
$enddate = new date('d/m/y');
$startdate ->diff($enddate );
if($startdate > $enddate )
echo "startdate is bigger";
else
echo "enddate is bigger";
Edited
Please look at this link for more information: http://php.net/manual/en/datetime.diff.php
I hope this helps you.

Answer 3

Dates in the m/d/y or d-m-y formats are disambiguated by looking at
the separator between the various components: if the separator is a
slash (/), then the American m/d/y is assumed; whereas if the
separator is a dash (-) or a dot (.), then the European d-m-y format
is assumed.
So basically, your month and day are getting switched around.
You want to use ...
$enddate=date('m/d/y');