PHPExcel upload data via xls file - php

Question

Do you know what I am doing wrong here? What I try to do is select a value from a choice box and then upload a xls file when I click on submit it uploads it into MySQL. But when I click on submit I get Invalid post request.
require '../PHPExcel/Classes/PHPExcel.php';
require_once '../PHPExcel/Classes/PHPExcel/IOFactory.php';
$proposal = "select * from proposal";
$rsExport = mysqli_query($DBCONN, $proposal) or die(mysql_error());
echo '<form id="proposal_form" method="post">';
echo "<select id='select_your_proposal' name = 'select_your_proposal'>";
echo "<option value=''>Select Your Proposal</option>";
while ($row = mysqli_fetch_array($rsExport)) {
echo "<option value='" . $row['id'] . "'>" . $row['enterpriseid'] . " - " . $row['sitename'] . " - " . $row['presaleconsultant'] . " </option>";
}
echo "</select>";
?>
<br>
<form method="post" enctype="multipart/form-data">
1.) Upload User File: <input type="file" name="spreadsheet"/>
<br>
<br>
<?php
if (isset($_POST['select_your_proposal'])) {
$proposal2 = mysqli_query($DBCONN, "select * from proposal where id = '" . $_POST['select_your_proposal'] . "'");
$row = $proposal2->fetch_assoc();
$proposalid = $_POST['select_your_proposal'];
unset($sessionid);
$sessionid = uniqid();
$user = CurrentUserName();
$date = date('Y-m-d H:i:s');
ini_set('display_errors', 1);
// Check valid spreadsheet has been uploaded
if (isset($_FILES['spreadsheet'])) {
if ($_FILES['spreadsheet']['tmp_name']) {
if (!$_FILES['spreadsheet']['error']) {
$inputFile = $_FILES['spreadsheet']['tmp_name'];
$extension = strtoupper(pathinfo($inputFile, PATHINFO_EXTENSION));
if ($extension == 'XLSX' || $extension == 'XLS') {
$objPHPExcel = PHPExcel_IOFactory::load($inputFile);
foreach($objPHPExcel->getWorksheetIterator() as $worksheet) {
$worksheetTitle = $worksheet->getTitle();
$highestRow = $worksheet->getHighestRow(); // e.g. 10
$highestColumn = $worksheet->getHighestColumn(); // e.g 'F'
$highestColumnIndex = PHPExcel_Cell::columnIndexFromString($highestColumn);
$nrColumns = ord($highestColumn) - 64;
echo "<br>The worksheet " . $worksheetTitle . " has ";
echo $nrColumns . ' columns (A-' . $highestColumn . ') ';
echo ' and ' . $highestRow . ' row.';
echo '<br>Data: <table border="1"><tr>';
for ($row = 1; $row <= $highestRow; ++$row) {
echo '<tr>';
for ($col = 0; $col < $highestColumnIndex; ++$col) {
$cell = $worksheet->getCellByColumnAndRow($col, $row);
$val = $cell->getValue();
$dataType = PHPExcel_Cell_DataType::dataTypeForValue($val);
echo '<td>' . $val;
}
echo '</tr>';
}
echo '</table>';
}
for ($row = 2; $row <= $highestRow; ++$row) {
$val = array();
for ($col = 0; $col < $highestColumnIndex; ++$col) {
$cell = $worksheet->getCellByColumnAndRow($col, $row);
$val[] = $cell->getValue();
}
$sqlsession = "INSERT IGNORE INTO session (
xxxx
";
$sqluser = "INSERT INTO bw_users (
xxxx
);";
// echo $sqluser."\n";
// echo $sqlsession."\n";
$result = mysqli_query($DBCONN, $sqlsession);
$result = mysqli_query($DBCONN, $sqluser);
if (!$result) {
echo "DB Error, could not query the database\n";
echo 'MySQL Error: ' . mysql_error();
exit;
}
}
}
}
}
}
else {
echo "Please upload an XLSX or XLS file";
}
}
echo "<br>";
echo "</form>";
echo '<input type="submit" name="submit" value="Submit">';
?>

Answer 1

You need to define action in the form your code should look like dis
<form method="post" enctype="multipart/form-data" action="yournextpage.php">
1.) Upload User File: <input type="file" name="spreadsheet"/>
Or use some javascript to redirect the page