My question may be confuse because I've started learning Laravel.
Can I use eloquent model property in subquery of with() function?
I have classes, students, and grades tables. I wish to get
$classes = [{id:1, name:'maths', students:[{id:2, name: john,
grade:B},{id:1, name: Mac, grade:C}]}, {id:2, name:'physics',
students:[{id:2, name: john, grade:null},{id:1, name: Mac,
grade:null}]}]
for example:
$classes = Class::with(['students' => function($query){
->leftJoin('grades', 'grades.student_id', '=', 'students.id')
}])->get()->toJSON();
This query doesn't select correct grades of related classes. I wish to use class::id = grades.class_id in join condition.
I use leftJoin because some class may not have released its grade.
You need to do it this way:
$classes = Class::with(['students' => function($query){
->leftJoin('grades', function($join) {
$join->on('grades.student_id', '=', 'students.id');
$join->on('grades.class_id', '=', 'class.id');
})
}])->get()->toJSON();
Finally I got solutions, even though, not best solution but it worked. Thank #Marcin Nabialek and #lukasgeiter. It is just simply to through pivot table class_student.
$classes = Class::with(['students' => function($query){
$query->leftJoin('grades', function($join) {
$join->on('grades.student_id', '=', 'students.id');
$join->on('students.id', '=', 'class_student.student_id');
$join->on('class_student.class_id', '=', 'grades.class_id');
})
}])->get()->toJSON();
It took too much time bcoz passing through many join tables.
Hoping to get better solutions.
Related
Ok.
I have three tables
products
--product_id
--product_name
--product_type_id
--price15
--price23
--description
--bonus_points
--image
productTypes
--product_type_id
--product_type_name
productQuantities
--id
--product_id
--warehouse_id
--quantity
Products are placed in different warehouses so I have to keep tracks of its numbers
And has relationships are like this
class Product extends Model
{
public function productType() {
return $this->belongsTo('App\Models\ProductType','product_type_id','product_type_id');
}
public function productQuantities() {
return $this->hasMany('App\Models\ProductQuantity','product_id','product_id');
}
}
What I want to get is all columns from products and product type name from productType, sum of quantity from productQuantities, so I can perform search on those column values later on with where().
How can I get these columns with Eloquent?
I know I could get them with raw SQL commands but I need to do this way for compatibility reasons.
I tried this way before I ask the question.
But model relations just stopped working with no errors. Values just got emptied out from the other parts of the page.
$products = Product::selectRaw('products.*, productTypes.product_type_name, sum(product_quantities.quantity) as quantitySum')
->leftjoin('productTypes','products.product_type_id','=','productTypes.product_type_id')
->leftjoin('productQuantities','products.product_id','=','productQuantities.product_id')
->where('products.product_id','like','%'.$searchID.'%')
->where('product_name', 'like', '%'.$searchName.'%')
->where('product_type_name', 'like', '%'.$searchType.'%')
->where(function($q) use ($searchPrice) {
$q->where('price15','like','%'.$searchPrice.'%')
->orwhere('price23','like','%'.$searchPrice.'%');
})
->where('points', 'like', '%'.$searchPoints.'%')
->groupBy('products.product_id')
->orderByRaw($query)
->paginate($paginateBy);
Working version before this was simple.
Product::leftjoin('productTypes','products.product_type_id','=','productTypes.product_type_id')
->select('products.*','productTypes.product_type_name')
->where('products.product_id','like','%'.$searchID.'%')
->where('product_name', 'like', '%'.$searchName.'%')
->where('product_type_name', 'like', '%'.$searchType.'%')
->where(function($q) use ($searchPrice) {
$q->where('price15','like','%'.$searchPrice.'%')
->orwhere('price23','like','%'.$searchPrice.'%');
})
->where('points', 'like', '%'.$searchPoints.'%')
->orderByRaw($query)
->paginate($paginateBy);
And I thought any kind of join methods doesn't seem to be working well with Eloquent relationship? But older one has leftjoin method as well.
I have not tested this (and am assuming you want to group on product_type_name but you should be able to do something along the lines of:
$results = Product::with(['productType','productQuantities'])
->select(DB::raw('products.*,
productType.product_type_name,
sum(productQuantities.quantity) as "QuantitySum"'))
->groupBy('productType.product_type_name')
->get();
OR
$results = DB::table('products')
->join('productType', 'productType.product_type_id', '=', 'products.product_type_id')
->join('productQuantities', 'productQuantities.product_id', '=', 'products.product_id')
->select(DB::raw('products.*,
productType.product_type_name,
productType.product_type_name,
sum(productQuantities.quantity) as "QuantitySum"'))
->groupBy('productType.product_type_name')
->get();
Then you should be able to access the aggregated quantities using (in a loop if you wanted) $results->QuantitySum.
you can get it with eager loading and aggregating. For example, you need to query products has product type name like "new product" and quantity greater than 1000:
Product::with("productType")
->whereHas("productType", function ($query) {
$query->where("product_type_name", "like", "new product");
})
->withCount(["productQuantities as quantity_count" => function ($query) {
$query->selectRaw("sum(quantity)");
}])
->having("quantity_count", ">", 1000)
->get();
you can get through relationship
$product->productType->product_type_name
and attribute:
$product->quantity_count
$products = Product::withsum('productQuantities','quantity')
->leftjoin('product_types','products.product_type_id','=','product_types.product_type_id')
Gives me the result that I wanted. And didn't break the other parts.
But I'm still confused why with() and withSum() didn't work together.
Is it because products belongs to productTypes maybe
I'm using a Roles package (similar to entrust). I'm trying to sort my User::all() query on roles.id or roles.name
The following is all working
User::with('roles');
This returns a Collection, with a Roles relation that also is a collection.. Like this:
I'm trying to get all users, but ordered by their role ID.
I tried the following without success
maybe because 'roles' returns a collection? And not the first role?
return App\User::with(['roles' => function($query) {
$query->orderBy('roles.id', 'asc');
}])->get();
And this
return App\User::with('roles')->orderBy('roles.id','DESC')->get();
None of them are working. I'm stuck! Can someone point me in the right direction please?
You can take the help of joins like this:
App\User::join('roles', 'users.role_id', '=', 'roles.id')
->orderBy('roles.id', 'desc')
->get();
Hope this helps!
You can make accessor which contains role id or name that you want to sort by.
Assume that the accessor name is roleCode. Then App\User::all()->sortBy('roleCode') will work.
Here's the dirty trick using collections. There might be a better way to achieve this(using Paginator class, I guess). This solution is definitely a disaster for huge tables.
$roles = Role::with('users')->orderBy('id', 'DESC')->get();
$sortedByRoleId = collect();
$roles->each(function ($role) use($sorted) {
$sortedByRoleId->push($role->users);
});
$sortedByRoleId = $sortedByRoleId->flatten()->keyBy('id');
You can sort your relations by using the query builder:
notice the difference with your own example: I don't set roles.id but just id
$users = App\User::with(['roles' => function ($query) {
$query->orderBy('id', 'desc');
}])->get();
See the Official Laravel Docs on Constraining Eager Loading
f you want to order the result based on nested relation column, you must use a chain of joins:
$values = User::query()->leftJoin('model_has_roles', function ($join)
{
$join>on('model_has_roles.model_id', '=', 'users.id')
->where('model_has_roles.model_type', '=', 'app\Models\User');})
->leftJoin('roles', 'roles.id', '=', 'model_has_roles.role_id')
->orderBy('roles.id')->get();
please note that if you want to order by multiple columns you could add 'orderBy' clause as much as you want:
->orderBy('roles.name', 'DESC')->orderby('teams.roles', 'ASC') //... ext
check my answer here:
https://stackoverflow.com/a/61194625/10573560
In plain English: I have three tables. subscription_type which has many email_subscriptions which has many emails.
I'm trying to select all email_subscription records that have a particular subscription_type, that also don't have any associated email records that have a status of Held.
The particular bit I am stuck on is only returning email_subscriptions which have zero emails (with an additional where clause stacked in there described above).
Using Eloquent, I've been able to get a bit of the way, but I don't have any idea how to select all the records that have a relationship count of zero:
$subscriptionsWithNoCorrespondingHeldEmail = EmailSubscriptions::whereHas('subscriptionType', function($q) {
$q->where('name', 'New Mission');
})-; // What do I chain here to complete my query?
Additionally, is this even possible with Eloquent or will I need to use Fluent syntax instead?
You can use the has() method to query the relationship existence:
has('emails', '=', 0)
Eg:
$tooLong = EmailSubscriptions::whereHas('subscriptionType', function($q) {
$q->where('name', 'New Mission');
})->has('emails', '=', 0)->get();
Edit
You can do more advanced queries with the whereHas() and whereDoesntHave() methods:
$tooLong = EmailSubscriptions::whereHas('subscriptionType', function($q) {
$q->where('name', 'New Mission');
})
->whereDoesntHave('emails', function ($query) {
$query->where('status', '=', 'whatever');
})->get();
OK what I have under stand from your Question is you would like to have a All Emails which have
specific subscription_type, Zero(0) association and status = status
If yes so you canuse array in where statement.
Like:
$q->->where(array('status' => 'status','subscription_type'=>'what ever you want));
Im working in a sensitive section of my app and i need to make sure to minimize the number of querys. I can easily do this with a multiple joins. The question is: is there a way to do this with beauty?
Elequent relationships are a good place to start but most of the time it requires multiple query.
The eager loading method used in this article looks alot better but still requires at least 2 querys and uses a whereIn statement instead of a join.
Article Example Of Eager Loading:
$users = User::with('posts')->get();
foreach($users as $user)
{
echo $user->posts->title;
}
Using Eager Loading, Laravel would actually be running the following
select * from users
select * from posts where user_id in (1, 2, 3, 4, 5, ...)
My current solution is to use laravel scopes in a way not intented.
public static function scopeUser($query) // join users table and user_ranks
{
return $query->join('users', 'users.id', '=', 'posts.user_id')
->join('user_ranks', 'users.rank_id', '=', 'user_ranks.id');
}
public static function scopeGroup($query,$group_id) // join feeds,group_feeds (pivot) and groups tables
{
return $query->join('feeds', 'feeds.id', '=', 'posts.feed_id')
->join('group_feed', 'feeds.id', '=', 'group_feed.feed_id')
->join('groups', 'groups.id', '=', 'group_feed.group_id')
->where("groups.id","=",$group_id);
}
The resulting query looks like this:
$posts = Post::take($limit)
->skip($offset)
->user() // scropeUser
->group($widget->group_id) // scropeGroup
->whereRaw('user_ranks.view_limit > users.widget_load_total')
->groupBy('users.id')
->orderBy('posts.widget_loads', 'ASC')
->select(
'posts.id AS p_id',
'posts.title AS p_title',
'posts.slug AS p_slug',
'posts.link AS p_link',
'posts.created_on AS p_create_on',
'posts.description AS p_description',
'posts.content AS p_content',
'users.id AS u_id',
'users.last_name AS u_last_name',
'users.first_name AS u_first_name',
'users.image AS u_image',
'users.slug AS u_slug',
'users.rank_id AS u_rank',
'user_ranks.name AS u_rank_name',
'user_ranks.view_limit AS u_view_limit'
)
->get();
Because of column name collisions i then need a huge select statement. This works and produces a single query, but its far from sexy!
Is there a better way to deal with big joined querys?
You could try to actually add the selects with aliases in the scope.
Note: This is totally untested
public static function scopeUser($query) // join users table and user_ranks
{
foreach(Schema::getColumnListing('users') as $column){
$query->addSelect('users.'.$related_column.' AS u_'.$column);
}
$query->addSelect('user_ranks.name AS u_rank_name')
->addSelect('user_ranks.view_limit AS u_view_limit');
$query->join('users', 'users.id', '=', 'posts.user_id')
->join('user_ranks', 'users.rank_id', '=', 'user_ranks.id');
return $query;
}
There is also no need to alias the post columns with a p_ prefix... But if you really want to, add another scope that does that and use addSelect()
I have a table of itineraries. An itinerary belongs to a customer and has multiple days. A package is assigned to each of these days. I want to be able to produce a manifest showing which customers are allocated to a package and on which days.
I'm struggling with Eloquent, because you can't do queries beyond a one-to-Many relationship
What i want to do is this:
return $this->package->where('PackageID, $id)->itineraryDay->itinerary->customer->select('CustomerID', 'Date')
But can only really achieve it using the query builder:
return DB::connection($this->connection)
->table('t_package as PA')
->join('t_itinerary_day_map as IDM', 'IDM.PackageID', '=', 'PA.PackageID')
->join('t_itinerary_day as ID', 'IDM.ItineraryDayID', '=', 'ID.ItineraryDayID')
->join('t_itinerary as IT', 'IT.ItineraryID', '=', 'ID.ItineraryID')
->join('t_customer as CC', 'CC.ItineraryID', '=', 'IT.ItineraryID')
->where('PA.PackageID', $id)
->select('CC.CustomerID', 'ID.Date')
->distinct()
->get();
I really want to use Eloquent as I hate hardcoding table names and i've already created relationships for these models, but can't see any way around it
I believe you could do something like this to find customers that have a package with the given ID:
$packageId = 42;
$customers = $customer->whereHas('packages', function($q) use($packageId){
return $q->where('package_id', $packageId);
})->get();
How would that work for what you want?
I'll have to make few assumptions on your relationship but it seems doable.
If one ItineraryDay belongs to one Itinerary. And one Itinerary belongs to one Customer. And one ItineraryDay may have more than one Package.
$packageID = 111;
$itineraryDays = ItineraryDay::with('itinerary.customer')
->whereHas('package', function($q) use($packageID) {
$q->where('PackageID', $packageID);
})
->get();
foreach($itineraryDays as $itineraryDay) {
var_dump($itineraryDay);
var_dump($itineraryDay->itinerary->customer);
}
I'm not sure if i get your relationship method naming correct, but hopefully this works.