Change the form of an array (PHP) - php

Question

I have a huge, complicated issue in my php app. Here are the details:
I currently have this as my array (var dumped):
array (size=6)
0 => string '11/04/15' (length=8)
1 => string '15/04/15' (length=8)
2 => string '19/04/15' (length=8)
3 => string '1' (length=1)
4 => string '1' (length=1)
5 => string '3' (length=1)
But I want it displayed as:
array (size=6)
array(size=2)
string '11/04/15' (length=8)
string '1' (length=1)
array(size=2)
string '15/04/15' (length=8)
string '1' (length=1)
array(size=2)
string '19/04/15' (length=8)
string '3' (length=1)
As you can see I would like to add sub arrays, reorder the structure and remove the keys. The starter array values change so there could be more dates/less dates and numbers. Also the its linked, the key 0 should be bulked with key 3 and key 1 bulked with key 4 etc. I think that's enough information.
PS: I'm trying to arrange the data for Chart PHP's Bar Graph (http://www.chartphp.com/).

Answer 1

My approach would be the following:
Go through the array values with a foreach-loop and find out when the first number starts (in this case, it's the 4. element)
Save the number inside of a variable.
Create a new array
Go through the old array again and get the pairs, then push them into the new array.
The code would be similar to this:
<?
$old = array("date1","date2","date3",1,2,3);
$n = null;
foreach($old as $k => $v){
if(/*CHECK HERE IF $v is NOT A DATE anymore*/){
$n = $k;
break;
}
}
$new = array();
foreach($old as $k => $v){
if($k < $n){
$temp = array($v, $old[$k+$n]);
array_push($new, $temp);
}
}
var_dump ($new);
?>

Answer 2

This should work for you:
Since it is pretty obvious I'm going to assume, that the pattern behind your expected results should be to combine the numbers with the dates which are sorted ASC.
So here I first get all dates into an array with preg_grep(). Then I also get the numbers by getting the array_diff() from the original array and the dates array.
Then I sort both arrays ASC and the $dates array I sort with usort() where I compare the timestampes which I get with strtotime() and the $numbers array I sort simply with sort().
At the end I simply loop through both arrays with array_map() where I then create the expected result.
<?php
$arr = [
"19/04/15",
"11/04/15",
"15/04/15",
"3",
"1",
"1",
];
$dates = preg_grep("/\d{2}\/\d{2}\/\d{2}/", $arr);
$numbers = array_diff($arr, $dates);
sort($numbers);
usort($dates, function($a, $b){
if(strtotime($a) == strtotime($b))
return 0;
return strtotime($a) < strtotime($b) ? 1 : -1;
});
$result = array_map(function($v1, $v2){
return [$v1, $v2];
}, $dates, $numbers);
print_r($result);
?>
output:
Array
(
[0] => Array
(
[0] => 11/04/15
[1] => 1
)
[1] => Array
(
[0] => 15/04/15
[1] => 1
)
[2] => Array
(
[0] => 19/04/15
[1] => 3
)
)