What is the difference between a public = $default and public = $test? - php

I'm trying to learn something new by going through CakePHP's tutorials and in the section where you link a database.php to your MAMP/SQL, it asks for you to change the information in an array calls public $default. However there is also a public $test array in the same file.
What is the public $test array for? I know I can run my page by just linking the $default but does the $test serve a purpose?
ie:
class DATABASE_CONFIG {
public $default = array(
'datasource' => 'Database/Mysql',
'persistent' => false,
'host' => 'localhost',
'login' => 'admin',
'password' => 'admin',
'database' => 'blog_tutorial',
'prefix' => '',
//'encoding' => 'utf8',
);
public $test = array(
'datasource' => 'Database/Mysql',
'persistent' => false,
'host' => 'localhost',
'login' => 'admin',
'password' => 'admin',
'database' => 'blog_tutorial',
'prefix' => '',
//'encoding' => 'utf8',
);
}
Just curious, thanks!

Related

How does DataSource test in cakephp 2

We have custom DataSource and want to test that verifies the data after find method execute equals to one not customized.As I thought it, it would be possible if we can change Datasource in test code.I try many case, but I couldn't make it work.
public $default = [
'datasource' => 'CustomPostgres',
'persistent' => false,
'host' => 'localhost',
'port' => '5432',
'login' => 'hoge',
'password' => 'hogehoge',
'database' => 'prod',
'schema' => 'public',
'prefix' => '',
'encoding' => 'utf8'
];
public $test = [
'datasource' => 'CustomPostgres',
'persistent' => false,
'host' => 'localhost',
'port' => '5432',
'login' => 'hoge',
'password' => 'hogehoge',
'database' => 'test_prod',
'schema' => 'public',
'prefix' => '',
'encoding' => 'utf8'
];
public $old = [
'datasource' => 'Database/Postgres',
'persistent' => false,
'host' => 'localhost',
'port' => '5432',
'login' => 'hoge',
'password' => 'hogehoge',
'database' => 'dev',
'schema' => 'public',
'prefix' => '',
'encoding' => 'utf8'
];
public $test_old = [
'datasource' => 'Database/Postgres',
'persistent' => false,
'host' => 'localhost',
'port' => '5432',
'login' => 'hoge',
'password' => 'hogehoge',
'database' => 'test_dev',
'schema' => 'public',
'prefix' => '',
'encoding' => 'utf8'
];
//try1
$this->Model->setDataSource('test_old');
//try2
ConnectionManage::create('test_old',///);
//try3
////in fixture File and ClassRegistry:Init("Model")
$useDbConfig = "old";
////inner start::up
ClassRegistry:Init("Model");
//try4 extends model
ModelForOldSetting extends Model{
$useDbConfig = "old";
}
Above codes didn't work and it always emit error says
MissingConnectionException: Database connection "Postgres" is missing, or could not be created ,when running test however it works fine when setting default datasource Database/Postgres running local browser without test.
So, I'm really confused why Database connection "Postgres" is missing.Any idea makes me appreciate to them.
I finally found irritating and stupid irritating code by outer database.php file overrides datasources' setting.Following code works fine after appropriate settings.
ModelForOldSetting extends Model{
$useDbConfig = "dev";
$useTables = "models";
}
ClassRegistry:Init("ModelForOldSetting");
$model = $this->getMockForModel('ModelForOldSetting');

error in baking database in cake php

I have created my database and edited my database in config file. I have filled database.config with the required details and my localhost/cakephp is also completely green but I dont know what is wrong. Below is my database coding in config.
<?php
class DATABASE_CONFIG {
public $test = array(
'datasource' => 'Database/Mysql',
'persistent' => false,
'host' => 'localhost',
'login' => 'user',
'password' => 'password',
'database' => 'test_database_name',
);
public $default = array(
'datasource' => 'Database/Mysql',
'persistent' => false,
'host' => 'localhost',
'login' => 'root',
'password' => '',
'database' => 'MyKitchen',
);
}
Remove (,) comma after array end , as display below,
public $test = array(
'datasource' => 'Database/Mysql',
'persistent' => false,
'host' => 'localhost',
'login' => 'user',
'password' => 'password',
'database' => 'test_database_name' // remove (,) comma
);
public $default = array(
'datasource' => 'Database/Mysql',
'persistent' => false,
'host' => 'localhost',
'login' => 'root',
'password' => '',
'database' => 'MyKitchen' // remove (,) comma
);

Cakephp 1.3 appfog database configuration

i just moving my blog to appfog. I am currently using cakephp 1.3.x. I know I need to upgrade, I am already working on it. But in the meantime, I would like to get my blog working. I am not able to configure the database file.
I know we need to add
$services_json = json_decode(getenv('VCAP_SERVICES'),true);
$af_mysql_config = $services_json['mysql-5.1'][0]['credentials'];
// Database settings
Configure::write('Database.config', array(
'default' => array(
'datasource' => 'Database/Mysql',
'persistent' => false,
'host' => $af_mysql_config['hostname'],
'login' => $af_mysql_config['username'],
'password' => $af_mysql_config['password'],
'database' => $af_mysql_config['name'],
'prefix' => '',
'encoding' => 'utf8',
)
));
I just want to know how we can send the setting to database config.
I appreciate any help.
I just did this:
class DATABASE_CONFIG {
public $default = null;
function __construct() {
$services = getenv("VCAP_SERVICES");
$services_json = json_decode($services, true);
$mysql_config = $services_json["mysql-5.1"][0]["credentials"];
$this->default = array(
'driver' => 'mysql',
'persistent' => false,
'host' => $mysql_config["hostname"],
'login' => $mysql_config["user"],
'password' => $mysql_config["password"],
'database' => $mysql_config["name"],
'prefix' => '',
'port' => $mysql_config["port"],
);
}
}

error with using variables as associative array value in php

For some reason this is giving me the follow error: syntax error, unexpected T_VARIABLE:
$mysql = json_decode(getenv("VCAP_SERVICES"));
$mysql = $mysql["mysql-5.1"][0]["credentials"];
class DATABASE_CONFIG {
public $default = array(
'datasource' => 'Database/Mysql',
'persistent' => false,
'host' => 'localhost',
'port' => $mysql['port'], // <-- Line with error
'login' => $mysql['username'],
'password' => $mysql['password'],
'database' => $mysql['name'],
'prefix' => ''
//'encoding' => 'utf8',
);
public $test = array(
'datasource' => 'Database/Mysql',
'persistent' => false,
'host' => 'localhost',
'login' => 'user',
'password' => 'password',
'database' => 'test_database_name',
'prefix' => '',
//'encoding' => 'utf8',
);
}
I know you can use variables as values in arrays, so what is going on?
It looks like you're trying to set the default value of a property to a variable.
You can't do that, not even inside an array. This is half PHP's parser sucking, a quarter of PHP's lack of appropriate error message, and a bit of sanity.
You'll need to do it from within the constructor instead by passing in $mysql:
$config = new DATABASE_CONFIG($mysql);
class DATABASE_CONFIG {
public $default = array(
'datasource' => 'Database/Mysql',
'persistent' => false,
'host' => 'localhost',
'port' => null,
'login' => null,
'password' => null,
'database' => null,
'prefix' => ''
//'encoding' => 'utf8',
);
public function __construct($mysql) {
$this->default['port'] = $mysql['port']; // etc
}
}
$mysql has no scope inside the class.
You need to inject it as an argument into the class constructor, and then define your array values for the class properties
You're trying to reference a variable inside a class which is defined outside of that class.
PHP has no idea what $mysql is inside of that class definition.

Need a script to edit file

<?php
class DATABASE_CONFIG {
public $default = array(
'datasource' => 'Database/Mysql',
'persistent' => false,
'host' => 'hostname',
'login' => 'username',
'password' => 'password',
'database' => 'database_name',
'prefix' => '',
//'encoding' => 'utf8',
);
public $test = array(
'datasource' => 'Database/Mysql',
'persistent' => false,
'host' => 'hostname',
'login' => 'username',
'password' => 'password',
'database' => 'database_name',
'prefix' => '',
//'encoding' => 'utf8',
);
}
There are some default value in login,password and database. How can i write a script to edit the login,password and database ?
php file contains your example text:
kent$ awk '/login/{l++;if(l>1)gsub(/root/,"newLogin");}
/password/{p++;if(p>1)gsub(/xxx/,"newPwd");}
/database/{d++;if(d>1)gsub(/xxx/,"newDB");} 1' php
<?php
class DATABASE_CONFIG {
public $default = array(
'datasource' => 'Database/Mysql',
'persistent' => false,
'host' => 'localhost',
'login' => 'root',
'password' => 'xxx',
'database' => 'xxx',
'prefix' => '',
//'encoding' => 'utf8',
);
public $test = array(
'datasource' => 'Database/Mysql',
'persistent' => false,
'host' => 'localhost',
'login' => 'newLogin',
'password' => 'newPwd',
'database' => 'cake_test_db',
'prefix' => '',
//'encoding' => 'utf8',
);
}
this only changes the blocks after your $default block. and, only default value will be changed. e.g. in your $test, 'database' => 'cake_test_db' the value is not the default 'xxx', so it would not be changed.
if you like you can put new value in variable, and passing to awk with -v.
edit
if you want to change all values, (including $default block), it would be easier, check the lines below: (same as above, only defalut values (root, xxx,xxx) would be changed.
kent$ awk '/login/{gsub(/root/,"newLogin");}
/password/{gsub(/xxx/,"newPwd");}
/database/{gsub(/xxx/,"newDB");} 1' php
<?php
class DATABASE_CONFIG {
public $default = array(
'datasource' => 'Database/Mysql',
'persistent' => false,
'host' => 'localhost',
'login' => 'newLogin',
'password' => 'newPwd',
'database' => 'newDB',
'prefix' => '',
//'encoding' => 'utf8',
);
public $test = array(
'datasource' => 'Database/Mysql',
'persistent' => false,
'host' => 'localhost',
'login' => 'newLogin',
'password' => 'newPwd',
'database' => 'cake_test_db',
'prefix' => '',
//'encoding' => 'utf8',
);
}
edit2
this works for your new example in question.
sed '/login/{s/username/newLOGIN/}; /password/{s/password/newPWD/2}; /database/{s/database_name/newDB/}' php
<?php
class DATABASE_CONFIG {
public $default = array(
'datasource' => 'Database/Mysql',
'persistent' => false,
'host' => 'hostname',
'login' => 'newLOGIN',
'password' => 'newPWD',
'database' => 'newDB',
'prefix' => '',
//'encoding' => 'utf8',
);
public $test = array(
'datasource' => 'Database/Mysql',
'persistent' => false,
'host' => 'hostname',
'login' => 'newLOGIN',
'password' => 'newPWD',
'database' => 'newDB',
'prefix' => '',
//'encoding' => 'utf8',
);
}
#!/usr/bin/awk -f
BEGIN { FS="'"
usr[0] ="usr1" ; usr[1] = "user2"
pass[0] ="pass1" ; pass[1] = "pass2"
db[0] ="db1" ; db[1] = "db2"
}
{
if ($2 == "login") {
$0="\t'login' => '" usr[u] "',"
u++
}
if ($2 == "password") {
$0="\t'password' => '" pass[p] "',"
p++
}
if ($2 == "database") {
$0="\t'database' => '" db[d] "',"
d++
}
print
}

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