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Please help me create links using a php foreach loop that iterates over an array which contains the names of navbar links for a webpage.
Currently my loop creates links but when you click on them an error 404 page and displays in the url (for example when clicking on "blog"):
...homebrew-actual/blog.php>Blog <a></li><li><a href="
I would like the url to go to:
... homebrew-actual/blog.php
without the html tags.
Here is my current PHP loop:
<nav>
<ul>
<?php
$navOptions = array('index', 'showcase','about','blog','contact','forums');
foreach($navOptions AS $navOption) {
if ($navOption == $currentPage) {
print '<li>' . '' . ucfirst($navOption) . '</li>';
} else {
echo '<li>' . '<a href="/homebrew-actual/' . $navOption . '.php>' . ucfirst($navOption) . '</a></li>';
}
}
?>
<li class="special">Shop</li>
</ul>
</nav>
Please help me identify a solution to create a links for a navbar using an array with the link names and use a for loop to link to those pages.
Thank you for checking out this question.
You forgot a ":
print '<li>' . '' . ucfirst($navOption) . '</li>';
^--start href ^---end of href, missing "
Since you never close the href string, you end up with broken HTML.
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I'm trying to make a dynamic tab with PHP. please can someone help me out just need to filter where the category parent = 0.
$parent_category_html.= '<span class="'.$current_tab.'"><a id="tab-'
. $category['id'].'-link" href="#tab-'.$category['id']
. '" role="tab" aria-selected="false" aria-controls="tab-1" class="tab-link">'
. **$category['title'] is it possible to put an if statement here to filter the title where parent = 0**
. '</a>
From comments on the question, it sounds like what you're asking is:
How can I conditionally include a value in my string?
For that you'd use the ternary conditional operator. The operation itself would look like this:
$parent == 0 ? $category['title'] : ''
It essentially means:
If $parent equals 0, $category['title'], else empty string
The whole operation resolves to the resulting value, so you can wrap the whole operation in parentheses and drop it anywhere you would a variable. So something like this:
$parent_category_html.= 'your various HTML code...'
. ($parent == 0 ? $category['title'] : '')
. 'the rest of your HTML code...';
You can add if statement before:
if (statement)
$parent_category_html .= '...';
or try to use ternary operator
$parent_category_html .= "<div>" . ($condition ? 'output if true' : 'output if false') . "</div>";
$parent_category_html.= '<span class="'.$current_tab.'"><a id="tab-' . $category['id'].'-link" href="#tab-'.$category['id'] . '" role="tab" aria-selected="false" aria-controls="tab-1" class="tab-link">';
if ($pareent_id ==0) {
$parent_category_html.= '...';
}
$parent_category_html.= '</a>';
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echo <a href = 'test.php'> "CategoryID: " . $row["CategoryID"]. " - Category Name: ".$row["CategoryName"]. </a> "<br>";
This is what i have an is not working properly.
This:
echo "<a href = 'test.php'>CategoryID: {$row['CategoryID']} - Category Name: {$row['CategoryName']}</a><br />";
I am using the { and } as they allow you to include an array in a string and ignore the concatenation which I find harder to read.
I find it funny that you can loop through a MySQL array but can't echo a simple string :P
Some links (teach a man to fish...):
W3Schools
PHP documentation
Codecademy
Tutorials Point
Try this:
<?php
$link = "";
$link = sprintf("<a href = 'test.php'>CategoryID: %d - Category Name: %s </a><br />", $row['CategoryID'], $row['CategoryName']);
echo $link;
?>
Assuming that $row['CategoryID'] is an integer and $row['CategoryName'] is a string.
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could someone please direct me to a simple (basic easy) tutorial or resource page of how to use hyperlinks in a website to display the results of a select statement
To be precise - I am working on the footer section of my website http://www.mandyevansartist.com
when someone clicks on the words 'coloured pencils' I would like them to be taken to the catagory.php page and be shown an array from the database
I know this is possible because I already have made it work by clicking an image - (there is an area in the http://www.mandyevansartist.com/gallery.php page that says 'click on a picture to see others in that catagory')
I have achieved this by
<?php
session_start();
include 'header.php';
echo '<h1>CLICK ON AN IMAGE TO SEE OTHERS IN THAT CATAGORY</h1>';
$con = mysqli_connect("*","*","*","*");
$db = mysqli_select_db("images", $con);
$answer = mysqli_query($con,"SELECT image FROM images where HEAD = 'true'");
echo '<div id = "list">';
echo '<ul>';
while ($row = mysqli_fetch_array($answer)) {
$pic = $row[image];
$link ="<a href = 'catagory.php?id=".$row[image]."'>" . ' <img src="'.$pic.'" style ="height:222px;"/> '. "</a>";
echo '<li>' .$link.'</li>';
}
echo '</ul>';
echo '</div>';
?>
At this point my footer.php is mainly html (enclosed in an echo'') with links going to nowhere
<div id="footer-one">
<h1>GALLERY</h1>
<p><a href = "#" >people pictures</a></p>
<p><a href = "#" >romance</a></p>
<p><a href = "#" >seascapes</a></p>
<p><a href = "#" >under the ocean</a></p>
<p><a href = "#" >paintings</a></p>
<p><a href = "#" >love heart series</a></p>
<p><a href = "#" >new works</a></p>
</div><!--/footer-one-->
one of the ways I have tried to insert a mysqli query into it
<h1>GALLERY</h1>';
$answer=mysqli_query($con,"SELECT image FROM images WHERE catagory = pencils");
while ($answer2 = mysqli_fetch_array($answer));
$link = <p>family portraits</p>
echo '<p>' .$link.'</p>';
echo' <p><a href = "#" >coloured pencils</a></p>
which just comes up with a parse error - unexpected "<"
I am looking for a tutorial to guide me through this process because i have looked and looked and cant find one
The error parse error - unexpected "<" is due to some missing stuff like ', " and {}. Try following fixes.
<?php
$answer = mysqli_query($con,"SELECT image FROM images WHERE catagory = pencils");
while ($answer2 = mysqli_fetch_array($answer));
{
$img = $answer2['image'];
$link = "<a href = 'catagory.php?id=$img'>family portraits</a></p>";
}
echo '<p>'.$link.'</p>';
echo '<p><a href = "#" >coloured pencils</a></p>';
?>
From the given code, I have come up with these fixes. But there may be some changes as per your requirements.
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this string is breaking my code and I am not sure why. If anyone can help me correct it I would appreciate it.
if ($p == $url) { echo '<li><a class="active" href="index.php?p=' . $url . '">'
. $label . '</a></li>'; } else { echo '<li>' . $label . '</li>'; }
htmlspecialchars(urlencode($url)) and htmlspecialchars($label). The rest seems fine.
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Closed 9 years ago.
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I am trying to echo a div class <div class="Box"> but not working. Can anyone help? Thanks.
echo '<div class="Box">
echo Anchor(T('Edit My Account'), '/profile/edit', FALSE, array('class' => 'Popup EditAccountLink'));
echo "<br />";
echo Anchor(T('Change My Password'), '/profile/password', FALSE, array('class' => 'Popup PasswordLink'));
echo "<br />";
$Inbox = 'Inbox';
$CountUnreadConversations = $Session->User->CountUnreadConversations;
if (is_numeric($CountUnreadConversations) && $CountUnreadConversations > 0)
$Inbox .= ''.$CountUnreadConversations.'';
echo Anchor(T('Inbox'), '/messages/all', 'Inbox');
</div>'
Your first and last lines are wrong, missing proper quotation marks and also an echo on the last line. It should be:
echo '<div class="Box">';
.... rest of code here...
echo '</div>';
You haven't terminated the string with ';.
echo '<div class="Box">';
Enable the error_reporting to E_ALL. Read on documentation. After this, you know what is happen.
This is a parse error. Enable error_reporting to E_ALL.