This question already has answers here:
Convert one date format into another in PHP
(17 answers)
Closed 7 years ago.
I have a string representing a date. It's format is MM/DD/YYYY. I need to submit it via API to a service that requires MMDDYYYY. Should I bother with overloading this string onto some date class and 'export' as MMDDYYY or just delete the "/" sub-string wherever I find it?
Any other neat way of doing that I wasn't aware of?
Since you just need to remove the '/' I would do that with the following code, it will eliminate the overhead of parsing the date.
$newDate = str_replace ('/', '', $oldDate);
You can use the DateTime object in PHP (http://php.net/manual/en/class.datetime.php)
Here is how I would do it:
<?php
$myDate = '05/15/2015';
$date = DateTime::createFromFormat('m/d/Y H:i:s', "$myDate 00:00:00");
$newDate = $date->format('mdY');
echo $newDate . PHP_EOL;
?>
Related
This question already has answers here:
Converting string to Date and DateTime
(13 answers)
Convert one date format into another in PHP
(17 answers)
Closed 3 years ago.
I'm trying to convert a string of numbers I am pulling from a db that looks like this '010219', representing January 2, 2019. I cannot find a way to convert this into 2019-01-02 using php, I just keep getting today's date from the functions I am trying.
Needs to be accomplished with no separators in original string.
There are a variety of ways to accomplish this, however the most concise is probably to use date_create_from_format.
An example is here:
$date = date_create_from_format('dmy', '010219');
This will output a Date as so:
echo date_format($date, 'Y-m-d');
Outputs: 2019-02-01
The date_create_from_format function accepts a parameter that defines the format of the date. In this case, the format is dmy which means:
d - Day of month as two-digit number (01-31)
m - Month of year as two-digit number (01-12)
y - Year as two-digit number
The documentation for date_create_from_format is here.
have you tried something like this?
<?php
$str="010219";
$date = DateTime::createFromFormat('dmy', $str);
echo $date->format('Y-m-d'); //2019-02-01
$time = strtotime('10/16/2003');
$newformat = date('Y-m-d',$time);
echo $newformat;
// 2003-10-16
Please see source: Converting string to Date and DateTime
split and concatenate with preg_replace
$newformat = preg_replace("/^(\d\d)(\d\d)(\d\d)$/","20$3-$1-$2","010219");
This question already has answers here:
Convert one date format into another in PHP
(17 answers)
Closed 4 years ago.
I have a string like this "20180720171534449" which is a kind of time stamp, is there an easy way I can convert this using PHP and format it as a date or date and time that makes sense to a human?
TIA
Peter
You have an 'YmdHisv' format where v is miliseconds.
Miliseconds is not parsable (as I found out today) with date_create_from_format so you need to remove that first from the string with substr.
$s = "20180720171534449";
$date = date_create_from_format('YmdHis', substr($s,0,-3));
echo date_format($date, 'Y-m-d H:i:s'); //2018-07-20 17:15:34
https://3v4l.org/m1XNd
As Ghost pointed out milliseconds is parasble if using microseconds u instead.
$s = "20180720171534449";
$date = date_create_from_format('YmdHisu', $s);
echo date_format($date, 'Y-m-d H:i:s\.v'); //2018-07-20 17:15:34.449
This question already has answers here:
Convert one date format into another in PHP
(17 answers)
Closed 6 years ago.
I need to convert a date string in a format like bellow using PHP,
2015-07-30T08:05:00.917Z
I try to convert using the bellow code,
echo str_replace('+00:00', '.917Z', gmdate('c', strtotime('2016-04-05 00:00:00')));
This will create 2016-04-05T00:00:00.917Z This is not correct,Is there any function to create date like this format?
There are two ways to create date from String.
1. date_create_from_format
$date=date_create_from_format("DATE_FORMAT",$dateString);
2. $date=new DateTime();
$date=$date->createFromFormat("DATE_FORMAT", $dateString);
Using following link to get your DATE_FORMAT.
http://php.net/manual/en/function.date.php
You can do it as #Alok has mentioned in his answer.
Or similarly using the following code.
$date = DateTime::createFromFormat('U.u', microtime(TRUE));
echo $date->format('Y-m-d\TH:i:s.u\Z');
Note that the microsecond mentioned in your question is of 3 digits. But generally php date formatting outputs microseconds in 6 digits precision.
Like the above code outputs 2016-04-06T09:24:50.830000Z
So I think you have to do some hack there if the digit precision is important.
Pass it through the function formatTime. This creates a new DateTime object in PHP called $date that can also easily be manipulated if you need. The examples below formats the date in two different ways, both work.
Procedural Style:
function formatTime($millis) {
$date = new DateTime($millis);
return date_format($date, 'l, jS F Y \a\t g:ia');
}
Object Oriented Style:
function formatTime($millis) {
$date = new DateTime($millis);
return $date->format('l, jS F Y \a\t g:ia');
}
The format for date can be found at this link:
http://php.net/manual/en/function.date.php
Hope this helps.
This question already has answers here:
Convert one date format into another in PHP
(17 answers)
Closed 8 years ago.
I have the following datetime 2014-02-05 17:12:48 stored in a php variable named $reportDb["reportDate"].
Now, It is in Y-m-d H:i:s format, I want it in d/m/Y H:i:s format. How can I set or reformat this variable?
I tried with datetime::createformat but It doesn't works.
$formatted = date("d/m/Y H:i:s", strtotime($reportDb["reportDate"]))
If you want another method. Even if i would prefer the one already mentioned.
Output 05/02/2014 17:12:48
PHP 5.3 and older:
$dt = new DateTime('2014-02-05 17:12:48');
echo $dt->format(''d/m/Y H:i:s'');
PHP 5.4+:
$dt = (new DateTime('2014-02-05 17:12:48'))->format(''d/m/Y H:i:s'');
with the variable:
$dt = (new DateTime($reportDb["reportDate"]))->format(''d/m/Y H:i:s'');
If I understand you right, $reportDb["reportDate"] is already a DateTime object.
If so, all you need is ...
$reportDb["reportDate"]->format('d/m/Y H:i:s');
Cheers!
This question already has answers here:
Convert one date format into another in PHP
(17 answers)
Closed 9 years ago.
I tried converting
12-18-1997
to
18-12-1997
with this code
$new_date = date('d-m-Y', strtotime('12-18-1997'));
but it results in 18-12-1969
If I have to convert full date alongwith time then its converting fine but in the date I posted in question there is no time.
Use DateTime instead of strtotime():
$date = DateTime::createFromFormat( 'm-d-Y', '12-18-1997');
echo $date->format( 'd-m-Y');
You can see from this demo that it prints:
18-12-1997
strtotime is good, but it's not psychic or omniscient. you're feeding it a time string it's not able to parse properly:
php > var_dump(strtotime('12-18-1997'));
bool(false)
Since you simply assumed it's succeeding, you feed that false back to date(), where it's type-cast to an integer 0. However, your result is impossible, since int 0 as a date is Jan 1/1970. With timezone conversions, it'd be 31-12-1969 for you, NOT 18-12.
If you can't feed strtotime a format it understands, then use date_create_from_format and TELL it what what the format is:
$date = date_create_from_format('m-d-Y', '12-18-1997');
$text = date('d-m-Y', $date);