json object in php not being read - php

Question

I want to pass username and password to a php script and check in the database. On the client side I use the following script to make a json object and post it to the php file.
var myobj = {};
myobj["usrname"]= $( "#customer option:selected" ).text();
myobj["usrpass"]= $("#psw").val();
var myjson = JSON.stringify(myobj);
$.ajax({
method: "POST",
url: "checkpass.php",
data: myjson
})
.done(function( msg ) {
alert( msg );
});
On the server side, when I see in firebug, the post is passed as
Parametersapplication/x-www-form-urlencodedDo not sort
{"usrname":"XXXXXXX...
JSON
usrname
"XX"
usrpass
"justdoit"
Source
{"usrname":"XXX","usrpass":"justdoit"}
however when i run the php script to check the query the it returns an error
$usrname = $_POST['usrname'];
$usrpass = $_POST['usrpass'];
$sql = "select count(*) from glusers where EmpName='$usrname' and EmpPass='$usrpass'";
$result = $conn->query($sql);
if($result >0){
$output = 'Success';
} else
{
$output = 'fail';
}
I have tried through all the posts but cannot get this to work.
Thanks in advance.
Regards,

Answer 1

Echo and die the statement in order for ajax to have a success event
Js File
var myobj = {};
myobj["usrname"] = 'myUsername';
myobj["usrpass"] = 'myPassword';
$.ajax({
type: "post",
url: "url",
dataType: "json",
data: {post_data: myobj},
contentType: "application/x-www-form-urlencoded",
success: function (responseData) {
console.log(responseData);
},
error: function (errorThrown) {
console.log(errorThrown);
}
});
PHP action File
/** if we print post we will get the following array * */
//print_r($_Post);
//die()
//Array
//(
// [post_data] => Array
// (
// [usrname] => myUsername
// [usrpass] => myPassword
// )
//
//)
if (isset($_Post['post_data'])) {
$myPost = $_Post['post_data'];
$usrname = $myPost['usrname'];
$usrpass = $myPost['usrpass'];
$sql = "select count(*) from glusers where EmpName='$usrname' and EmpPass='$usrpass'";
$result = $conn->query($sql);
$num_row = $result->num_rows;
if ($num_row > 0) {
$output = 'Success';
} else {
$output = 'fail';
}
echo json_encode($output);
die();
}

Answer 2

Try This :
in js file :
$(document).on("ready", function(){
// Create an object using an object literal.
var ourObj = {};
// Create a string member called "data" and give it a string.
// Also create an array of simple object literals for our object.
ourObj.data = "Some Data Points";
ourObj.arPoints = [{'x':1, 'y': 2},{'x': 2.3, 'y': 3.3},{'x': -1, 'y': -4}];
var savedata = JSON.stringify(ourObj)
$.ajax({
type:"POST",
url:"Users.php",
data: {"points" : JSON.stringify(ourObj)},
success: function(data) {
// Do something with data that came back.
alert(data);
}
})
});
In PHP File :
if (isset($_POST["points"])) {
$points = json_decode($_POST["points"]);
echo "Data is: " . $points->data . "<br>";
echo "Point 1: " . $points->arPoints[0]->x . ", " . $points->arPoints[0]->y;
}

Answer 3

Try this:
var myobj = '{
usrname:'+$( "#customer option:selected" ).text()+',
usrpass:'+$("#psw").val()+'
}';
or
var myobj = {};
myobj.usrname= $( "#customer option:selected" ).text();
myobj.usrpass= $("#psw").val();

Answer 4

Use Json2 library as follows,
var myobj = {};
myobj["usrname"]= $( "#customer option:selected" ).text();
myobj["usrpass"]= $("#psw").val();
var myjson = JSON2.stringify(myobj);
$.ajax({
method: "POST",
url: "checkpass.php",
data: myjson
})
.done(function( msg ) {
alert( msg );
});

Answer 5

Well actually you php code is invalid because you pass json day not name value pair so you cant get it from $_POST['username']. You need to get the whole post data and decode it like this.
$data = json_decode(file_get_contents('php://input'), true);
Now $data is dictionary array of username and password. Also sanitize your data before passing to query to avoid sql injection.