I am working on a website of a client for which I didn't write the code. I have troubles making files downloadable.
It is about a subdomain where users can download course files.
The website files are contained in the folder "courses" (on the root level).
The file for displaying the downloadable course files is contained in
"courses/displayfiles.php".
The downloadable files are contained in a folder in "courses/downloadfolder". Inside this folder, each user has his own
files folder which as its name has the user id.
displayfiles.php: The following code successfully displays all files that can be downloaded by the logged-in user:
$path = "downloadfolder/" . $_SESSION['userId'] . "/";
$files = array();
$output = #opendir($path) or die("$path could not be found");
while ($file = readdir($output)) {
if (($file != "..") and ($file != ".")) {
array_push($files, $file);
}
}
closedir($output);
sort($files);
foreach ($files as $file) {
echo '<a class="imtext" href="downloadfolder/' . $_SESSION['userId'] . '/' . $file . '/">' . $file . '</a><br/>';
}
So what does not work about this code: When a user clicks on a file, I get a "404 Not Found" message that the file was not found. How can this be?
Why does displaying the files totally works fine, but at the same time I get a 404 error when clicking a file? The files path ($path) must be correct, or not? What further investigations do I need to take in order to solve this problem?
* UPDATE *
I decided to modify the files loop as followed (changing the href):
foreach ($files as $file) {
echo '<a class="imtext" href="http://'.$_SERVER['HTTP_HOST']. '/downloadfolder/' . $_SESSION['courseId'] . '/' . $file . '/">' . $file . '</a><br/>';
}
Still, when I click on a file, I get a 404 Not Found error. How can this be?
You have to look where the webroot of your page is, where the php file generating the list is located and wherer the files are.
Your generated link is relative to the php file generating the link, which might not be corresponding to the URL in the browser. I'd try to make this link relative to the webroot (note the leading slash!)
echo '<a class="imtext" href="/courses/downloadfolder/' . $_SESSION['userId'] . '/' . $file . '/">' . $file . '</a><br/>';
If that guessed solution doesn't work please provide the current URL of the page where this links are generated and one generated link, so we can help you better.
Related
so I come to you with this problem:
GIVENS:
I have Hostgator as the ISP.
I'm using PHP 5.5
The LINUX box is CENTOS
Shared Hosting Environment
I am a professional coder and experienced with LAMP for many years
PROBLEMS:
I'm NOT familiar with Jailed Shell but have an idea
I've tried the script and have been searching for an answer
Still Stuck...
Here's my current code:
function getMyFakeDir($myfile) {
$target = "";
$link = 'content/purchased-items/link';
symlink($target, $link);
echo "READ LINK: ". readlink($link);
return readlink($link);
}
Here's the called to the function:
$linkText = getMyFakeDir('SomePDFThatTheUserCanDownload.pdf');
Then I pass that "$linkText" var to PHPMailer and wala!!! The user clicks to download through the Symlink and I've written a code to make it expire after 24 hours. Yeah, I got that from PHP.net.
So, basically that's my problem....
Here's the error:
Warning: symlink(): Permission denied in /homeSomewhere/someMasterDir/public_html/webServices/somePHPFile.php on line 654
This is link 654 from above:
symlink($target, $link);
Thanks...
Figured it out.... Simple LOGIC!
First I had the PATHS all wrong. Here's the CORRECTED CODE:
//Generate Symbolic Link that blows away a fake directory each time
//A symbolic Link is created to "THIS" file below
$filename = $myfile;
//This is ANY directory on the server...
//A randomly named directory is created here...STEP 1
$downloaddir = "/home/someHostDir/public_html/sldktrulwiu2555ivd0fjvdfgdfgdfgdf/";
//Any directory NOT accessible by a browser - This is one level up
$safedir = "/home/someHostDir/content/purchased-items/";
//This is the equivalent of the $downloaddir and the browser is REDIRECTED here and the download begins
$downloadURL = "http://www.theSomeDomain.com/sldktrulwiu2555ivd0fjvdfgdfgdfgdf/"; //THIS IS THE FAKE DIRECTORY (Which I simply type gobbligook and created that mess above)
$letters = 'abcdefghijklmnopqrstuvwxyz';
srand((double) microtime() * 1000000);
$string = '';
for ($i = 1; $i <= rand(4, 12); $i++) {
$q = rand(1, 24);
$string = $string . $letters[$q];
}
$handle = opendir($downloaddir);
while ($dir = readdir($handle)) {
if (is_dir($downloaddir . $dir)) {
if ($dir != "." && $dir != "..") {
#unlink($downloaddir . $dir . "/" . $filename);
#rmdir($downloaddir . $dir);
}
}
}
closedir($handle);
mkdir($downloaddir . $string, 0777);
symlink($safedir . $filename, $downloaddir . $string . "/" . $filename);
//Header("Location: " . $downloadURL . $string . "/" . $filename);
That just about does it.
The result is a Dynamic directory inside the "/sldktrulwiu2555ivd0fjvdfgdfgdfgdf/" directory like this: "dfsgss/" and a "shortcut" to the REAL LOCATION where the files are. THEN when the file is downloaded, and the page returns to the INDEX.HTML, the code BLOWS OUT the FAKE directory Never more to be seen again. Thus, if the user wants to go back, they get the horrible 404 PAGE error that the file / has been moved or deleted. BUMMER.
That's it folks. Thanks for your assistance, it was you all the helped me release my error. TEAM WORK!
I can't get the picture to display/show when viewing, although the files are already stored in the database (table 'menu') http://i.imgur.com/wo1w90H.png. Also when I upload the images all at once, their file name would change automatically. I don't know how and why this happens. I use array to upload multiple images.
if (isset($_POST["Submit"])) {
--some code here--
if (isset($_POST["id_list"])) {
// if id list available
foreach($_POST["id_list"] AS $id) {
--some code here--
/* Handle file upload */
if ($_FILES['upload']['error'][$id] == 'UPLOAD_ERR_OK') {
$path = "images/newmenu/";
$path_parts = pathinfo($_FILES["upload"]["name"][$id]);
$extension = $path_parts['extension'];
$picture = md5(uniqid()) . "." . $extension;
if (move_uploaded_file($_FILES['upload']['tmp_name'][$id], $path . "/" . $picture)) {
$update = " UPDATE menu
SET MenuPicture='$picture'
WHERE MenuID=$id";
$mysqli->query($update) or die(mysqli_error($mysqli));
}
}
}
}
}
}
Below is the form and yes it does include enctype="multipart/form-data"
<input type="file" multiple name="upload[' . $id . ']" value="' . $record["MenuPicture"] . '">
Filename changes because you are generating it this way
$picture = md5(uniqid()) . "." . $extension;
uniqid() is based on current time and hashing it will cause the filename to change everytime
When I upload the images all at once, their file name would change automatically
It was due to this:
$picture = md5(uniqid()) . "." . $extension;
// And later
move_uploaded_file($_FILES['upload']['tmp_name'][$id], $path . "/" . $picture)
Basically, you are moving your uploaded file to a new filename for your image file, which is generated using uniqid() and hashed with md5(), with the file extension appended at the end.
I can't get the picture to display/show when viewing
How are you trying to display the picture? Is it from web browser, or you go straight to the directory and open from there? What error(s) did you get, if any?
Actually, have you tried to go to the directory and see whether the file is created inside the images/newmenu/ directory?
Also, for the target upload directory, you might want to append it with $_SERVER['DOCUMENT_ROOT'] so that the target directory is not dependent on where your script is located, but it's always based on the root.
By the way, you might know already, but there is an entry in PHP manual page on uploading multiple files
Hi wonder if you can help,
I'm looking to do this in PHP if someone can help me. I have a number of files that look like this:
"2005532-JoePharnel.pdf"
and
"1205121-HarryCollins.pdf"
Basically I want to create a PHP code that when someone ftp uploads those files to the upload folder that it will 1) Create a directory if it doesn't exist using there name 2) Move the files to the correct directory (E.g. JoePharnel to the JoePharnel Directory ignoring the number at the beginning)
I have looked through alot of code and found this code and have adapted it:
<?php
$attachments = array();
preg_match_all('/([^\[]+)\[([^\]]+)\],?/', $attachments, $matches, PREG_SET_ORDER);
foreach ($matches as $file) {
$attachments[$file[1]] = $file[2];
}
foreach ($attachments as $file => $filename) {
$uploaddir = "upload" . $file;
$casenumdir = "upload/JoePharnel" . $CaseNumber;
$newfiledir = "upload/JoePharnel" . $CaseNumber .'/'. $file;
$each_file = $CaseNumber .'/'. $file;
if(is_dir($casenumdir)==false){
mkdir("$casenumdir", 0700); // Create directory if it does not exist
}
if(file_exists($casenumdir.'/'.$file)==false){
chmod ($uploaddir, 0777);
copy($uploaddir,$newfiledir);
}
$allfiles = $CaseNumber .'/'. $file . "[" . $filename . "]" . ",";
$filelistfinished = preg_replace("/,$/", "", $allfiles);
echo $filelistfinished;
// displays multiple file attachments on the page correctly as: casenumber/testfile1.pdf[testfile1.pdf],casenumber/testfile2.pdf[testfile2.pdf],
],
}
?>
Sorry for the lack of code but best i could find.
Any help is much appreciated.
Thanks.
Can I get an eyeball on my symlink?
I'm trying to download a file from one directory, while the file actually exists in another.
I've got the actual file, and the symlink in seperate subdirectories, but both reside in the public html(both are web accessible).
I've verified the file and file location on my (shared Linux) server by going to the file directly.
The link is being created (I've used readlink, is_link, and linkinfo), and I can see it when I FTP in.
I believe I am probably just having a misunderstanding of the directory structure.
I put the file here: ./testdownload/
I put the symlink here: ./testDelivery/
<?php
$fileName = "testfiledownload.zip";//Name of File
$fileRepository = "./testdownload/";//Where the actual file lives
$downloadDirectory = "./testDelivery/";//Where the symlink lives
unlink($downloadDirectory . $fileName); // Deletes any previously exsisting symlink (required)
symlink($fileRepository . $fileName, $downloadDirectory . $fileName);
$checkLink = ($downloadDirectory . $fileName);
if (is_link($checkLink))
{
echo ("<br>Symlink reads: " .readlink($checkLink) . "<br>");
echo ("<br>LinkeInfo reads: " . linkinfo($checkLink));
}
?>
<p><a href="<?php echo ("/testDelivery/" . $fileName); ?>"</a>SymLink</p>
<p><a href="<?php echo ("/testdownload/" . $fileName); ?>"</a>regular link</p>
Everything looks right to me....but the link won't work.
Help?
Ultimately, I will put the source data outside the public area...this is just for testing.
(I'm trying to find a better solution for download than chunking out fread which fails for poor connections. (200-400MB files))
My problem (appears) to be not providing the absolute path for the symlink.
I've added the absolute path below to the same code above, to give a working copy:
<?php
$absolutepath = ( $_SERVER['DOCUMENT_ROOT']);
$fileName = "testfiledownload.zip";//Name of File
$fileRepository = "/testdownload/";//Where the actual file lives
$downloadDirectory = "/testDelivery/";//Where the symlink lives
unlink($absolutepath .$downloadDirectory . $fileName); // Deletes any previously exsisting symlink (required)
symlink($absolutepath . $fileRepository . $fileName, $absolutepath. $downloadDirectory . $fileName);
$checkLink = ($absolutepath . $downloadDirectory . $fileName);
if (is_link($checkLink))
{
echo ("<br>Symlink reads: " .readlink($checkLink) . "<br>");
echo ("<br>LinkeInfo reads: " . linkinfo($checkLink));
}
?>
<p><a href="<?php echo ("/testDelivery/" . $fileName); ?>"</a>SymLink</p>
<p><a href="<?php echo ("/testdownload/" . $fileName); ?>"</a>regular link</p>
This original post, is a duplicate (though I didn't see it until now)
Create a valid symlink for PHP file
(Most of the answers given for that question were wrong however--but the original poster figured it out, and it worked for me too)
Beginner : I cant seem to get my head around the logic of it. Have searched but seems to come up with listing files and folders from an actual directory ie. (opendir).
My problem is :
Im trying to work out (in PHP) how to list files and subfolders from a path stored in a database. (Without any access to the file or dir, so just from the path name)
For example database shows:
main/home/television.jpg
main/home/sofa.jpg
main/home/bedroom/bed.jpg
main/home/bedroom/lamp.jpg
So if i specify main/home - it shows: television.jpg, sofa.jpg and the name of the subfolder : bedroom.
scanFolder('main/home');
function scanFolder($dir) {
foreach (scandir($dir) as $file) {
if (!in_array($file, array('.', '..'))) {
if (is_dir($file)) {
scanFolder($dir . '/' . $file);
}
else {
echo $dir . '/' . $file . "\n";
}
}
}
}
You would probably want to check on each iteration if the filename is a directory or not. If it is, open it up and read its contents and output them. A recursive function would work best in this situation.
http://php.net/manual/en/function.is-dir.php