I am trying to run an query using php into a database, I need to check if the customers address is already exists then do not insert, but if not exists then insert into table, I have based it around the following:
$query = "INSERT INTO address(id,address_type)
SELECT('1111','bill')FROM DUAL
WHERE NOT EXISTS
(SELECT * FROM address
WHERE id='1111' AND address_type='bill')";
$n = mysql_query($query, $connect ) or die(mysql_error());
This allows me to insert just the id but not the address_type.
I will have the same id for both bill & ship addresses making a unique field not possible.
I have about 8 fields to insert, what am I doing wrong?
$query = "INSERT INTO address(id,address_type)
SELECT('1111','bill')FROM DUAL
WHERE NOT EXISTS
(SELECT * FROM address
WHERE id='1111' )";
remove address_type='bill' and check
Related
Im creating a website for booking activities. I have 3 centres. The customer is cant book the same activity twice neither in a different centre. Im using a table in mysql which i store the infos provided by the costumers. Is there any way to filter or to check in my php code if a customer has already booked the same activity more than one time and echo an error msg?
my table(and the info im asking) contains these columns:
ID(Primary)
FirstName
LastName
Email
ContactNumber
ClassName
Week
Intensity
CentreName
$values = $_POST;
foreach ($values as &$value) {
$value = mysql_real_escape_string($value);
}
$sql1="INSERT INTO loan (loan_id)
VALUES ('$values[loan_id]')";
$result = mysql_query($sql1);
if (!$result) {
die('Invalid query: ' . mysql_error());
}
When you create the table add the unique attribute to the fields you want to prevent, something like this
CREATE TABLE Persons
(
P_Id INT NOT NULL AUTO_INCREMENT,
LastName VARCHAR(255) NOT NULL,
FirstName VARCHAR(255),
Address VARCHAR(255),
City VARCHAR(255),
UNIQUE (P_Id)
)
If you already have created the table just edit it like this
ALTER TABLE Persons
ADD UNIQUE (P_Id)
Hope this helps you; If you do not have a unique id i believe this will suit you best on what you need; Note that this is not the full code; You need to add some to other information to fit in your question;
// Checks if the value already exist on the database
$query = SELECT EXISTS(SELECT column_name FROM table_name WHERE
condition LIMIT 1)
// If condition is not met it will proceed with save
if (mysql_num_rows(!$query) > 0) {
echo "Activity Booked";
} else { // If condition is met it will echo an error message
echo "Unable to booked activity"; }
You need to create a unique (composite) index on the column(s) that you wish to be unique. You can disregard your PK when making your unique index. In your case your sql would look something like:
Alter table yourtablename
add unique index idx_unq(`LastName`, `FirstName`, `Email`, `ContactNumber` `ClassName`, `Week`, `Intensity`, `CentreName`);
Then do an INSERT IGNORE INTO instead of an INSERT INTO.
This post may also help you.
"INSERT INTO .. ON DUPLICATE KEY UPDATE" Only inserts new entries rather than replace?
In order to see if record already exist in table you must first "test" to see if that exact record exist in your table. This is to be done before the 'Insert IGNORE Into' in your logic. Using the variables your code would look something like this:
$testcount = "Select count(`LastName`, `FirstName`, `Email`, `ContactNumber` `ClassName`, `Week`, `Intensity`, `CentreName`)
from yourtablename
where
(LastName = '$LastName' AND FirstName= '$FirstName' AND Email= '$EMAIL' AND ContactNumber= '$ContactNumber' AND ClassName= '$ClassName' AND Week= '$Week' Intensity = '$Intensity' AND CentreName = '$CentreName' )";
This query will give you back (assuming there are no duplicates already in the table) a 0 or a 1 and store it in your $testcount variable. This can then be used to either determine based on the value to insert the record into the table or print a message to end user informing them that it already exist.
I am not sure how you want to structure the php code but the psuedocode would look something like:
If $testcount = 1 then do your insert.
else if $testcount = 0 then echo your message.
I have a database of Users and another table for Teachers. Teachers have all the properties as a user but also an e-mail address. When inserting into the DB how can I insert the info, ensuring that the ID is the same for both?
the ID currently is on automatic incrament.
this is what I have at the moment:
$sqlQuery="INSERT INTO user(firstName,lastName,DOB,title,password,classRoomID)
VALUES('$myFirstName','$myLastName','$myDOB','$myTitle','$newPassword','$myClassRoom')";
$result=mysql_query($sqlQuery);
$sqlQuery = "INSERT INTO teacher(email) VALUES ('$myEmail')";
$result=mysql_query($sqlQuery);
thank you!
use MYSQL function LAST_INSERT_ID()
OR php mysql http://ro1.php.net/manual/en/function.mysql-insert-id.php
why to use separate table for teachers. instead, you can have email field with in user table and additional field with flag (T ( for teacher) and U (for user). Default can be a U. This have following Pros.
Will Not increase table size as email would be varchar
Remove extra overhead of maintaining two tables.
Same Id can be used
If you want to have that as separate table then answer you selected is good one but make sure last insert id is called in same connection call.
After the first insert, fetch the last inserted id:
$last_id = mysqli_insert_id(); // or mysql_insert_id() if you're using old code
Or you could expand your second query and use mysql's integrated LAST_INSERT_ID() function:
$sqlQuery = "INSERT INTO teacher(id, email) VALUES ((SELECT LAST_INSERT_ID()), '$myEmail')";
Try this:
$sqlQuery="INSERT INTO user(firstName,lastName,DOB,title,password,classRoomID)
VALUES('$myFirstName','$myLastName','$myDOB','$myTitle','$newPassword','$myClassRoom')";
$result=mysql_query($sqlQuery);
$id = mysql_insert_id();
$sqlQuery = "INSERT INTO teacher(id, email) VALUES (' $id ','$myEmail')";
$result=mysql_query($sqlQuery);
Insert data into two tables & using the same ID
First method
$sqlQuery1 = "INSERT INTO user(firstName,lastName,DOB,title,password,classRoomID) VALUES('$myFirstName','$myLastName','$myDOB','$myTitle','$newPassword','$myClassRoom')";
$result1 = mysqli_query($conn, $sqlQuery1);
$lastID = mysqli_insert_id($conn);
$sqlQuery2 = "INSERT INTO teacher(email, lastID) VALUES ('$myEmail', 'lastID')";
$result2 = mysqli_query($conn, $sqlQuery2);
If the first method not work then this is the second method for you
$sqlQuery1 = "INSERT INTO user(firstName,lastName,DOB,title,password,classRoomID) VALUES('$myFirstName','$myLastName','$myDOB','$myTitle','$newPassword','$myClassRoom')";
$result1 = mysqli_query($sqlQuery1);
$sqlQuery2 = "INSERT INTO teacher(email) VALUES ('$myEmail')";
$result2 = mysqli_query($sqlQuery2);
You can set the Foreign Key in your database table (phpMyAdmin/ MySQL Workbench) to let the Foreign Key follow the Primary Key (ID). Then the data after insert will auto-follow the Primary Key ID.
Example here,
Teachers table set ID - Primary Key
Users table set UserID - Foreign Key (will follow the Teachers table ID)
if you're using MySQL WorkBench, you can refer to this link to set a foreign key.
https://dev.mysql.com/doc/workbench/en/wb-table-editor-foreign-keys-tab.html
Hope I can help any of you.
Though you can use the LAST_INSERT_ID() function in order to get the last insert id, the best approach in this case is to create a column reference to user id table.
teacher
id | user_id | email
So the teacher.id could be anyting, but the user_id column is the real reference to user table.
If you use InnoDB table, you can make the database consistent using Foreign keys
You Should Use A Transaction In MySQL. First insert In One Table And GET LAST_INSERT_ID().
Insert LAST_INSERT_ID() In Second Table.
$sqlQuery="INSERT INTO user(firstName,lastName,DOB,title,password,classRoomID)
VALUES('$myFirstName','$myLastName','$myDOB','$myTitle','$newPassword','$myClassRoom')";
$sqlQuery = "INSERT INTO teacher(LAST_INSERT_ID(), email) VALUES (' $id ','$myEmail')";
$result=mysql_query($sqlQuery);
i had following table and columns
Table Name = users
column = user_id, name, email, password, status, identity
i'm using following query for insert data to table users
$name = mysql_real_escape_string($_POST['name']);
$email = mysql_real_escape_string($_POST['name']);
$password = mysql_real_escape_string($_POST['txtPassword']);
$password = md5($password); //===Encrypt Password
if(isset($_POST['btnRegister'])) //===When I will Set the Button to 1 or Press Button to register
{
$query = "insert into users(name,email,pasword,status,identity)values('$name','$email','$password','1','0')";
$res = mysql_query($query);
header('location:success_register.php');//Redirect To Success Page
}
what i am asking is, i want store last id to column identity also
for example: if last user_id= 10, identity also will be = 10. i mean get last id then store that id to identity column
Result will be look like this
user_id name email password status identity
5 aa aaa#ab.com **** 1 5
6 bbb bbb#ac.com **** 1 6
how to do it,?
In MYSQL, you have alternative possibility to find it, when you think last_insert_id() is not working. You may require to have SELECT privilege on INFORMATION_SCHEMA and its tables.
If you have that privileges, try the following query.
$query = "insert into users( name, email, pasword, status, identity )"
. " values( '$name', '$email', '$password', '1',"
. " ( SELECT AUTO_INCREMENT FROM INFORMATION_SCHEMA.TABLES"
. " WHERE TABLE_NAME='users' and TABLE_SCHEMA=DATABASE() )"
. " )";
And, lastly, suggesting to stop using deprecated API.
Save last insert id like this:
$id = mysql_insert_id();
and use it in next insert
You are looking for:
mysql_insert_id()
mysqli_insert_id(mysqli $link)//for mysqli
PDO::lastInsertId()//for PDO
Other Approach:
if your id column is auto increment and not random then you can select the max id(everytime just after your insert query) from the users table and insert it into whatever column you want.
$id=mysql_result(mysql_query(select max(user_id)
from users),0);
Dont use mysql_ as they are depracated.*
here is what you are looking for. Select max(user_id)+1 and store it in a variable.
Now you need to pass this variable in user_id and identity parameter.
Note that even though user_id is auto increment, it will allow you to insert the new row with specified user_id
i think you can also put it like this
$lastID = MySQLI_insert_id($DBcon); //where Dbcon is your connection to your database
and then
$query = "insert into users(name,email,pasword,status,identity)values('$name','$email','$password','1','$lastID')";
$res = mysql_query($query);
I think you need to insert number of rows in the table after the insert:
It may useful to you
$query = "insert into users(name,email,pasword,status,identity)values('$name','$email','$password','1','0',(select COUNT(*)+1 FROM users))";
I have this script add new users to MySql andnow I have created secondary Mysql table for black-list name. so I want MySql check the black-list name before allow insert the data.
$all = implode(",",$_POST);
$all = explode(",",$all);
$insert = "INSERT INTO name VALUES (";
for ($x=0;$x<5;$x++)
{
$all[$x] = clean($all[$x]);
if ($all[$x] == "" || strlen($all[$x]) > 300)
die("<p>Please fill in the whole form." . $x);
$insert .= "'" . $all[$x] . "',";
}
$insert .= "'')";
$res = #mysql_query($insert) ;
I have change to
$insert = "INSERT INTO name VALUES (";
for ($x=0;$x<5;$x++) NOT IN (SELECT `blacklist` FROM `exclude`)
but didn't get what I am looking for. how I can fix that?
AS far as I am aware you are going to have to do a seperate select on your exclude table using whatever is the key to that table that is shared with the name table to check this user is not in the exclude list.
There is no INSERT syntax to allow a concept like INSERT unless something exists within another table.
As a matter of fact, you could (ab)use INSERT ... SELECT to do what you want:
-- insert one name:
INSERT INTO user SELECT "john" FROM DUAL
WHERE "john" NOT IN (SELECT name FROM blacklist);
INSERT INTO user SELECT "ringo" FROM DUAL
WHERE "ringo" NOT IN (SELECT name FROM blacklist);
-- insert several names
CREATE TEMPORARY TABLE candidate(name char(40));
INSERT INTO candidate VALUES
("paul"), ("ringo"), ("georges");
INSERT INTO user SELECT name FROM candidate
WHERE name NOT IN (SELECT name FROM blacklist);
See http://sqlfiddle.com/#!2/7ea68/1 for an example.
I have a php script that uploads csv files into a mysql database.
The database has several columns. Among these columns is an 'email' field. I wrote some mysql that would remove rows that contained duplicate values in the email column. Below is the mysql:
$sql = "CREATE TABLE new_table as SELECT * FROM auto WHERE 1 GROUP BY email";
mysql_query($sql, $conn);
$query = mysql_query("SELECT COUNT(*) FROM new_table");
list($number) = mysql_fetch_row($query);
$query = mysql_query("SELECT COUNT(*) FROM auto");
list($number2) = mysql_fetch_row($query);
$result = $number2 - $number;
mysql_query("DROP TABLE auto");
mysql_query("RENAME TABLE new_table TO auto");
The code works, it removes duplicate values.
Problem:
It removes rows that contain no values. So it assumes that two or more emails values that are empty are duplicates and removes they're rows.
Question:
How do I tell mysql to ignore empty values.
Thanks for the help.
Edit
The where is my database table. One table.
The when is when I execute the code. I plan on putting in a php file to be executed on demand.
The result I expect is a mysql table without duplicate emails.
Something like this would work for a one-time alteration, by allowing NULL in email, and adding a UNIQUE constraint:
-- set empties to NULL
UPDATE tablename SET email = NULL WHERE LENGTH(email)=0;
-- drop all rows violating the UNIQUE constraint on email:
ALTER IGNORE TABLE tablename ADD UNIQUE (email);