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I am trying to get this to update a record and was wondering why I cant get this to work?
I can write a new record no problem but the update doesn't work; is it something simply I am missing?
else {
echo "ID NOT EMPTY-";
//---inside else statement shows this echo and the $id number printed on screen WHERE should have varible $ID but I changed it to debug
echo "$id";
$SQLstring3 = "UPDATE $Tablename SET(blank='1') WHERE(id='5')";
$QueryResult = #mysql_query($SQLstring3, $DBConnect);
}
I think the problem might be the way you are using SET and WHERE. Putting them the parentheses () immediately following them might make them seem like a MYSQL function, which it tries to execute. What you have is this:
"UPDATE $Tablename SET(blank='1') WHERE(id='5')";
Try removing the parentheses:
"UPDATE $Tablename SET blank='1' WHERE id='5'";
Related
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SO, I want to create a pretty big mysql table that should save all of the squares of a chess board and their value, I'm using a PHP for() since it has 64 squares.
This always gives me 'not working'
<?php
mysql_connect('localhost','pierostesting','');
mysql_select_db('my_pierostesting');
$query="CREATE TABLE board (";
for($i=0;$i<63;$i++){
$query .= "i".$i." INT(1) NOT NULL,";
}
$query .="turno BOOL";
if (mysql_query($query)){
echo 'working';
}else echo 'not working'; ?>
I'm an idiot, didn't close the bracket.
try echoing out your complete SQL string, then use phpMyAdmin and see if the sql string actually works, or if it throws errors. You may have a sql syntax error.
If it does work, make sure your connection variables are correct (host, db name, username, password)
that should get you close to the answer.
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Closed 8 years ago.
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foreach($db->fetch_array("SELECT id_categories FROM csn_categories_join_kartes where id_kartes===".$card['id']."") as $kat){
echo (kat['id_categories']);
}
table cols and values are all matched, something is wrong in this part of code
I tried adding $ before kat and using only one "=", sill doesnt work
NEW LINK
http://pastebin.com/RPK7vEaJ
this
where id_kartes===".$card['id']."
would be
where id_kartes=".$card['id']."
and missing $
echo $kat['id_categories'];
so full code :-
foreach($db->fetch_array("SELECT id_categories FROM csn_categories_join_kartes where id_kartes='".$card['id']."'") as $kat){
echo $kat['id_categories'];
}
best practice if you store your query result in a variable and loop over this variable.
foreach($db->fetch_array("SELECT id_categories FROM csn_categories_join_kartes where id_kartes=".$card['id']."") as $kat)
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$cid = $_GET['cid'];
$aid = $_GET['aid'];
echo 'test';
echo $aid;
echo $cid;
http://whatever.com/script.php?cid=40?aid=20
$cid and $aid do not echo values. Echoing is not my intended usage, I'm trying to compare $aid to a value I get from the database using $cid.
When I noticed my comparison statement validating true when it was definitely supposed to be false, I echoed out the vars and realized the statement is returning true because they are both null.
I'm completely stumped.
Your test URL should not have two question marks. Use ampersands for additional parameters after the first.
http://whatever.com/script.php?cid=40&aid=20
^
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I'm wondering why the first delete query won't work, when the second does?
if(isset($_POST['accept request' . $user_from])) {
$delete_request = mysql_query("DELETE FROM friend_requests WHERE user_from='$user_from' AND user_to='user_to'");
header("location: friend_requests.php");
echo "<br /><br />You are now friends with " . $user_to;
}
if(isset($_POST['ignorerequest' . $user_from])) {
$delete_request = mysql_query("DELETE FROM friend_requests WHERE user_from='$user_from' AND user_to='$user_to'");
header("location: friend_requests.php");
echo "Friend Request Declined";
}
Please ignore the fact that they're not prepared, and that it's a security issue. I purely want to know why the first delete request doesn't work (yes, the if gets triggered properly)
your missing the dollar sign on your user_to variable
"DELETE FROM friend_requests WHERE user_from='$user_from' AND user_to='$user_to'"
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Closed 9 years ago.
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I am running the below code and know that this is the suspect peice as I have placed an echo above and below it. The first runs fine but the second does not.
If I change the query to something like "show tables" it will run but I cannot see what if anything is wrong with this. I have checked reserved words and syntax. Am I missing something obvious!
try
{
$sth = $dbh->prepare('SELECT COUNT(*) AS val FROM users WHERE username=:user');
$sth->binvalue('user',$_POST['user']);
$sth->execute();
}
catch(PDOException $e)
{
echo $e->getMessage();
}
There is a type error:
instead of
$sth->binvalue('user',$_POST['user']);
Try
$sth->bindvalue('user',$_POST['user']);
^
$sth->binvalue('user',$_POST['user']);
should be
$sth->bindValue(':user',$_POST['user']);
Notice both the bindValue and the :user