Php for loops explaination [closed] - php

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I know that to show dates between two dates in Php we can use this code
$tsDateFrom = date('2015-05-01');
$tsDateTo = date('2015-05-07');
for($i=$tsDateFrom;$i<=$tsDateTo;$i++) {
echo $thisDate = $i."<br>" ;
}
displays
2015-05-01
2015-05-02
2015-05-03
2015-05-04
2015-05-05
2015-05-06
2015-05-07
but how about this?
$tsDateFrom1 = date('2015-05-01');
$tsDateTo1 = date('2015-05-07');
for($i=$tsDateFrom1;$i<=$tsDateTo1;$i = strtotime('+1 day', $i)) {
echo $thisDate = $i."<br>";
}
displays
2015-05-01
I need explanation since I'm only new to php and I want to learn how loops works.And why the second loop return just the first date?

Answer 1

First, you're not using date() properly:
$d = date('2015-05-01');
That will format the current date/time according to your pattern, e.g. "Y-m-d", but because those format specifiers are missing it will just return what you have passed it, i.e. a string.
Second, strtotime() expects the second argument to be a timestamp, not a string; when a non-numeric string is supplied, it will complain and return something you probably didn't expect:
$ var_dump(strtotime('+1 day', '2015-05-07'));
PHP Notice: A non well formed numeric value encountered in php shell code on line 1
int(88415)
As you can see, it doesn't return a string either, but an integer value that represents a timestamp.
You could write it like so:
$d = date('Y-m-d', strtotime("$d +1 day"));
But, in this case it would be a better idea to use DatePeriod instead:
$tsDateFrom = new DateTime('2015-05-01 00:00:00');
$tsDateTo = new DateTime('2015-05-07 23:59:59');
foreach (new DatePeriod($tsDateFrom, new DateInterval('P1D'), $tsDateTo) as $date) {
echo $date->format('Y-m-d'), '<br>';
}

Answer 2

$i = strtotime('+1 day', $i) returns an integer and it is not comparable in $i<=$tsDateTo1.
Maybe $i=date('m-d-Y',strtotime($i. "+1 days")); would work.
You can take a look at PHP - add 1 day to date format mm-dd-yyyy.... it might be useful

Answer 3

From the PHP doc:
int strtotime ( string $time [, int $now = time() ] )
The function expects to be given a string containing an English date
format and will try to parse that format into a Unix timestamp (the
number of seconds since January 1 1970 00:00:00 UTC), relative to the
timestamp given in now, or the current time if now is not supplied.
So, for example:
echo(strtotime("+1 day"));
Output:
1432868203
Then, as you see strtotime() doesnt returns something in the format you are expecting, since you are working with yy-mm-dd.
In fact, strtotime('+1 day', $i) is throwing an error in your code, and because that your loop fails.
Two advices:
Read the doc
Turn on PHP error reporting, this will give you some indication of where your errors are.