I would like to obtain on my localhost (somehow dynamically) the following URLs:
localhost/demo1/
localhost/demo2/
localhost/demo3/
...
and so on (more than 30).
I have an index.php file which I would like to use as a template for each of the above paths.
When I access localhost/demoX/ I would like to load the index.php template only with some few changes inside, based on the demoX name.
Can you tell me how to obtain this structure?
Thanks
Use PHP
1) Parse site URL (hint for url "http://" . $_SERVER['SERVER_NAME'] . $_SERVER['REQUEST_URI']) to get variable you need (I think you will use RegEx for that)
2) $template = require_once('index.php');
3) Process all variables used in index.php
4) echo $template; exit();
NOT TESTED PSEUDO CODE
$url = $_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'];
$part = preg_match("/demo(\d+)/", $url)[0];
$partName = "File name is demo-{$part}";
$template = require_once('index.php');
echo $template;
exit();
[index.php]
<?php
echo $partName;
Related
The title says it all: I want the page to determine the title, but the title is being set before the page is being read (I think). Is there a way to accomplish this, or am I doomed to include the header on each individual page?
Here's what I have:
php.ini:
auto_prepend_file = "header.php"
header.php:
<?php
if (isset($title) == false) {
$title = "foobar";
}
$title = "My Site : " . $title;
?>
<title><?php echo($title) ?></title>
index.php
<?php
$title = "Home"; // ideally this would make the title "My Site : Home"
?>
Instead of using auto_prepend_file, I would just use:
include 'header.php';
An important reason why I wouldn't use auto_prepend_file is, if you move to another server, you'll have to remember to edit the php.ini. If you just include the file, you can move your code to any server.
Also, just like Fred-ii- said, I wouldn't use parenthesis. Also, you are missing a semi-colon after the echo.
To take that a step further, I would create a file called something like $config.php or $vars.php. Include that before everything and have it define all your global variables and constants.
I would check this out: http://php.about.com/od/tutorials/ht/template_site.htm
This is not an ideal answer, but I could use CGI variables to get the name of the page, then turn that into a title.
function get_title($page){
$title = str_replace("/", "", $page);
$title = str_replace("_", " ", $title);
$title = str_replace(".php", "", $title);
$title = ucfirst($title);
if($title = "Index"){
$title = "Home";
} elseif ($title == "") {
$title = 'Foobar';
}
return $title;
}
$title = get_title($_SERVER["PHP_SELF"]);
$title = 'My Site: ' . $title;
As a follow-up to my original comment, I'm posting this as an answer because while it doesn't specifically solve the problem, it addresses the underlying cause.
Disclaimer: The code below has many problems, especially security, it's not meant to be copied directly but only explains the concept.
What you need to do is have a container file that includes your headers and whatever else, and each PHP file is included from there. For example, name your container index.php, and have the following in it:
<?php
include 'header.php';
if ($_GET['page'])
include $_GET['page'].'.php';
include 'footer.php';
?>
Then each PHP page you have will be wrapped in the index.php file, and you can add whatever you want in the header file which will be included in all of your files. That way you don't have to include anything in the individual page files.
The client will access your pages with a query string, such as: index.php?page=test
Again, for security reasons you will still want to include basic checks in each individual file, but technically this can be avoided in you plan for this. You definitely won't need to include huge headers in each file, like MySQL connections etc. Also for security you should have stringent checks on your $_GET variables to make sure that only the pages you want can be included.
I'd define a writeTitle (or similar) function in the header.php file which you're auto_prepending:
header.php
<?php
function writeTitle($title = 'foobar') {
$title = "My Site : " . $title;
return '<title>' . $title . </title>';
}
And then you can just call the function from your page scripts instead of setting a variable:
index.php
<?php
echo writeTitle('Home');
Still learning php as I go so this might just be something I haven't gotten to yet but it's the next roadblock in building my personal site. I have a basic understanding of includes such as linking:
<a href="art.php?id=image id&name=This is my title&menu=side-menu-portfolio">
to pull my includes but I've come to a small problem in that my generic art-gallery page needs to switch between a 'portfolio' header and an 'artwork' header. So I figured I could either build "art-gallery.php" AND "port-gallery.php" and go back and relink everything or just make it so that when you call the link like the above code I just specify which header goes with it. Unfortunately this would also require going back and changing every link. But I noticed that I did state:
...&menu=side-menu-portfolio...
and the pages are already calling side-menu-artwork or side-menu-portfolio so if I could just call in menu and cast aside the 'side-menu-" portion then it would just use artwork or portfolio and call the right header. Unfortunately this is where my limited knowledge of php and syntax come in. I have tried to produce the following code based on my php and js understanding:
<?php include("headlines/headline-" . $_GET[menu - "side-menu-" ] . ".php"); ?>
but I don't know if my syntax is just wrong or if what I'm trying to do is impossible to begin with. Note that when I try this I get
Function Include error of "Warning: include(headlines/headline-.php)"
so it looks like everything else is reading correctly, I just don't know if or how I can extract the word I want from the rest of the menu name.
Should be, Assumed your included file name is headline-side-menu-portfolio.php
<?php
$filename = str_replace("side-menu-", "", $_GET['menu']); // headline-portfolio
include("headlines/headline-" . $filename . ".php"); // headline-portfolio.php
?>
Something like this :
<?php include("headlines/headline-" . $_GET["menu"].".php"); ?>
<!--gives include("headlines/headline-side-menu-portfolio.php")-->
where
$_GET["menu"] = 'side-menu-portfolio'
Try this:
<?php include("headlines/headline-" . $_GET['menu'] . ".php"); ?>
Your code is wrong.
Instead of
<?php include("headlines/headline-" . $_GET[menu - "side-menu-" ] . ".php"); ?>
try
<?php include("headlines/headline-" . $_GET['menu'] . ".php"); ?>
You should check if the file exists before you try including it.
if (file_exists($filesrc)) { ... }
Better yet don't let the user change the menu through a $_GET variable. Instead link to a specific page or pass a variable then decide what menu to get. Like
switch ($_GET['menu']) {
case 'side-menu':
include("headlines/headline-side-menu.php");
break;
}
Just use
$_GET['menu']
, the "side-menu-" part is already in the content of your variable passed as param.
You propably want to do an if .... else so to include one header or another based on the $_GET variable menu.
So something like this will do this:
if($_GET['menu'] == 'side-menu-portfolio') {
include 'headliens/side-menu-portfolio.php';
} elseif($_GET['menu'] == 'side-menu-other') {
include 'headliens/side-menu-other.php';
}
okay....your are almost there....just quotes missing from include syntax...it should be
include("headlines/headline-.php"); /* notice the quotes*/
so it should be
<?php include("headlines/headline-" .$_GET['menu'].".php"); ?>
where $_GET['menu'] should be in the url, like:
art.php?id=image id&name=This-is-my-title&menu=side-menu-portfolio
so what's happening her ??
Upon execution of the line :
<?php include("headlines/headline-" .$_GET['menu'].".php"); ?>
$_GET is fetched from the url and replaced in the header tag, so now the header tag becomes :
<?php include("headlines/headline-"."side-menu-portfolio".".php"); ?> => <?php include("headlines/headline-side-menu-portfolio.php"); ?>
Also. may i suggest that for :
<a href="art.php?id=image id&name=This is my title&menu=side-menu-portfolio">
don't use space in the url, either replace it by - or _
For example I have a website that points to a page like this:
http://www.mysite.com/folder/file
How can I get determine /folder so that I can go further an quote an if statement like
if /folder then echo something
Why do I need this?
I am trying to tell facebook which image to pick from a page. Actually I have a pretty simple page structure and the image that facebook should take is always at first but somehow it does choose another one from time to time. I guess because the other images are loaded faster. And the old way to rel="img_src" doesn't seem to work anymore as that I could just add it to the wanted image.
So well of course I use the open graph protocol to tell facebook which Image it should use.
I am working with a cms were I can output the path of the image depending on the id the image has. I have two different id's for the different kind of pages living in two different folders.
This leads to:
if index --> echo meta og for index img
else if /folderone (with id1) --> echo meta og for id1
else if /foldertwo (with id2) --> echo meta og for id2
This is why I need to know the foldername.
Now with the answer I have following setup, just that you know:
<?php $folder = dirname($_SERVER['SCRIPT_NAME']); ?>
<?php if (dirname($_SERVER['SCRIPT_NAME']) == "/") echo "<meta property='og:image' content='http://www.mysite.com/img/img.jpg'/>" ;?>
<?php if (dirname($_SERVER['SCRIPT_NAME']) == "/folderOne") echo "<meta property='og:image' content='http://www.mysite.com/img/{$img_id1}'/> " ;?>
<?php if (dirname($_SERVER['SCRIPT_NAME']) == "/folderTwo") echo "<meta property='og:image' content='http://www.mysite.com/img/{$img_id2}'/> " ;?>
parse_url &
explode
$path = parse_url($url, PHP_URL_PATH);
gives you
/folder/file
then you can explode() to separate the path values and check the first one to see if it is 'folder'
Example here: http://tehplayground.com/#7TIKAwp6J
Example code:
$url = "http://www.mysite.com/folder/file";
$path = parse_url($url, PHP_URL_PATH);
$arr = explode("/",$path);
echo $arr[1]; // leading slash makes [0] ""
outputs
folder
$script = $_SERVER['SCRIPT_NAME'];
echo dirname($script);
Possibly use "get current working directory" function getcwd()?
Explode it by directory separator.
Then grab the last element like this:
$var = getcwd();
$var = explode('\\', $var); // your OS might use '/' instead
$var = end($var);
I suppose this assumes you're not using some kind of MVC framework that uses routing.
I hope that helps!
I think this is nicer than exploding the string:
function getCurrentDirectory(){
$curDirPath = getcwd();
return substr($curDirPath, strrpos($curDirPath, '/') + 1);
}
getcwd() gives you the current directory's path, and then you can truncate it starting right after the last occurrence of the / in its file path.
$dir_list = explode('/', dirname($_SERVER['SCRIPT_FILENAME']));
$this_folder = $dir_list[count($dir_list)-1];
...
if ($this_folder) == "folderOne") echo "...."
...
if(dirname('yoursite/folder')){
I need "calculate" an URL and redirect to it. I have the following code:
<?php
//Basic HTML parsing with PHP
include("simple_html_dom.php");
$htmlCode = file_get_html('http://example.net/example.html');
foreach($htmlCode->find('div[class=frontPageImage]') as $element) {
foreach($element->find('img') as $imagee)
$imgurl = $imagee->src;
}
header("'Location:".$imgurl."'");
?>
First in $imgurl get the url and later redirect to that url... but it doesn't work..
any idea or suggestion? thanks
header("'Location:".$imgurl."'");
Should probably be:
header("Location: " . $imgurl);
I removed the single quote ' because your HTTP header would look like:
'Location: http://site.com/image.jpg'
which is invalid because of the single quotes.
You are also looping and finding many image URL's but only redirecting to the last one.
Is it possible to save the current page in a variable (not the full url) using php
So if my page is www.mywebsite.com/news/bob
I am looking to get /bob in a variable.
<?PHP $file_name = $_SERVER['PHP_SELF']; ?>
see this variable
$_SERVER['PATH_INFO']
maybe you need
basename($_SERVER['PATH_INFO']);
$_SERVER['PATH_INFO'] doesn't seem to exist on my install. Not sure what the story is there, but if it's not on mine, it may not be on yours so here's some alternatives.
$current_page = '/' . basename($_SERVER['PHP_SELF']);
$current_page = '/' . basename($_SERVER['REQUEST_URI']);
$current_page = '/' . basename($_SERVER['SCRIPT_NAME']);
I find $_SERVER['PHP_SELF'] to be quite dependable.
If you're fond of regular expressions you could try
$current_page = preg_replace('/(.*?\/)+(.*)$/', '/$2', $_SERVER['PHP_SELF']);
If you are using $_SERVER['PHP_SELF'] on included or required files, then it will return the current file, not the URL of the current page. On Windows machines, the only reliable options are $_SERVER['REQUEST_URI'] or $_SERVER['HTTP_X_ORIGINAL_URL'] however, these will include any querystring as well.
You would need to strip the query string off the end of the URL to get the part you want.
$current_page = $_SERVER['REQUEST_URI'];
$current_page = substr($current_page, 0, strpos($current_page, "?")); //removes query string
$current_page = = '/' . array_pop(array_filter(explode("/", $current_page)));