$_FILES returning nothing - php

Question

So, I recently looked up how to upload files onto a database using Blob. This is the tutorial I found http://www.php-mysql-tutorial.com/wikis/mysql-tutorials/uploading-files-to-mysql-database.aspx
I followed this tutorial and came up with this code -
HTML FORM -
<form action='memberPage.php' method='post' enctype='multipart/form-data'>
<input type='text' name='programName' placeholder='Program Name'></input>
<input type='text' name='programPrice' placeholder='Price'></input>
<div id='uploadFiles'>
<input name='userfile1' type='file' onchange='addAnother()'>
</div>
<input type='submit' value='Create program' style='cursor:pointer;'></input>
</form>
PHP UPLOAD ($programName is specified outside code it looks something like $programName=$_POST["programName"];)
for($i = 1; $i < 999;$i++){
if(isset($_POST["userfile" . $i]) && $_FILES["userfile" . $i]['size'] > 0){
$Filename = $_FILES["userfile" . $i]['name'];
$finfo = new finfo();
$Filetype = $finfo->file($_FILES["userfile" . $i]['tmp_name'], FILEINFO_MIME);
$Filesize = $_FILES["userfile" . $i]['size'];
$Filetmpname = $_FILES["userfile" . $i]['tmp_name'];
$Fileerror = $_FILES["userfile" . $i]['error'];
$fp = fopen($Filetmpname, 'r');
$content = fread($fp, filesize($Filetmpname));
$content = addslashes($content);
fclose($fp);
if(!get_magic_quotes_gpc())
{
$Filename = addslashes($Filename);
}
mysqli_query($conn, "INSERT INTO upload(name,type,size,content,program) VALUES('
'" . $Filename. "','" . $Filetype. "','" . $Filesize . "','" . $content . "','" . $programName . "')");
}else{
$i=999;
header("location:memberPage.php");
}
}
But when I submit the forum, the files return with nothing in them, no name, and the size is zero.
I have also checked out the other question things on here and did not find the answer, so my guess is that it is in my code.
Let me also specify that the onchange='addAnother()' adds another input, but has the next end number on it (Example - userfile1, it would then add userfile2)

Answer 1

you are using input name "programName" and try to get "Programname" the same with $_POST.
PHP is case sensitive you should use same case in PHP "$_POST['programName']"

Answer 2

We need to check file element istead of post element.
Try changing this
if(isset($_POST["userfile" . $i]) && $_FILES["userfile" . $i]['size'] > 0){
to this
if(isset($_FILES["userfile" . $i]) && $_FILES["userfile" . $i]['size'] > 0){

Answer 3

It would be better to create the input names as arrays.
<input name='userfile[]' type='file' onchange='addAnother()'>
and iterate through it in php like:
if (isset($_FILES["userfile"]) && is_array($_FILES["userfile"])) {
for ($i=0;$i<count($_FILES["userfile"]);$i++) {
echo $_FILES["userfile"]["name"][$i];
}
}