I have a header.php file containing my DOCTYPE and all my links/scripts.
I use
<?php
// HTML DOCTYPE insert
include 'header.php';
?>
at top of all my pages to have only one header for everyone, and it works fine.
Now, I have another page that get from a database a summary of my products information. When someone click on the "read more" link:
<p>
read more...
</p>
another page opens with the full information displayed...
Actually that works...
BUT on my new page (display_product.php/id=[anynumber]) my included file doesn't work. So I have no nav bar, no scripts, no stylesheet. Only the text from my database.
AND the weird thing is that when I copy/paste the HTML of my generated display_product page and launch it on my browser, it works... O-o
So the generated code is good.
AND the second weird thing is that when I get rid of the /?id... my layout works fine (but I have no text anymore, of course)
Does one of you have an idea why this crazy things happens?
"Hi guys, Thanks very much Fred -ii this was it. it works perfectly. Thanks sergiodebcn for your concerne."
Since other answers were given and did not solve the actual problem, am posting my comment to an answer, in order to close the question.
Remove the slash from /?id
The slash is trying to instruct the server to probably find a folder after a filename, which technically looks like is what's happening here.
The ultimate solution for include and require functions with path issues, is to use the absolute filesystem path to the file that you want to include or require.
i.e you may say:
include("C:\\www\\app\\incs\\header.php");
Hint
To learn how to set the absolute path for include dynamically for your project, check the source code of two files of cakephp framework:
index.php
webroot/index.php
Related
The question has been asked before but none of the previous answers that I have found solves my problem.
This is the structure for my web page.
index.php calls the loader.
loader.tpl generates <head>, generates <body> by include header.tpl, include $body and include footer.
A separate php page holds the functions and a new page is generated by calling a function that sets $page to a new value matching a .tpl file.
I've created the analyticstracking.php file and placed it in a folder.
I've tried placing<?php include_once("foldername/analyticstracking.php") ?> pretty much in every place I can think of. Either it doesn't do anything at all or it causes an error.
No error code is given, it only returns a blank grey page.
I tried copying the script code straight into the body of the $page template and it only generated an error.
I'm out of ideas.
Where should I place
Since I've tried any number of different locations, it would be great if you could give an answer so foolproof that it can't be miss interpreted.
Thanks
I absolutely don't post a question here in SO unless I really can't find a way to solve my problem myself. I did a lot of googling and was not able to find a solution for this one problem I am about to describe.
Here is the problem. I am creating a templated php website. With templated I mean something like below:
<?php include("header.php");?>
<div id="content">
<div id="main">
<h2><?php echo($page_title);?></h2>
<?php
echo ($page_content);
?>
</div>
<?php include("sidebar.php");?>
</div>
<?php include("footer.php");?>
As you can see here page template ECHOES the content of the $page_content variable between header and footer sections to build the page.
To keep the code clean and separated (in my own way) I have been placing the html content in .txt files (let's say page1_content.txt) and assigning the txt content to this variable ($page_content) as below:
$page_content = file_get_contents("page1_content.txt");
My problem starts when I place some php code in page1_content.txt, lets' call this file page2_content.php (yes, I change the file from .txt to .php). Then I assign the content of this file to $page_content variable as below as usual:
$page_content = file_get_contents("page2_content.php");
Now, when the page template ECHOES page2_content.php contents the php code in it is also echoed as string and not executed, but I am trying to query a database and do some stuff in this file with some php code. I mean, I want the php code inside page2_content.php to be executed and the cumulative html code to be echoed by the "echo" line inside the template file.
How can I achieve this?
Please ask me any questions if you need more info/clarification.
Thanks
EDİT:
As many people here suggested the solution was including the file. Actually, I tried including the file before but it didn't look like it was working, it broke my template, so I though I was on the wrong track and quit the "include" way of doing this. Since everybody here is advising to use include I tried that again. I replaced the php code in "page2_content.php" with a basic 1-line code just to see if it gets executed before adding generated html code without breaking the template and it worked. Apparently my php code had a problem at first place and hence broke my template execution.
Now I have changed the template structure slightly and pages using the template, and it seems to work nicely. Thanks a lot everybody. I have up-voted every answer suggesting that I use include :)
As #Ali suggested, you could include the files. The other option which I highly suggest you do not use is the eval() function.
I think what you want to do is to include your content PHP file, not echo it (as you are doing with header.php and footer.php).
echo($page_content);
Would become as below:
include("page2_content.php");
You've already done this in your footer and sidebar, just use include()
The content generate by list.php should be only opened into an iframe tag, on the index.php. But when it's called directly, it should not be possible to open it.
How can I obtain this?
In fact I already adopete this method:
<iframe title="frame" class="iframe" src="http://www.example.com/list.php?type=a&013acd2b6c1368f">[Your browser doesn%27;t support iframes]</iframe>
which works fine, thus if the file is called without the arguments ,it redirects to the index.
BUT if you call it directly in this way http://www.example.com/list.php?type=a&013acd2b6c1368f the content appears at full page. While I want that, being outside the tag , it redirects to Index.php
Is there any way please?
I'm sorry to any one.
After have written this message, I finally found the answer here and with small adaption it worked out perfectly.
I didn't find this post before.
Answer to my question
I'm learning php, been trying to make a cms, but when I use an include for the header this results in the page appearing as if it were written in pre tags. There's no errors when I debug or anything. And I'm completely stumped. When I put the header back in without the include it renders just fine.
<?php include("..\includes\layouts\header.php"); ?>
That's the include I'm using.
I've tried using the full path name, tried it in different browsers and using :
include($_SERVER["DOCUMENT_ROOT"]
Check that you are closing your php tags, ending your strings with semi colons etc.. My guess is that your html is being sucked into the php code which freaks out and just dumps it.
Maybe try one of the validators such as http://phpcodechecker.com (I have not used this one so I cannot comment on it's effectiveness)
Edit: I am rereading your post and I think I understand what you are trying to say - your header contains the path to your css and when you put it in a separate php file the css doesn't work? So the first thing to do is determine if the issue with the php path or the css path inside the header.php file. Look at your source code to see if the header code is being included - if it is then play around with the css path - though including the header in a php file will not cause that css path to change.
I am guessing that your header is not included at all from your mention of paths. include() works from the loading file's location. The path it wants is a server path and not a url. The one that you have above: ../includes... means that you have an include folder at the same level as the loading file such as (assume index.php is the main file):
/includes/layouts/header.php
/somedirectory/index.php
The ../ means - drop down one directory then go up from there.
If your path is more like:
/includes/layouts/header.php
/index.php
Then the include would be:
include('./includes/layouts/header.php');
Let me know if that works - if it doesn't try to explain your directory structure.
I am brand new to PHP. I want to use it to include a universal header and footer in an html/jquery site. Currently I am using includes to do this:
<?php include('../includes/footer.php'); ?>
This works fine. Where I encounter a problem is with any images in the header or footer.
An explanation of my file structure:
Root folder: contains index.php and the folders "includes", "img", "php" etc.
php folder: contains gallery.php
includes folder: contains header.php, footer.php
When viewing the index.php all images in the header and footer show properly, but, because they are linked relatively (ex "img/facebook.png"), the do not show in gallery.php. To work they would need a ../ included. But then this would defeat the purpose of a universal header.
Thus I am trying to figure out how to link the images in the includes files in way that is doesn't matter where the php file is located. I have read this thread (which sounds like my problem) but I do not understand any of the answers. I have also read things that suggest $_SERVER['DOCUMENT_ROOT'] .'/folder/';, in conjunction with an echo to display the image. I tried this in my footer.php with this code:
<?php
$path = $_SERVER['DOCUMENT_ROOT'] . '/img/';
$image = ($path . "facebook.png");
echo "<img src=\"$image\" />"; ?>
When I view the page though, I end up with a little torn paper icon instead of my image. I assume this means that the path is incorrect, but I do not know why. facebook.png resides in the img folder. This problem occurs on both index.php and gallery.php.
After this rather long winded explanation (sorry), my mains questions are:
1) How do I get images to show up properly in my includes across multiple directories?
2) If I am going about this in the right way with the echo, what are the possible reasons why it is not working?
Once again, I know nothing about php, so if you could try to make your answers as basic as possible, it would be much appreciated.
Thank you!
Instead of img/facebook.png, add a / before the img/ like this: /img/facebook.png
This says "go to the root, and look for the img folder there. All your images should work fine then. The path of the images are absolute or relative based on the HTML page you're viewing, not which files you use to create it.
Though there's probably not much of reason for a "php" folder - just keep all your pages in the root directory.