I have a bike I have a car
I know when the form is submitted the value will be vehicle=Bike&vehicle=Car if both are ticked
Is there a way to make the value to be vehicle=Bike,Car
Put them into one variable then separated in a comma
Since you are using POST and multiple check boxes, set the name of each check box like this:
<input type="checkbox" name="vehicle[]" value="Bike">
<input type="checkbox" name="vehicle[]" value="Car">
Then when your form is submitted you will receive an array of all the checked boxes and their values in the array:
$_POST['vehicle'][];
Now if both boxes are checked you can retrieve the values in a foreach loop:
foreach($_POST['vehicle'] as $type){
echo "Type = ".$type;
}
With this you will get an output of
Type = Bike
Type = Car
Try this one,
<input type="hidden" name="vechiclesStr" id="vechiclesStr">
//on submitting,
document.getElementById("vechiclesStr").value = document.formname.vechicle.join();
Related
I have a form with a check box.
The check box has three "states":
Checked as default.
Unchecked by user.
Checked again by user.
How would I do something like that? If I use !isset(), I can uncheck the checkbox but it doesn't distinguish if it was unchecked by the user or if it's suppose to be checked as default.
I want to use this to refill the last values of the form inputs whenever there are form errors on submit.
It's easy to do when the default state of the check box is unchecked. I can then just do:
if (isset($_POST['checkbox'])) echo ' checked'; //check box has been checked
The cleanest way of maintaining the form's state after submission is to use an array to store the input values. First you set the default values, then if the form has been submitted, overwrite the defaults with whatever was submitted. In the HTML form, always output the value from the form array.
// create the array (for both viewing the form and maintaining the submitted values)
$form = array(
'myCheckbox' => true // default to checked
'firstName' => '',
)
// was the form submitted?
if($_SERVER['REQUEST_METHOD'] == 'POST'){
// overwrite the form array
$form['myCheckbox'] = isset($_POST['myCheckbox']);
$form['firstName'] = $_POST['firstName'];
// at this point do any validation, if it fails, let the form show
}
Now for the form:
<form method="post">
<input type="checkbox" name="myCheckbox" value="1" <?php echo $form['myCheckbox'] ? 'checked' : '' ?> />
<input type="text" name="firstName" value="<?php echo htmlspecialchars($form['firstName']); ?>" />
</form>
In the above, I added a text input firstName to illustrate that all of the form inputs should be managed by the array.
you can use javascript with an input hidden to tell how many times the checkbox was clicked
<form action="">
<input id="bike" type="checkbox" name="vehicle" value="Bike" checked onchange="document.getElementById('bike-state').value=parseInt(document.getElementById('bike-state').value)+1">I have a bike
<input type="hidden" id="bike-state" name="count" value="0">
</form>
now in the server side if $_POST['bike-state'] is an odd then it was unchecked, if it is even and greater than 0 it was unchecked and then rechecked , otherwise if still 0 it was checked by default
How can I use the conditional OR in a form with isset?
I have this but it does not work.
FORM HTML:
...
<input type="checkbox" name="carga1">
<input type="checkbox" name="carga2">
...
and the PHP
$cargas=array($_POST['carga1'],$_POST['carga2'],$_POST['carga3'],
$_POST['carga4'],$_POST['carga5'],$_POST['carga6'],
$_POST['carga7'],$_POST['carga8'],$_POST['carga9'],
$_POST['carga10'],$_POST['carga11'],$_POST['carga12'],
$_POST['carga13'],$_POST['carga14'],$_POST['carga15'],
$_POST['carga16'],$_POST['carga17'],$_POST['carga18']);
if(isset($cargas[0]) ││ isset ($cargas[1])){
$cargas[0]=5.62;
$cargas[1]=4.5;
echo "$cargas[0]<br>";
echo "$cargas[1]<br>";
}
i expect that this works but is not.
Only checked checkbox is posted to the server.You have to change your condition using pregmatch and work accordingly.
$postData = $_POST;
foreach ($postData as $key => $value) {
$match = preg_match('|cargas(\d+)|', $key, $matches);
if ($match) {
$index = $matches[1];
if($index == 0 || $index == 1){
// do your stuff which you would have done in case of $cargas[0] ,$cargas[1]
}
}
}
I think array is not Suitable way to do this try following
try this
<input type="checkbox" name="carga1">
<input type="checkbox" name="carga2">
.....................................
<input type="submit" name="submit">
<?php
if(isset($_POST['submit'])){
//
$category1=$_POST['carga1'];
$category2=$_POST['carga2'];
$category3=$_POST['carga3'];
if(isset($category1) ││ isset ($category2)){
$category1=5.62;
$category2=4.5;
echo "$category1<br>";
echo "$category2<br>";
}
}
?>
only the checked checkboxes get posted. so it needs slightly different appraoch.
You can acheive it like this-
put a hidden input with the same name as the checkbox that might not be checked. I think it works so that if the checkbox isn't checked, the hidden input is still successful and sent to the server but if the checkbox is checked it will override the hidden input before it. This way you don't have to keep track of which values in the posted data were expected to come from checkboxes.
<form>
<input type='hidden' id='testName' value='0' name='carga1'>
<input type='checkbox' id='testNameHidden' value='1' name='carga1'>
</form>
Before submitting the form , disabled the hidden field based on the checked condition.
<script>
if(document.getElementById("testName").checked){
document.getElementById('testNameHidden').disabled = true;
}
</script>
I personally think its the easiest approach for this.
ok, check boxes in html works as follows,
<input type="checkbox" name="carga1" value="1">
<input type="checkbox" name="carga2" value="123">
in php,
if the check box is in checked state during the submission, you will get
isset($_POST['carga1']) as true, else the form element would not be available in post data, hence false.
and in cheked state you will get value for
$_POST['carga1'] as 1 and
$_POST['carga2'] as 123
and if you want to group the check boxes in form you can use a single name for multiple check boxes and different values,
<input type="checkbox" name="carga[]" value="1">
<input type="checkbox" name="carga[]" value="2">
<input type="checkbox" name="carga[]" value="3">
<input type="checkbox" name="carga[]" value="4">
and in php you will get an array of selected values of the check boxes
$arr=$_POST['carga'];
and you can use foreach to iterate through the values,,,
I have code similar to the following:
<input type="checkbox" name="visitProperty" value="1" id="visit-0">
<input type="checkbox" name="visitProperty" value="1" id="visit-1">
<input type="checkbox" name="visitProperty" value="1" id="visit-2">
...
Once the form is submitted I want to get checked checkboxes, so far I've been using
if (isset($_POST['visitProperty']) {..}
But to my understanding it only gets one checkbox? Where as I need to check all of them and see if they were checked, so inside the if statement I can create a loop that gets id's of all submitted checkboxes and then gets the number from id, to update a certain array.
<input type="checkbox" name="visitProperty[]" value="1" id="visit-0">
<input type="checkbox" name="visitProperty[]" value="2" id="visit-1">
<input type="checkbox" name="visitProperty[]" value="3" id="visit-2">
<?php
foreach($_POST['visitProperty'] as $check) {
echo $check . "<br>"; // for example
}
?>
NOTE: $_POST['visitProperty'] will hold checked checkbox values. You will access all the checkboxs as an array as following $_POST['visitProperty'][]
When you put in the name, you are declaring a variable. You need to declare it as an array, or each checkbox will bump out the last one. Add some empty square brackets to the name.
You would need or defined ID or a unique value, otherwise you will not be able to identify them on the server-side (the ID does not get sent in $_POST).
So in case of a unique, identifyable ID, you could do something like:
<input type="checkbox" name="visitProperty[<?php // echo some unique id from a database for example ?>]" value="1" id="visit-0">
The reason you would need the ID to be identifyable, is that unchecked checkboxes do not get sent to the server, so you might end up with an array of 2 if visitProperty is an array, but you would not know which 2.
Below is an explanation of exactly what I want
On the submission form I have multiple checkboxs. when users click on checkbox a textbox appears next to it, where user input text. I want to insert the value of texbox in array and insert it in database with PHP-MYSQL.
for example checkbox1 is index 0=>valueoftextbox, checkbox2 is index 1=>value of texbox2
How can I achieve this?
Serialize received $_POST.
<input type="checkbox" name="smth[]" value="One" />
<input type="checkbox" name="smth[]" value="Two" />
<input type="checkbox" name="smth[]" value="Three" />
<?php
if (isset($_POST)) {
$smth = serialize($_POST['smth']);
$query = mysql_query("INSERT INTO table VALUES ('$smth')") or die(mysql_error());
}
A few pointer to get you going:
1) From PHP use:
echo "<pre>";
print_r($_POST);
echo "</pre>";
That way you can see WHAT is posted from your client-form.
2) Note that an unchecked checkbox ISN'T posted at all.
So if you have following checkbox in your form named "wantsnewsletter".
Then check that from PHP like this:
if (isset($_POST["wantsnewsletter"])){
// It was checked.
} else {
// It wasn't checked
}
Futhermore you just have to think up some sensible naming and do the inserts into you DB.
i have an html form full of text fields, checkbox's , and radio fields.
i wanted to get all the names of the fields so that i can get started in validating the information in them.
the method i am using to get them is
if(isset($_POST['submit'])) {
foreach($_POST as $name => $value) {
print $name."<br/>";
}
}
but i noticed that it only displays textbox and textarea field names and it doesnt include checkbox and radio field names through this submission. do i need to include anything for it to grab the field names of those?
Checkboxes and radio buttons work a little differently than your standard inputs. If a checkbox is present on a form that doesn't necessarily mean that it will be available in the resulting POST information. Rather, those values will only be avialable if they are actually marked (checkboxes checked and radio buttons selected). The proper way to test for their value in PHP is not to check the field value but rather to check isset() first.
For a checkbox:
$data['my_checkbox'] = isset($_POST['my_checkbox']) ? 'on' : 'off';
and for a radio button:
$data['my_radio'] = isset($_POST['my_radio']) ? $_POST['my_radio'] : false;
To be a little more descriptive let's say you have the following form:
<form action="test.php" method="post">
<input type="text" name="email" value="" />
<input type="checkbox" name="active" value="Yes" />
<input type="submit" value="Submit" />
</form>
If I were to submit that form with an email value of 'test#email.com' but not check the checkbox I would have the following in $_POST:
Array (
'email' => 'test#email.com'
)
However, if I were to submit the same form with the same email address and check the checkbox I would have the following:
Array (
'email' => 'test#email.com',
'active' => 'Yes'
)
Hope that helps.
0./ Try using the following code to see the raw posted data:
echo '<pre>';
print_r($_POST);
echo '</pre>';
1./ Make sure you use a name attribute value for your checkbox and radio inputs.
Typically for checkboxes, it will be an array.
<input type="checkbox" id"=fruit-apple" name="fruits[]" value="apple" />
<input type="checkbox" id="fruit-pear" name="fruits[]" value="pears" />
2./ Make sure they sit inside the form tag.
3./ If you submit using a javascript call, try disabling javascript and see if the error stays. If it does not, you know your javascript is the culprit.